Advanced Sequences, Inequalities, and Straight Lines
Advanced Sequence Differences
First Difference in Arithmetic Progression (AP): * If the first difference of a sequence is in AP, the general term tn takes the quadratic form: * tn=an2+bn+c
First Difference in Geometric Progression (GP): * If the first difference is in GP, the general term takes the form: * tn=a(rn)+bn+c
Second Difference in AP: * If the second difference of a sequence is in AP, the general term is a cubic polynomial: * tn=an3+bn2+cn+d
Second Difference in GP: * If the second difference is in GP, the general term takes the form: * tn=a(rn)+cn2+dn+e
Case Study Example: * Sequence: 5+7+13+31+85+… up to 10 terms. This was analyzed in the context of identifying the order of difference.
Telescopic Method of Difference
Core Principle: * Express the general term tr as a difference of two terms of a function, such as tn=f(n+1)−f(n). * Summation formula: Sn=∑r=1ntr=[f(2)−f(1)]+[f(3)−f(2)]+⋯+[f(n+1)−f(n)] * Cancellation occurs, leaving only the first and last terms: Sn=f(n+1)−f(1).
Application Example 1 (Product of Odds): * Find the sum of 10 terms of S=(1×3×5)+(3×5×7)+(5×7×9)+… * General term: tr=(2r−1)(2r+1)(2r+3). * Transformation: Multiply and divide by the constant difference of the extended sequence. Use (2r+5)−(2r−3)=8. * tr=81[(2r−1)(2r+1)(2r+3)(2r+5)−(2r−3)(2r−1)(2r+1)(2r+3)] * Final Sum S10=81[f(10)−f(0)]=81[(19×21×23×25)+15].
Application Example 2 (Fractions with Odds): * Series: Sn=1×31+1×3×52+1×3×5×73+… * General term: tr=1×3×5…(2r+1)r. * Transformation: Multiply by 2. 2r=(2r+1)−1. * tr=21[1×3…(2r+1)(2r+1)−1]=21[1×3…(2r−1)1−1×3…(2r+1)1]. * Sum Sn=21[1−1×3…(2n+1)1].
JEE Mains 2021 Question: * Calculate 32−11+52−11+72−11+⋯+2012−11. * tr=(2r+1)2−11=4r(r+1)1=41[r1−r+11]. * Sum for n=100: 41[1−1011]=10125.
JEE Mains 2021 Question 2: * Sum of 10 terms of 12×223+22×325+32×427+… * General term: tr=r2(r+1)22r+1=r2(r+1)2(r+1)2−r2=r21−(r+1)21. * Result: 1−1121=121120.
Factorial Series and Summation
Product Property: * n×n!=((n+1)−1)n!=(n+1)!−n!
Example Case: * S=1⋅1!+2⋅2!+3⋅3!+⋯+100⋅100! * tr=(r+1)!−r! * S=101!−1!
Example Case (Fractional Factorials): * S=2!1+3!2+4!3+⋯+51!50 * tr=(r+1)!r=(r+1)!(r+1)−1=r!1−(r+1)!1. * Sum: 1−51!1.
Arithmetic, Geometric, Harmonic, and Root Mean Square Inequalities
Theorem for Positive Real Numbers: * For positive numbers a1,a2,…,an, the following hierarchy holds: * RMS≥AM≥GM≥HM
Definitions for Two Positive Numbers (a,b): * Arithmetic Mean (AM):2a+b * Geometric Mean (GM):ab * Harmonic Mean (HM):a+b2ab * Root Mean Square (RMS):2a2+b2
General Formulas for $n$ Numbers: * AM=n∑ai * GM=(a1a2…an)n1 * HM=∑ai1n * RMS=n∑ai2
Equality Condition: * The equality AM=GM=HM=RMS holds if and only if a1=a2=⋯=an.
Application - Minimum Values: * For f(x)=x+x1 where x > 0, since AM≥GM: 2x+x1≥x⋅x1=1⟹x+x1≥2. Range: [2,∞). * JEE Advanced 2011: Minimum value of a−5+a−4+3a−3+1+a8+a10 for a > 0. * Split 3a−3 into a−3+a−3+a−3. There are 8 terms total. * Check product: (a−5)(a−4)(a−3)3(1)(a8)(a10)=a−5−4−9+18=a0=1. * AM≥GM⟹8Sum≥(1)81⟹Minimum Sum=8.
