Quadratic Functions and Their Properties

Introduction to Quadratic Functions

  • Quadratic functions are expressed in the form: f(x) = ax^2 + bx + c

    • Where

    • $a$ determines the direction of the parabola (upward if $a > 0$, downward if $a < 0$).

    • $b$ and $c$ are coefficients that affect the position and orientation of the graph.

Key Components of Quadratic Functions

The Quadratic Equation

  • The general format is: y = ax^2 + bx + c

    • This function has a parabolic shape.

  • Intercepts:

    • Y-Intercept is found by substituting $x=0$:
      y = c

    • X-Intercepts are found by solving:
      ax^2 + bx + c = 0

    • Can be determined using the quadratic formula: x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

      • Discriminant:

      • $D = b^2 - 4ac$

        • If $D > 0$: Two distinct x-intercepts.

        • If $D = 0$: One repeated x-intercept.

        • If $D < 0$: No x-intercepts.

Vertex of the Parabola

  • The vertex is the highest or lowest point on the graph, depending on the direction of the parabola.

    • X-Coordinate of Vertex:
      x_v = \frac{-b}{2a}

    • Y-Coordinate of Vertex:

    • Found by substituting $xv$ back into the function: yv = f(x_v) = a\left(\frac{-b}{2a}\right)^2 + b\left(\frac{-b}{2a}\right) + c

Graphing Quadratic Functions

General Characteristics
  • The graph is symmetric about a vertical line called the axis of symmetry, located at
    x = \frac{-b}{2a}

  • The direction of the parabola is defined by the sign of $a$:

    • Opens upward if $a > 0$, downward if $a < 0$.

Vertex Example
  • For the function:
    y = 3x^2 + 5x + 2

  • Calculate x-coordinate of vertex:
    x_v = \frac{-5}{2(3)} = \frac{-5}{6}

  • To find $y$:

    • Substitute $x = -\frac{5}{6}$ in the function:
      y_v = 3\left(\frac{-5}{6}\right)^2 + 5\left(\frac{-5}{6}\right) + 2

Finding Intercepts

Calculation of X-Intercepts

  • To find x-intercepts, solve for when $y=0$:

    • Use factorization or quadratic formula.

    • Example for f(x) = -x^2 + x :

      • Factor out $x$:
        x(-x + 1) = 0

      • Solutions: $x = 0$ and $x = 1$.

    • If graphing, plot x-intercepts and y-intercepts accordingly.

Example of Y-Intercept

  • For function f(x) = 3x^2 + 5x + 2 ,

    • The y-intercept will be:

    • Directly from $c$:
      y = 2

    • Thus, point (0, 2) on the graph.

Real-World Applications of Quadratic Functions

  • Quadratic equations model various phenomena, such as projectile motion or revenue maximization problems.

  • Revenue Optimization Example:

    • Assuming revenue $R(x) = -5x^2 + 50x$,

    • Vertex provides maximum revenue point.

Summary

  • Quadratic functions have distinct properties based on coefficients, which allow us to predict the shape and intersections of their graphs.

  • Tools include calculating intercepts, finding the vertex, and evaluating the discriminant to determine possible solutions.

  • Understanding these functions is crucial, especially when applied to calculus in later studies, such as analyzing behavior near critical points and optimization problems.