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Electron Transitions in Hydrogen

  • Electrons in hydrogen atoms can gain energy and transition between energy levels.
      - Example: An electron in the ground state (n = 1) can be promoted to a higher energy state (n = 3).
      - When the electron falls back from n = 3 to n = 2, it emits light at a specific wavelength.

  • Emission Spectrum of Elements
      - The light emitted during these transitions results in lines in the emission spectrum of hydrogen.
      - The emitted light encompasses various regions of the electromagnetic spectrum, including ultraviolet and infrared.

Focus on the Hydrogen Atom

  • Hydrogen is particularly studied due to its simpler mathematical treatment compared to multi-electron atoms.
      - The wavelengths of the lines in hydrogen's emission spectrum are predictable by calculating energy differences between states.

  • For an electron in energy state n, the number of possible transitions (lines) it can produce is n - 1:
      - E.g., if n = 3, possible transitions = 3 - 1 = 2 lines.

  • The Bohr model and quantum mechanical models can accurately predict the emission spectrum for hydrogen, a single-electron system.

Electromagnetic Spectrum Regions

  • Emission lines viewed through a spectroscope show only three visible lines due to hydrogen's transitions:
      - Ultraviolet Part: Emission when an electron transitions from n = 1 to a higher state and back to n = 1.
      - Visible Part: When the electron transitions from n = 2 to higher energy states and back to n = 2.
      - Infrared Part: Emission occurring when transitions from n = 3 to higher energy and back to n = 3.

Example Calculation of Wavelength

  • Problem Statement: Determine the wavelength of light emitted when an electron transitions from n = 7 to n = 2.
      - Formulas Used:
        - Energy of emitted photon:
          E_{ ext{photon}} = 2.18 imes 10^{-18} ext{ joules} imes igg(\frac{1}{n_{final}^2} - \frac{1}{n_{initial}^2}\bigg)
      - Wavelength relation:
    E=hcλE = \frac{hc}{\lambda}
          - Rearranged to:
    λ=hcEextphoton\lambda = \frac{hc}{E_{ ext{photon}}}

  • Calculations:
      - Initial and final states identified:
        - n_final = 2
        - n_initial = 7
      - Squared values:
        - nfinal2=22=4n_{final}^2 = 2^2 = 4
        - ninitial2=72=49n_{initial}^2 = 7^2 = 49
      - Energy equation becomes:
    Eextphoton=2.18imes1018imes(14149)E_{ ext{photon}} = 2.18 imes 10^{-18} imes \bigg(\frac{1}{4} - \frac{1}{49}\bigg)
        - Calculation:
          - Compute the energy difference:
          - Result: Eextphoton=5.01imes1019extjoulesE_{ ext{photon}} = 5.01 imes 10^{-19} ext{ joules}

  • Finding the wavelength:
      - Constants:
        - Planck’s constant: h=6.626imes1034extJsh = 6.626 imes 10^{-34} ext{ J s}
        - Speed of light: c=2.998imes1017extnm/sc = 2.998 imes 10^{17} ext{ nm/s}
      - Plugging values into wavelength formula:
    λ=(6.626imes1034extJs)(2.998imes1017extnm/s)5.01imes1019extJ\lambda = \frac{(6.626 imes 10^{-34} ext{ J s})(2.998 imes 10^{17} ext{ nm/s})}{5.01 imes 10^{-19} ext{ J}}
      - Result for wavelength:
        - λ=397extnm\lambda = 397 ext{ nm}
          - This corresponds to light emitted during the transition from n = 7 to n = 2.

Orbital Shapes and Quantum Numbers

  • s Orbitals (l = 0):
      - Spherical shape.
      - Each principal energy level (n) has one s orbital, which is the lowest energy level in its state.

  • p Orbitals (l = 1):
      - Exist in each principal energy level above n = 1, with three p orbitals.
      - Shape resembles an hourglass, oriented along x, y, and z axes.

  • d Orbitals (l = 2):
      - Present in principal energy levels above n = 2, comprising five d orbitals.
      - Fourth-lowest energy orbitals, complex shapes including toroidal regions.

  • f Orbitals (l = 3):
      - Exist in principal energy levels above n = 3 with seven f orbitals.
      - Structures are considerably complex, some having eight lobes.

Why Atoms Are Spherical

  • Atoms are typically depicted as spherical due to the distribution of orbitals which, when combined, create a roughly spherical shape, akin to multiple balloons tied together.

  • Summary of Orbital Types:
      - A one s orbital is spherical.
      - p orbitals have hourglass shapes.
      - d orbitals involve more complex geometries with lobes and rings.
      - f orbitals present even more complicated structures with multiple lobes.

Transition to Electron Configuration

  • Now moving on to Chapter Nine: Electron Configuration.
      - Refer to page seven of the fourth class handout for upcoming discussion details.