Physical Quantities and Measurement Class 7 ICSE Physics Notes

Measurement of Volume

  • Definition of Volume: All objects, whether solids, liquids, or gases, occupy space. The space occupied by an object is formally defined as its Volume.
  • Comparative Example: A school hall is considered bigger than a classroom because the volume of air contained within the empty hall is greater than the volume of air in the empty classroom.
  • S.I. Unit of Volume: The standard international unit for volume is the Cubic metre, denoted as m3m^3.
  • Definition of 1 Cubic Metre: It is defined as the volume of a cube where each side measures exactly 1m1\,m in length.
  • Volume Unit Conversions (Cubic Metre to Cubic Centimetre):
    • 1m3=1m×1m×1m1\,m^3 = 1\,m \times 1\,m \times 1\,m
    • 1m3=100cm×100cm×100cm1\,m^3 = 100\,cm \times 100\,cm \times 100\,cm
    • 1m3=1,000,000cm3=106cm31\,m^3 = 1,000,000\,cm^3 = 10^6\,cm^3
  • Liquid Volume Units: The volume of a liquid is typically expressed in litres (LL).
  • Standard Conversions for Liquids:
    • 1 litre=1000cm31\text{ litre} = 1000\,cm^3
    • 1cm3=103 litre=1mL1\,cm^3 = 10^{-3}\text{ litre} = 1\,mL
  • Capacity: This term is specifically used to express the volume of a vessel or a container.
  • Cubic Decimetre (dm3dm^3): This is another unit used for volume, sometimes referred to as c.c.c.c..
    • 1dm3=1dm×1dm×1dm1\,dm^3 = 1\,dm \times 1\,dm \times 1\,dm
    • 1dm3=10cm×10cm×10cm=1,000cm31\,dm^3 = 10\,cm \times 10\,cm \times 10\,cm = 1,000\,cm^3
    • 1dm3=1 litre1\,dm^3 = 1\text{ litre}

Vessels for Measuring Liquid Volume

  • Types of Vessels: Two primary tools are used:
    1. Measuring cylinder
    2. Measuring beaker
Measuring Cylinder
  • Physical Description: It is a cylinder typically made of glass or plastic with a cross-sectional area of approximately 10cm210\,cm^2.
  • Graduation: The length is approximately 10cm10\,cm, graduated in cm3cm^3 (or mLmL). The zero mark is located at the bottom, and the highest mark (100100) is at the top.
  • Capacity: Standard capacity is 100cm3100\,cm^3 (or 100mL100\,mL).
  • Applications:
    • Commonly used in laboratories to measure liquid volumes.
    • Used to find the volume of irregular objects through the displacement of water or liquid.
  • Other Sizes: Larger measuring cylinders are available in capacities such as 200mL200\,mL and 500mL500\,mL.
Measuring Beaker
  • Purpose: Used to measure a specific, fixed volume of a liquid, such as milk, oil, or lubricating oil.
  • Available Capacities: Beakers come in various fixed sizes: 50mL50\,mL, 100mL100\,mL, 200mL200\,mL, 500mL500\,mL, and 1000mL1000\,mL.

Procedures for Measuring Liquid Volume

Using a Measuring Cylinder
  1. Take a measuring cylinder, wash it thoroughly with water, and dry it.
  2. Place the cylinder on a flat, level surface.
  3. Pour the liquid into the cylinder gently to ensure no splashing occurs.
  4. Wait for the liquid to become stationary.
  5. Observe the meniscus: The upper surface of the water is curved when stationary. Measurements should be taken based on the appropriate level of the meniscus.
Using a Measuring Beaker
  • This method is used when a specific fixed volume needs to be extracted from a large volume.
  • Example: Measuring 500mL500\,mL of milk from a bucket.
  • Process: Select a measuring beaker with the exact capacity required (500mL500\,mL) and fill it from the larger container.

