CHEM1010 W12.1

Energy in Chemical Reactions

Electrostatic Potential Energy

  • Like Charges (e.g., two positive ions):
    • When far apart, there's minimal interaction.
    • Bringing them together requires work due to repulsive forces.
    • The closer they get, the more work is needed, increasing electrostatic potential energy.
    • Releasing them converts potential energy into kinetic energy (movement).
  • Opposite Charges (e.g., positive and negative ions):
    • Attract each other.
    • They accelerate towards each other, decreasing potential energy.
    • Separating them requires work, increasing potential energy.

Thermodynamics and the First Law

  • Thermodynamics: Deals with work, potential energy, and kinetic energy relationships.
  • First Law of Thermodynamics (Conservation of Energy):
    • Energy is neither created nor destroyed.
    • It's converted from one form to another (e.g., work to potential energy, potential energy to kinetic energy).

System and Surroundings

  • System:
    • The chemical species reacting (reactants and products).
    • Can be a liquid or a gas.
  • Surroundings:
    • The reaction vessel or container.
    • The atmosphere around the reaction.
  • Universe:
    • Combination of the system and the surroundings.
    • Defining the system and surroundings helps track matter and energy.

Types of Systems

  • Open System:
    • Both energy and matter can be transferred between the system and surroundings.
    • Example: Open mug of hot coffee.
      • System: The coffee liquid.
      • Surroundings: Mug, saucer, table, air.
      • Matter transfer: Evaporation of coffee (steam).
      • Energy transfer: Coffee heating the mug and surroundings.
  • Closed System:
    • Energy can be transferred, but matter cannot.
    • Example: Closed cup of coffee with a lid.
      • Matter is contained.
      • Energy transfer: Coffee cooling down and releasing heat to the surroundings, glass gets hot.
  • Isolated System:
    • Neither energy nor matter can be transferred.
    • Example: Coffee in a sealed, insulated mug.
      • Approximation: True isolated systems are hard to achieve.

Internal Energy (E)

  • Represents the total kinetic and potential energies within a system.
  • We primarily focus on the change in internal energy (ΔE\Delta E).
  • ΔE=E<em>finalE</em>initial\Delta E = E<em>{\text{final}} - E</em>{\text{initial}}, where:
    • ΔE\Delta E is the change in internal energy.
    • EfinalE_{\text{final}} is the final internal energy.
    • EinitialE_{\text{initial}} is the initial internal energy.

Changes in Internal Energy

  • If \Delta E < 0 (negative):
    • The system has lost energy to the surroundings.
  • If \Delta E > 0 (positive):
    • The system has gained energy from the surroundings.

Combustion of Hydrogen and Oxygen

  • 2H<em>2+O</em>22H2O2H<em>2 + O</em>2 \rightarrow 2H_2O
  • Initial internal energy is higher than the final internal energy.
  • \Delta E < 0
  • Energy is released to the surroundings as light, heat, and sound.
  • Kinetics describes the rate of reaction, while thermodynamics describes the start and end energies.

Endothermic and Exothermic Reactions (Heat Flow/Enthalpy)

  • Enthalpy (H): Heat flow at constant pressure.
  • Focus on the change in enthalpy (ΔH\Delta H).
  • Endothermic Reactions:
    • \Delta H > 0. The system gains heat from the surroundings.
    • Feels cold because the system is drawing energy from the surroundings.
    • Key Distinction: Heat (energy flow) vs. Temperature (degrees).
  • Exothermic Reactions:
    • \Delta H < 0. The system loses heat to the surroundings.
    • Often characterized by an increase in temperature in the surroundings.
    • Heat flows from the system to the surroundings.

State Functions

  • Internal energy (E) and enthalpy (H) are state functions.
  • We only care about the initial and final states, not the path taken.

Heat Flow and Enthalpy of Reaction

  • Enthalpy of Reaction (ΔHreaction\Delta H_{\text{reaction}}) or Heat of Reaction

  • The amount of heat flow is proportional to the amount of reagents.

