L4.1 Graphing Quadratic Functions and Finding Maximum/Minimum Values Study Guide

L4.1 Graphing Quadratic Functions: Overview and Objectives

  • General Purpose: Learning how to graph quadratic functions and how to find and interpret the maximum and minimum values of these functions.

  • Core Concepts:
        * Graphing quadratic functions.
        * Identifying, calculating, and interpreting the maximum and minimum values of a quadratic function.

Defining the Quadratic Function

  • Standard Form: The standard form of a quadratic function is represented as:
        * f(x)=ax2+bx+cf(x) = ax^2 + bx + c, where a0a \neq 0.

  • Components of the Equation:
        * Quadratic term: ax2ax^2
        * Linear term: bxbx
        * Constant term: cc

  • Critical Characteristic: In a quadratic function, the greatest exponent (the degree) is always 2.

  • The Parabola: The graph of a quadratic function is a curve called a parabola.

Key Features of a Quadratic Graph

  • Parabola Definition: To graph a quadratic function, one must graph ordered pairs that satisfy the function and connect them with a smooth curve.

  • Key Features for Labeling:
        * X-intercepts: The points where the graph intersects the x-axis. These occur when y=0y = 0 or f(x)=0f(x) = 0.
        * Y-intercept: The point where the graph intersects the y-axis. This occurs when x=0x = 0. For the standard form f(x)=ax2+bx+cf(x) = ax^2 + bx + c, the y-intercept is always (0,c)(0, c).
        * Vertex (Turning Point): The highest or lowest point on the graph of the parabola.
        * Axis of Symmetry: A vertical line that passes through the vertex of a parabola and divides the parabola into two congruent halves.

Graphing Method 1: Using a Table of Values

  • Process:
        1. Choose integer values for xx.
        2. Evaluate the function for each chosen value to find the corresponding f(x)f(x) (or yy) values.
        3. Graph the resulting coordinate pairs.
        4. Connect the points with a smooth curve.

  • Example 1: Graph f(x)=x2+3x1f(x) = x^2 + 3x - 1 using a table.
        * Calculator Tool: The CASIO fx-991EX CLASSWIZ can be used to generate the ordered pairs using the Table function.

  • Calculator Instructions (Table Function):
        * Use the MENU SETUP button, navigate to the Table function.
        * Input the function f(x)f(x).
        * Define the start, end, and step values to generate the list of coordinates.

Graphing Method 2: Algebraic Steps (Without a Table)

  • Step 1: Consider the Graph Direction:
        * Identify if the parabola opens upward or downward based on the leading coefficient aa.

  • Step 2: Find the Axis of Symmetry:
        * Use the formula: x=b2ax = -\frac{b}{2a}.

  • Step 3: Find the Vertex:
        * The vertex lies on the axis of symmetry, so its x-coordinate is b2a-\frac{b}{2a}.
        * Find the y-coordinate by substituting the x-coordinate back into the original function.
        * Example: For an axis of symmetry at x=3x = -3, substitute 3-3 into the equation to find the y-value (e.g., y=11y = -11), resulting in a vertex of (3,11)(-3, -11).

  • Step 4: Find the Y-intercept:
        * Substitute x=0x = 0 into the equation.
        * Example: For f(x)=x2+6x2f(x) = x^2 + 6x - 2, if x=0x = 0, then y=2y = -2. The point is (0,2)(0, -2).

  • Step 5: Find the Reflected Point:
        * Use the axis of symmetry to find the reflection of the y-intercept.
        * Example: If the y-intercept is (0,2)(0, -2) and the axis of symmetry is at x=3x = -3, the reflected point is (6,2)(-6, -2).

  • Step 6: Connect the Points:
        * Draw a smooth curve through the vertex, the y-intercept, and the reflected point.

Determining Maximum and Minimum Values

  • Maximum and Minimum Rule:
        * If a > 0: The graph opens upward and has a minimum value.
        * If a < 0: The graph opens downward and has a maximum value.

  • Defining the Value: The actual maximum or minimum value of the function is the y-coordinate of the vertex.

  • Example 4: Consider f(x)=x2+2x+3f(x) = -x^2 + 2x + 3.
        * a=1,b=2,c=3a = -1, b = 2, c = 3.
        * Since a < 0, the graph opens downward; the function has a maximum value.
        * The vertex is found at x=22(1)=1x = -\frac{2}{2(-1)} = 1.
        * Evaluating f(1)=(1)2+2(1)+3=4f(1) = -(1)^2 + 2(1) + 3 = 4.
        * The maximum value is 44.

Domain and Range of Quadratic Functions

  • Domain: The set of all possible input values (xx-values). For any quadratic function, the domain is all real numbers.