Measurement of Regular and Irregular Objects

Volume of Regular Objects
  • The volume of regular objects is determined by measuring their dimensions (length, breadth, height, or radius) and applying formulas:
    • Volume of a Cube: (one side)3(\text{one side})^3
    • Volume of a Cuboid: length×breadth×height\text{length} \times \text{breadth} \times \text{height}
    • Volume of a Sphere: V=43×π×(radius)3V = \frac{4}{3} \times \pi \times (\text{radius})^3 (Transcript indicates proportionality to r3r^3).
    • Volume of a Cylinder: π×(radius)2×height\pi \times (\text{radius})^2 \times \text{height}
    • Volume of a Cone: V=13×π×(radius)2×heightV = \frac{1}{3} \times \pi \times (\text{radius})^2 \times \text{height} (Transcript indicates proportionality to r2×hr^2 \times h).
Volume of Irregular Objects
  • Method: The Displacement Method using a measuring cylinder.
  • Principle: The volume of an irregular solid is equal to the volume of the liquid it displaces when completely immersed.

Area

  • Definition: The surface occupied by an object is called its area.
  • S.I. Unit: Square metre, denoted as m2m^2.
    • 1m2=1m×1m1\,m^2 = 1\,m \times 1\,m
  • Large Units:
    • Are: The area of a square with each side measuring 10m10\,m.
    • 1 are=10m×10m=100m21\text{ are} = 10\,m \times 10\,m = 100\,m^2
    • Hectare: The area of a square with each side measuring 100m100\,m.
    • 1 hectare=100m×100m=10,000m21\text{ hectare} = 100\,m \times 100\,m = 10,000\,m^2
    • Square Kilometre: The area of a square with each side measuring 1km1\,km.
    • 1km2=1km×1km=1,000,000m2=106m21\,km^2 = 1\,km \times 1\,km = 1,000,000\,m^2 = 10^6\,m^2
  • Smaller Units (for objects like pencils or rubbers):
    • Square Centimetre (cm2cm^2): 1cm2=1cm×1cm=104m21\,cm^2 = 1\,cm \times 1\,cm = 10^{-4}\,m^2
    • Square Millimetre (mm2mm^2): 1mm2=1mm×1mm=106m21\,mm^2 = 1\,mm \times 1\,mm = 10^{-6}\,m^2
Area of Regular Objects
  • Calculated by measuring two dimensions:
    • Area of a Square: (one side)2(\text{one side})^2
    • Area of a Rectangle: length×breadth\text{length} \times \text{breadth}
    • Area of a Circle: π×r2\pi \times r^2
    • Surface Area of a Cylinder: 2π×radius×length2\pi \times \text{radius} \times \text{length}
    • Surface Area of a Sphere: 4π×(radius)24\pi \times (\text{radius})^2
Area of Irregular Objects
  • Method: Using graph paper where each square has a side of 1cm1\,cm, meaning each square represents an area of 1cm21\,cm^2.
  • Formula: Approximate Area=(No. of complete squares+No. of half or more than half incomplete squares)×Area of one square\text{Approximate Area} = (\text{No. of complete squares} + \text{No. of half or more than half incomplete squares}) \times \text{Area of one square}
  • Calculation Example: For an object covering 44 complete squares and 44 half or more squares:
    • A=(4+4)×1cm2=8cm2A = (4 + 4) \times 1\,cm^2 = 8\,cm^2

