Area & Perimeter

Unit 8: 2D Geometry

Lesson 2: Area + Perimeter

Learning Goals

  • To calculate area and perimeter of rectangles, squares, and triangles.

  • To find missing lengths when given area and perimeter of rectangles, squares, and triangles.

Minds On: Review

  • Assess prior knowledge regarding perimeter and area of basic shapes.

  • Example:

    • Rectangle:


    • Dimensions: 3 cm (width) & 5 cm (length)
      Perimeter Calculation:
      P=2l+2w=2(5)+2(3)=10+6=16extcmP = 2l + 2w = 2(5) + 2(3) = 10 + 6 = 16 ext{ cm}
      Area Calculation:
      A=lw=5(3)=15extcm2A = lw = 5(3) = 15 ext{ cm}^2

    • Triangle:


    • Side lengths: 9 m, 14 m, and 11 m
      Perimeter Calculation:
      P=a+b+c=9+14+11=34extmP = a + b + c = 9 + 14 + 11 = 34 ext{ m}
      Area Calculation:
      A=racbh2=rac7(14)2=rac982=49extm2A = rac{bh}{2} = rac{7(14)}{2} = rac{98}{2} = 49 ext{ m}^2

Definitions

Perimeter

  • Definition: The calculation of the distance around a closed 2D shape.

  • Formula: P=extside+extside+extside+extsideP = ext{side} + ext{side} + ext{side} + ext{side}

  • Alternately, for rectangles:

    • P=2w+2lP = 2w + 2l

    • P=2(l+w)P = 2(l + w)

  • Practical Implication: To find how far one would travel around a shape.

Area

  • Definition: The calculation of the amount of space inside a closed 2D shape, measured in square units.

  • Major Calculation:

  • For Squares and Rectangles:

    • Count the squares or multiply the sides.

    • Formula: A=extLengthimesextWidthA = ext{Length} imes ext{Width}

Squares: Perimeter

Perimeter Formula

  • Definition: The perimeter of squares can be found by adding up all sides.

  • General Formula: P=s+s+s+s=4sP = s + s + s + s = 4s

Squares: Area

Area Formula

  • Area of squares is calculated as the total number of squares inside.

  • Formula:

    • A=simessA = s imes s

    • A=s2A = s^2

Squares: Practice Examples

  • Find the perimeter and area of squares:

    • For example:

    • Side length: 50 cm

      • P=4(50)=200extcmP = 4(50) = 200 ext{ cm}

      • A=502=2500extcm2A = 50^2 = 2500 ext{ cm}^2

    • For side length: 22 m

      • P=4(22)=88extmP = 4(22) = 88 ext{ m}

      • A=222=484extm2A = 22^2 = 484 ext{ m}^2

Rectangles: Perimeter

Perimeter Calculation

  • Definition: The perimeter of a rectangle is calculated by adding up all sides.

  • General Formula: P=L+W+L+W=2L+2WP = L + W + L + W = 2L + 2W

  • Alternatively, P=2(L+W)P = 2(L + W)

Rectangles: Area

Area Formula

  • Area of rectangles is calculated as the number of squares inside.

  • Formula:

    • A=extLengthimesextWidthA = ext{Length} imes ext{Width}

    • A=LWA = LW

Rectangles: Practice Examples

  • Example Problem:

    • Dimensions: 70 cm by 30 cm

    • P=2(70)+2(30)=140+60=200extcmP = 2(70) + 2(30) = 140 + 60 = 200 ext{ cm}

    • A=70(30)=2100extcm2A = 70(30) = 2100 ext{ cm}^2

Triangles: Perimeter

Perimeter Calculation

  • Definition: The perimeter of triangles is calculated by adding up all sides.

  • General Formula: P=a+b+cP = a + b + c

  • Types of Triangles:

    • Scalene: All sides different; P=a+b+cP = a + b + c

    • Equilateral: All sides equal; P=3aP = 3a

    • Isosceles: Two sides equal; P=2b+cP = 2b + c

Triangles: Area

Area Formula

  • Area of triangles is calculated similar to rectangles but requires division by 2 (since it is half of a rectangle).

  • Formula:

    • A=racbimesh2A = rac{b imes h}{2}

    • Where bb is the base and hh is the height.

Triangles: Practice Examples

  • Example Problem:

    • For a triangle with side lengths of 25 cm, 32 cm, and 25 cm:

    • P=25+32+25=82extcmP = 25 + 32 + 25 = 82 ext{ cm}

    • For the area with base of 50 cm and height of 20 cm:
      A=rac50imes202=500extcm2A = rac{50 imes 20}{2} = 500 ext{ cm}^2

Challenge Problems

  • Squares:

    • Given perimeter P = 220 cm, find side length.

    • P=4sP = 4s, therefore s=220/4=55extcms = 220/4 = 55 ext{ cm}

    • Given area A = 256 m², find side length.

    • A=s2<br>ightarrows=ext256=16extmA = s^2 <br>ightarrow s = ext{√256} = 16 ext{ m}

  • Rectangles:

    • Given perimeter P = 190 cm with one side 45 cm, find width:

    • Solve:
      190=2(45)+2w<br>ightarrow190=90+2w190 = 2(45) + 2w <br>ightarrow 190 = 90 + 2w
      2w=100<br>ightarroww=50extcm2w = 100 <br>ightarrow w = 50 ext{ cm}

    • Area given as 375 m², find length from width of 25 m:

    • Solve:
      375=25L<br>ightarrowL=rac37525=15extm375 = 25L <br>ightarrow L = rac{375}{25} = 15 ext{ m}

  • Triangles:

    • Given perimeter P = 121 m with base 45 m, find missing equal sides:

    • 121=2a+45<br>ightarrow2a=12145<br>ightarrow2a=76<br>ightarrowa=38extm121 = 2a + 45 <br>ightarrow 2a = 121 - 45 <br>ightarrow 2a = 76 <br>ightarrow a = 38 ext{ m}

    • Area given as 1575 cm², find height using base of 75 cm:

    • 1575=rac75h2<br>ightarrow3150=75h<br>ightarrowh=rac315075=42extcm1575 = rac{75h}{2} <br>ightarrow 3150 = 75h <br>ightarrow h = rac{3150}{75} = 42 ext{ cm}

Consolidation Vocabulary

  • Area

  • Perimeter

  • Area & Perimeter Formulas for:

    • Rectangle

    • Square

    • Triangle

Additional Practice

IXL Quiz
  • Complete exercises regarding Area & Perimeter in math notebook following proper mathematical format and organization!