lesson 12 continued

Probability Basics
  • Definition: Probability measures the likelihood of a specific event occurring, ranging from 0 (impossible) to 1 (certain).
Calculating Probability of Correct Answers
  • Example: If guessing on a test with 4 options per question:
    • Correct answer probability: P(C)=14=0.25P(C) = \frac{1}{4} = 0.25
    • Incorrect answer probability: P(I)=1−P(C)=34=0.75P(I) = 1 - P(C) = \frac{3}{4} = 0.75
Multiple Questions Scenario
  • For answering 5 questions incorrectly:

    • Probability of getting all incorrect answers:
      P(I)=(0.75)5=0.2373P(I) = (0.75)^5 = 0.2373 (approximately)
  • To find the probability of getting at least one correct answer:

    • Use the complement rule:
      P(at least one correct)=1−P(all incorrect)P(at\ least\ one\ correct) = 1 - P(all\ incorrect)
      =1−0.2373=0.7627= 1 - 0.2373 = 0.7627 (approximately)
Straightforward Calculation
  • Alternatively, you can find the probability of getting one, two, or more correct answers directly, but this is often complex because it requires tracking multiple outcomes.
General Probability Rules
  • Multiplication Rule:
    • If events A and B are independent,
      P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B)
Conditional Probability
  • Definition:
    • Conditional probability measures the probability of event B occurring given that event A has occurred.
    • Notation:
      P(B∣A)P(B | A)
    • Formally:
      P(B∣A)=P(A and B)P(A)P(B | A) = \frac{P(A \text{ and } B)}{P(A)}
    • Example:
    • Probability of a person being pregnant given a positive test result.
      • Calculate based on the relevant portion of a given data set (e.g., a table).
Practice Problems on Conditional Probability
  • Working through examples with a provided table covering test results (pregnant/not pregnant, positive/negative).

  • Key idea is to focus only on the given condition when performing calculations (e.g., focus on rows/columns related to positive test results).

General Multiplication Rule
  • For two events A and B:

    • P(A and B)=P(A)×P(B∣A)P(A \text{ and } B) = P(A) \times P(B | A)
  • This allows addressing scenarios where choosing one outcome affects the outcome of another.
Independence of Events
  • To check if two events A and B are independent:
    • If
      P(B∣A)=P(B)P(B | A) = P(B)
      then events are independent.
Practical Examples
  • Discussed examples included scenarios like machine failures or outcomes of marble picking.
  • Example of picking marbles without replacement illustrates how probabilities change as each event alters the sample size.
Alternate Calculating Method for Conditional Probability
  • If having trouble calculating P(B∣A)P(B | A) directly:
    • Use the formula:
      P(B∣A)=P(A and B)P(A)P(B | A) = \frac{P(A \text{ and } B)}{P(A)}
    • This method simplifies some tasks by focusing on known event pairs directly from historical data or a table.
Conclusion and Further Topics
  • Move toward counting methods and their applications in probability questions and scenarios.