    • Example: Combustion of Methane (CH4CH_4)
    • CH<em>4+2O</em>2CO<em>2+2H</em>2OCH<em>4 + 2O</em>2 \rightarrow CO<em>2 + 2H</em>2O
    • One mole of methane releases approximately 890 kJ of heat to the surroundings.
    • Heat is transferred from the system to the surroundings (enthalpy is reduced).
    • Two moles of methane release 1780 kJ.
    • Ten moles of methane release 8900 kJ.
    • ΔHreaction\Delta H_{\text{reaction}} is often expressed in kJ/mol.
  • Reverse Reaction:

    • The reverse reaction has the same magnitude of ΔH\Delta H but with the opposite sign.
    • Example: CO<em>2+2H</em>2OCH<em>4+2O</em>2CO<em>2 + 2H</em>2O \rightarrow CH<em>4 + 2O</em>2 has ΔH=+890\Delta H = +890 kJ/mol.

Phase and Heat Flow

  • The phase (solid, liquid, gas) of reactants and products affects ΔH\Delta H.
  • Phase changes (e.g., evaporation) involve changes in enthalpy.

Calorimetry

  • A process to determine the amount of heat being transferred.
  • Measures changes in temperature to quantify heat flow.

Example: Formation of Liquid vs. Gaseous Water

  • 2H<em>2(g)+O</em>2(g)2H2O(l)ΔH=890 kJ2H<em>2(g) + O</em>2(g) \rightarrow 2H_2O(l) \quad \Delta H = -890 \text{ kJ}
  • 2H<em>2(g)+O</em>2(g)2H2O(g)ΔH=802 kJ2H<em>2(g) + O</em>2(g) \rightarrow 2H_2O(g) \quad \Delta H = -802 \text{ kJ}
  • The difference in ΔH\Delta H accounts for the condensation of water vapor to liquid water.
  • The overall enthalpy change is the sum of the individual steps.

Hess's Law

  • The total enthalpy change for a reaction is the sum of the enthalpy changes for each step, regardless of the number of steps.

  • It doesn't matter how you get there, only the initial and final states.

  • Example:

    • 2H<em>2(g)+O</em>2(g)2H2O(g)2H<em>2(g) + O</em>2(g) \rightarrow 2H_2O(g)

    • 2H<em>2O(g)2H</em>2O(l)2H<em>2O(g) \rightarrow 2H</em>2O(l)

    • ΔH<em>total=ΔH</em>1+ΔH2\Delta H<em>{\text{total}} = \Delta H</em>1 + \Delta H_2

Standard Enthalpy of Formation

  • The enthalpy change when a compound is formed from its elements in their standard states.
  • Using Hess’s law, it's possible to calculate the enthalpy of a reaction using standard enthalpies of formation.
  • Reaction: C<em>3H</em>8+5O<em>23CO</em>2+4H2OC<em>3H</em>8 + 5O<em>2 \rightarrow 3CO</em>2 + 4H_2O
  • We can look up standard enthalpies of formation for C<em>3H</em>8C<em>3H</em>8, CO<em>2CO<em>2, and H</em>2OH</em>2O.

Applying Hess's Law with Standard Enthalpies of Formation

  • Imagine breaking reactants into elemental blocks and then reassembling them into products.
  • The overall ΔH\Delta H is the sum of the enthalpy changes for breaking down reactants and forming products.
  • ΔH<em>reaction=ΔH</em>f, productsΔH<em>f, reactants\Delta H<em>{\text{reaction}} = \sum \Delta H</em>{\text{f, products}} - \sum \Delta H<em>{\text{f, reactants}}, where ΔH</em>f\Delta H</em>{\text{f}} is the standard enthalpy of formation
  • Diagrammatical Representation:
    • Reactants (e.g., propane and oxygen) at a high energy level.
    • Products (e.g., CO2CO_2 and water) at a lower energy level.
    • Breaking reactants into elements and then forming products allows us to account for energy changes (bookkeeping).
  • The combustion reaction process involves taking all starting materials and accounting for the change in enthalpy from elemental forms and formation.
  • Does not describe reaction's mechanism, only start and end states.

Next Steps

  • The next lecture will consider entropy to determine whether reactions will spontaneously occur.