Power Series Expansions and Maclaurin Series
Maclaurin Series Formula: * f(x)=f(0)+1!f′(0)x+2!f′′(0)x2+3!f′′′(0)x3+…
Exponential Series (ex): * ex=1+1!x+2!x2+3!x3+⋯=∑r=0∞r!xr * e−x=1−1!x+2!x2−3!x3+…
Logarithmic Series: * Valid for -1 < x \le 1: ln(1+x)=x−2x2+3x3−4x4+… * ln(1−x)=−x−2x2−3x3−…
Homework Exercise: * Evaluate ∑n=0∞n!n3.
Straight Lines - Fundamentals of Coordinate Geometry
Distances from Axes: * Distance of point (x,y) from X-axis = ∣y∣ (Modulus of Ordinate). * Distance of point (x,y) from Y-axis = ∣x∣ (Modulus of Abscissa).
Relative Movement: * Moving Right/Left: y-coordinate reflects no change; x-coordinate increases/decreases. * Moving Up/Down: x-coordinate reflects no change; y-coordinate increases/decreases.
Quadrant Logic (JEE Advanced 2011 Example): * Point coordinates involving logarithms: Determining signs of terms like 5+log2(x) to identify the quadrant.
Section Formula: * Internal Division:P(x,y)=(m+nmx2+nx1,m+nmy2+ny1). * External Division: Replace n with −n. * Harmonic Conjugates: If $P$ divides $AB$ internally and $Q$ divides $AB$ externally in ratio $m:n$, then $P$ and $Q$ are harmonic conjugates. Distances $AP, AB, AQ$ satisfy AB2=AP1+AQ1.
Collinearity of Three Points: * Conditions: Area of triangle is 0; Slope of $AB$ = Slope of $BC$; Section formula is applicable with a consistent ratio (λ).
Centers of Triangles
Centroid (G): * Intersection of medians. Divides each median in ratio 2:1 from the vertex. * Coordinates: (3x1+x2+x3,3y1+y2+y3). * Area Property: $G$ divides a triangle into 3 triangles of equal area and 6 smaller triangles of equal area.
Incenter (I): * Intersection of internal angle bisectors. Center of the circle touching all sides. * Equidistant from all sides. * Coordinates: (a+b+cax1+bx2+cx3,a+b+cay1+by2+cy3).
Circumcenter (O): * Intersection of perpendicular bisectors. Center of circle passing through vertices. * For a Right Triangle: Midpoint of the hypotenuse.
Orthocenter (H): * Intersection of altitudes. * For a Right Triangle: The vertex where the $90^{\circ}$ angle is formed.
The Euler Line (O−G−H Rule): * In any non-equilateral triangle, the Orthocenter ($H$), Centroid ($G$), and Circumcenter ($O$) are collinear. * Centroid ($G$) divides the segment HO in the ratio 2:1. * O-N-G-C mnemonic: Orthocenter ($H$), Nine-point center ($N$), Centroid ($G$), Circumcenter ($O$).
Special Triangle Properties: * Equilateral: All centers coincide (H=G=I=O). * Isosceles: All centers are collinear. * Image Property: The image of the Orthocenter ($H$) with respect to any side lies on the circumcircle.
Slope and Intercepts
Slope (m): * m=tan(θ) where θ is the angle with the positive X-axis. * Two-point form: m=x2−x1y2−y1.
Parallel and Perpendicular Lines: * Parallel: m1=m2. * Perpendicular: m1×m2=−1.
Angle Between Two Lines: * tan(θ)=∣1+m1m2m1−m2∣
Line Intercept Properties: * Equal Intercepts: Slopes m=−1. * Equal Length of Intercepts: Slope m=±1. * Equal Magnitude but Opposite Sign: Slope m=1. * Equally Inclined with Axes: Slope m=±1.
Questions & Discussion
Question: How many lines can pass through one point?
Response: Infinite lines. If you have both a point and a fixed slope, then exactly one line is defined.
Question: What happens to the slope of a vertical line?
Response: The angle is 90∘, so tan(90∘) is undefined. Thus, the slope is not defined.
Question: In a right-angled triangle, where is the circumcenter located?
Response: It is exactly at the midpoint of the hypotenuse.