Chemical Kinetics – Reaction Mechanisms, Molecularity & Rate Laws
Reaction Mechanisms
A reaction mechanism = the step-by-step pathway that converts reactants to products.
Some reactions are 1-step (elementary) but, as the number/complexity of particles rises, multi-step pathways become overwhelmingly more probable.
Each elementary step has its own collision event that obeys its own rate law.
Net (Overall) Equation vs. Elementary Steps
Net equation = balanced chemical equation that shows only initial reactants and final products.
Elementary steps reveal hidden, short-lived species that never appear in the net equation.
Example given (color-coded R = red, Y = yellow, B = blue):
Net (overall) reaction: 2R + 2Y + B \longrightarrow R2Y2B
Possible 4-step mechanism:
R + R \rightarrow R_2
R2 + B \rightarrow R2B
Y + Y \rightarrow Y_2
R2B + Y2 \rightarrow R2Y2B
Reaction Intermediates
Defined as species produced in one step and consumed in a later step.
Highly energetic/unstable, exist only micro-seconds.
Because they cancel when steps are summed, they never appear in the net equation.
In the example above: R2, R2B and Y_2 are intermediates.
Collision-Probability Argument
A successful collision requires: right particles + right time + right place + correct orientation + E \ge E_a (activation energy).
Three-, four-, or five-particle simultaneous collisions are statistically rare.
Classroom demo: 16 R, 16 Y, 16 B particles at T = 300\,\text K ⇒ mostly 2-body collisions.
Even at 700\,\text K the vast majority remain 2-body; very few triple hits.
Multi-step mechanisms therefore decompose seemingly 5-body events into sequential 2- or 1-body events.
Rate-Determining (Slow) Step
Overall rate is governed by the slowest elementary step (longest time).
Example timing:
Step 1 = 1\,\text s
Step 2 = 0.01\,\text s
Step 3 = 42.6\,\text h (slow step)
Step 4 = 1\,\mu\text s
Total ≈ 42\,\text h\,36\,\text{min}; Step 3 controls the rate.
Rate law is written from reactants of the slow step only.
If Step 3 is Y + Y \rightarrow Y_2 then
\text{rate}=k[Y]^2Interpretation: bimolecular w.r.t. Y, second order overall for this mechanism.
Important AP disclaimer: final rate law must use only species present in the net reaction. If the slow step contains an intermediate, extra algebra (steady-state or pre-equilibrium) must remove it.
Molecularity & Reaction Order
Molecularity = number of molecules involved in an elementary step’s collision; determines the possible kinetic order for that step.
Common cases:
Unimolecular (1 particle) → first-order kinetics
Speed limited by internal bond rearrangement or shape change of a single molecule.
Bimolecular (2 particles) → second-order kinetics
Bond breaking & new bond forming occur in concert between attacker & victim.
Termolecular (3 particles) → third-order kinetics
Very rare unless one particle is a catalyst that “holds” the other two (induced-fit model).
>3 (quad-, quint-molecular) ≈ negligible in ordinary chemistry.
Zero-order kinetics
Rate independent of reactant concentration.
Analogies: people exiting a room (door size = rate limiter); reactions limited by catalyst surface area.
Diagram Interpretation Tips
If transition diagram shows bond breaking & forming simultaneously between two species → bimolecular.
If only one species deforms then fragments → unimolecular.
If catalyst plus two reactants converge → termolecular.
SN2 illustration: CH$3$I initially tetrahedral; as nucleophile approaches, CH$3$ group becomes pseudo-planar, iodide repelled → bond forming & breaking together (bimolecular).
Worked Mechanism Problem from Lecture
Given:
2A + B \rightarrow X (slow)
C + C \rightarrow Y
Y + X \rightarrow Z
X \rightarrow D + E
Net equation – cancel intermediates X, Y:
3A + B + 2C \rightarrow D + E + ZRate law – use slow step (#1): three reactant particles \Rightarrow third order overall
\text{rate}=k[A]^2[B]
Five Classical Factors Affecting Rate
Nature of reactants (bond type, state, complexity).
Temperature (via E_a & collision frequency).
Concentration or pressure (gas) – treated identically because both alter collision frequency.
Surface area (heterogeneous reactions/catalysts).
Presence of catalyst or inhibitor (homogeneous, heterogeneous or biochemical).
Thermodynamic vs. Kinetic Stability (Exam Reminder)
Thermodynamic: sign/magnitude of \Delta H, \Delta G, \Delta S.
Endothermic often more thermodynamically stable; exothermic less so.
Kinetic: magnitude of E_a, complexity of activated complex → governs rate not energy favorability.
Spontaneity depends on \Delta G = \Delta H - T\Delta S; exothermic generally spontaneous at Earth-like T.
Key Equations
Elementary-step rate law (general):
\text{rate}=k\prodi[\text{Reactant}i]^{mi} where mi = stoichiometric coefficient within that step.Arrhenius: k = A e^{-E_a/RT}
Overall reaction time illustration: t{total}=\sum t{step}; slowest t{step}\approx t{total}.
Study / Test Checklist
Write & cancel to obtain net equations from multi-step mechanisms.
Identify slow step → derive rate law with correct molecularity & only net-equation species.
Recognize zero-, first-, second-, third-order behaviour in graphs or data.
Interpret potential-energy vs. reaction-coordinate diagrams: E_a, \Delta H, catalyzed vs. uncatalyzed paths.
Distinguish thermodynamic vs. kinetic control; apply five rate factors; relate pressure ↔ concentration for gases.
Be comfortable with example numeric forms:
E_a displayed in \text{kJ mol}^{-1}
Rate-constant units:
• 0-order \text{M s}^{-1},
• 1-order \text s^{-1},
• 2-order \text{M}^{-1}\text s^{-1},
• 3-order \text{M}^{-2}\text s^{-1}.
(Le Chatelier & K_{eq} topics deferred to next unit.)