Density

Fundamental Concepts
  • Every body possesses a certain mass and a definite volume.
  • Equal Masses of Different Substances: Occupy different volumes.
    • Example: 1kg1\,kg of sugar occupies more volume than 1kg1\,kg of iron; therefore, iron is denser than sugar.
  • Equal Volumes of Different Substances: Have different masses.
    • Example: An iron cube and an aluminium cube of the same size (equal volume) will differ in mass. The mass of the iron is greater.
  • Comparative Density Examples:
    • Aluminium is denser than glass (mass of aluminium cube > identical glass cube).
    • Glass is denser than wood (mass of glass cube > identical wooden cube).
    • Milk is denser than water (a certain volume of milk has more mass than an equal volume of water).
Definition and Formula
  • Density (dd): Defined as the mass per unit volume of a substance.
  • Formula: d=MVd = \frac{M}{V}
  • Calculated Example (Water):
    • Given: M=1gM = 1\,g, V=1cm3V = 1\,cm^3
    • Density of water=1g1cm3=1gcm3\text{Density of water} = \frac{1\,g}{1\,cm^3} = 1\,g\,cm^{-3}
  • Properties: The density of a substance does not change with changes in its shape or size.
Units of Density
  • S.I. Unit: Mass is in Kilograms (kgkg) and Volume is in Cubic metres (m3m^3), so Density is measured in kgm3kg\,m^{-3}.
  • C.G.S Unit: Mass is in Grams (gg) and Volume is in Cubic centimetres (cm3cm^3), so Density is measured in gcm3g\,cm^{-3}.
  • Relationship between kgm3kg\,m^{-3} and gcm3g\,cm^{-3}:
    • 1kg=1000g1\,kg = 1000\,g or 1g=11000kg1\,g = \frac{1}{1000}\,kg
    • 1m3=(100cm)3=1,000,000cm31\,m^3 = (100\,cm)^3 = 1,000,000\,cm^3 or 1cm3=11,000,000m31\,cm^3 = \frac{1}{1,000,000}\,m^3
    • 1gcm3=103kg106m3=1000kgm31\,g\,cm^{-3} = \frac{10^{-3}\,kg}{10^{-6}\,m^3} = 1000\,kg\,m^{-3}
Temperature and Density
  • Generally, the density of solids, liquids, and gases decreases as temperature increases because substances expand when heated.
  • Anomalous Expansion of Water:
    • Water contracts when heated from 0C0^\circ C to 4C4^\circ C.
    • Water expands when heated above 4C4^\circ C.
    • The density of water is at its maximum at 4C4^\circ C.
    • Density decreases whether the water is cooled from 4C4^\circ C to 0C0^\circ C or heated above 4C4^\circ C.
Determination of Density of Regular Solids
  1. Measure the Mass (MM) of the solid using a beam balance.
  2. Measure the dimensions (length, breadth, height) using a metre ruler.
  3. Calculate Volume: V=length×breadth×heightV = \text{length} \times \text{breadth} \times \text{height}.
  4. Apply the formula: d=MVd = \frac{M}{V}.
Determination of Density of Irregular Solids (Stone/Coin)
  1. Measure the mass (MM) of the solid using a beam balance (in grams).
  2. Use the displacement method for volume:
    • Partially fill a measuring cylinder with water.
    • Record initial volume level (V1V_1).
    • Tie the solid with a thread and immerse it gently in the cylinder.
    • Record the new volume level (V2V_2) in mLmL.
  3. Calculate the volume of the solid: V=V2V1cm3V = V_2 - V_1\,cm^3 (since 1mL=1cm31\,mL = 1\,cm^3).
  4. Calculate density: d=MV2V1gcm3d = \frac{M}{V_2 - V_1}\,g\,cm^{-3}.
Determination of Density of a Liquid (e.g., Milk)
  1. Measure the mass of an empty beaker using a beam balance (M1M_1).
  2. Use a measuring cylinder to measure a specific volume (VV) of the liquid (e.g., 50mL50\,mL of milk, which is 50cm350\,cm^3).
  3. Pour the liquid into the empty beaker and measure the mass again (M2M_2).
  4. Calculate the mass of the liquid: M=M2M1M = M_2 - M_1.
  5. Calculate density: d=MVd = \frac{M}{V}.

Speed

  • Definition of Distance: When a body is in motion, the length of the path travelled in a certain time is the distance moved.
  • Unit of Distance: Metre (mm).
  • Understanding Speed: Speed is measured to determine how fast or slow an object is moving by comparing distance travelled in a specific time interval.
    • Example: A car travels more distance than a bullock cart in the same time interval, meaning the car moves faster.
  • Definition of Speed: Speed is the distance travelled divided by time taken.
  • Variable Representation: Denoted by vv.
  • Formula: v=dtv = \frac{d}{t}
  • Units:
    • S.I. Unit: ms1m\,s^{-1}
    • Other Units: kmh1km\,h^{-1}
  • Conversion Relationships:
    • 1kmh1=1000m3600s=518ms11\,km\,h^{-1} = \frac{1000\,m}{3600\,s} = \frac{5}{18}\,m\,s^{-1}
    • 1ms1=3.6kmh11\,m\,s^{-1} = 3.6\,km\,h^{-1}