  • Range: The set of all possible output values (yy-values).
        * If the graph opens upward (has a minimum): Range is f(x)y-value of the vertexf(x) \geq \text{y-value of the vertex}.
        * If the graph opens downward (has a maximum): Range is f(x)y-value of the vertexf(x) \leq \text{y-value of the vertex}.

  • Example 5: For f(x)=x2+2x+3f(x) = -x^2 + 2x + 3 (where the maximum is 44):
        * Domain: All real numbers.
        * Range: f(x)4f(x) \leq 4.

Worked Example: f(x) = 2x² - 4x + 5

  • Analyze Coefficients: a=2,b=4,c=5a = 2, b = -4, c = 5.

  • A) Direction: Opens upward because a=2a = 2 (positive).

  • B) Axis of Symmetry: x=42(2)=44=1x = -\frac{-4}{2(2)} = \frac{4}{4} = 1. The line is x=1x = 1.

  • C) Vertex: Substitute x=1x = 1 into the function: f(1)=2(1)24(1)+5=24+5=3f(1) = 2(1)^2 - 4(1) + 5 = 2 - 4 + 5 = 3. Vertex is (1,3)(1, 3).

  • D) Y-intercept: Since c=5c = 5, the y-intercept is (0,5)(0, 5).

  • E) Graphing:
        * Plot (1,3)(1, 3).
        * Plot (0,5)(0, 5).
        * Plot the symmetric point. Since (0,5)(0, 5) is 11 unit left of the axis x=1x = 1, the symmetric point is 11 unit right: (2,5)(2, 5).

Worked Example: f(x) = 2 - 4x + x²

  • Step 1: Rearrange to Standard Form: f(x)=1x24x+2f(x) = 1x^2 - 4x + 2.

  • Step 2: Identify Coefficients: a=1,b=4,c=2a = 1, b = -4, c = 2.

  • A) Direction: Opens upward (a=1a = 1).

  • B) Axis of Symmetry: x=42(1)=2x = -\frac{-4}{2(1)} = 2.

  • C) Vertex: y=(2)24(2)+2=48+2=2y = (2)^2 - 4(2) + 2 = 4 - 8 + 2 = -2. Vertex is (2,2)(2, -2).

  • D) Y-intercept: y=2y = 2. The point is (0,2)(0, 2).

Real-Life Application: Projectile Motion

  • Scenario: A rock is thrown upward from a 112foot112\,foot high cliff at a speed of 96feet/second96\,feet/second.

  • Model Equation: H(t)=16t2+96t+112H(t) = -16t^2 + 96t + 112.

  • Question: When does the rock hit the ocean?

  • Solution:
        * When the rock hits the ocean, its height H(t)=0H(t) = 0.
        * Equation: 0=16t2+96t+1120 = -16t^2 + 96t + 112.
        * Solve for zeros using a calculator.
        * Results: t=7t = 7 and t=1t = -1.
        * Conclusion: Ignore the negative value. The rock hits the ocean after 7seconds7\,seconds.

Questions & Discussion

  • Search and Synergize (Introductory Activity):
        * 1) What is the quadratic function?
        * 2) Write the standard Form of a quadratic function?
        * 3) What does the graph of a quadratic function look like?
        * 4) How to graph a quadratic function using a table?

  • Search and Synergize (Advanced Activity):
        * 1) What are the maximum and minimum values of a quadratic function?
        * 2) What are the domain and range of a quadratic function?

  • EST Practice 1: Which graph is the graph of f(x)=2x2+3x+2f(x) = 2x^2 + 3x + 2?

  • EST Practice 2: Consider f(x)=36x+x2f(x) = 3 - 6x + x^2. Find the y-intercept, axis of symmetry, and x-coordinate of the vertex.
        * Result: y-intercept = 33; Axis of symmetry: x=3x = 3; x-coordinate = 33 (Option C).

  • EST Practice 3: Consider f(x)=36x+x2f(x) = 3 - 6x + x^2. Make a table of values that includes the vertex.

  • EST Practice 4: Use information from parts A and B to graph the function f(x)=36x+x2f(x) = 3 - 6x + x^2.

  • EST Practice 5: Consider f(x)=x2+4x1f(x) = x^2 + 4x - 1. Determine if it has a max or min.
        * Result: Minimum at x=2x = -2 (Option B).

  • EST Practice 6: What is the maximum or minimum value of f(x)=x2+4x1f(x) = x^2 + 4x - 1?
        * Calculation: x=4/2=2x = -4/2 = -2. f(2)=(2)2+4(2)1=481=5f(-2) = (-2)^2 + 4(-2) - 1 = 4 - 8 - 1 = -5.
        * Result: 5-5 (Option A).

  • EST Practice 7: What are the domain and range of f(x)=x2+4x1f(x) = x^2 + 4x - 1?
        * Result: D=all real numbers;R=f(x)f(x)5D = {\text{all real numbers}}; R = {f(x) | f(x) \geq -5} (Option A).