Limits and Continuity in Calculus

Math 20A Study Notes

Instructor: Gaojin He
Department: Mathematics
Institution: University of California San Diego
Semester: Fall 2025

1. The Idea of Limit

1.1 Examples of Limits
Example 1: Finding Instantaneous Velocity
  • A ball is dropped from the air at time t = 0.

  • The displacement function is given by:
    s(t)=5t2extmeterss(t) = 5t^2 ext{ meters}

  • To find the instantaneous velocity at t = 1s, we approximate this value by finding the average speed over the interval [1, 1 + ∆t] where ∆t is small.

  • The average velocity is defined as:
    v=racextchangeinpositionextchangeintime=racst=racs(1+t)s(1)tv = rac{ ext{change in position}}{ ext{change in time}} = rac{∆s}{∆t} = rac{s(1 + ∆t) - s(1)}{∆t}

  • As ∆t → 0, we find that v → 10.

  • Therefore, the instantaneous velocity at t = 1s is:
    10extm/s10 ext{ m/s}

Example 2: Finding Tangent Lines
  • We need to define the tangent line of the function
    s(t)=5t2s(t) = 5t^2
    at the specific point (1, 5).

Steps to Define the Tangent Line:

  1. Point: The tangent line must pass through (1, 5).

  2. Slope: The slope of this line should approximate the slope of the secant line connecting (1, 5) and (1 + ∆t, 5(1 + ∆t)^2) on the graph.

  3. Calculation of Slope: The slope of the secant line is: rac5(1+t)25(1)t=rac5[(1+t)21]t=10+5trac{5(1 + ∆t)^2 - 5(1)}{∆t} = rac{5[(1 + ∆t)^2 - 1]}{∆t} = 10 + 5∆t

    • As ∆t → 0, the slope approaches 10.

  4. Tangent Equation: Thus, the equation of the tangent line can be derived as:
    y5=10(x1)<br>ightarrowy=10x5y - 5 = 10(x - 1) <br>ightarrow y = 10x - 5

1.2 Implications of Limits
  • The instantaneous velocity at time t0 can be described as the slope of the tangent line at the point (t0, s(t0)).

  • Fundamental limit principles demonstrate the behavior of functions as independent variables approach certain values.

2. Investigating Limits

2.1 Definition and Existence of Limits
  • Consider the function
    f(x)=rac<br>insinxxf(x) = rac{<br>in sin x}{x}
    which is undefined at x = 0.

  • Behavior Near Zero: The limit is investigated as follows:

    • If x approaches 0, then sin x also approaches 0, leading to finite ratios.

2.2 Formal Definition of Limits
  • Let L be a finite number.

  • If f(x) is defined for all x around c (open interval) but potentially not at c:

    • We declare
      extlimxocf(x)=Lext{lim}_{x o c} f(x) = L
      or
      f(x)oLextasxocf(x) o L ext{ as } x o c
      if the value of |f(x) - L| can be made arbitrarily small as x approaches c.

  • If L does not exist, we denote this by:
    extlimxocf(x)extDNEext{lim}_{x o c} f(x) ext{ DNE}.

2.3 Examples and Theorems on Limits
  • Theorem: For linear functions
    f(x)=ax+bf(x) = ax + b, the limit is defined as:
    extlimxocf(x)=f(c)=ac+bext{lim}_{x o c} f(x) = f(c) = ac + b.

  • Example Function:
    g(x)=3x+1g(x) = 3x + 1
    leads to:
    extlimxo4g(x)=13ext{lim}_{x o 4} g(x) = 13

3. The Concept of Continuity

3.1 Definitions of Continuity
  • Left-Continuous at a point c if:
    extlimxocf(x)=f(c)ext{lim}_{x o c^-} f(x) = f(c)

  • Right-Continuous at a point c if:
    extlimxoc+f(x)=f(c)ext{lim}_{x o c^+} f(x) = f(c)

  • A function f is continuous at c if both limits exist and equal to the function value:
    extlimxocf(x)=f(c)ext{lim}_{x o c} f(x) = f(c)

3.2 Types of Discontinuities
  • Removable Discontinuity: Exists when
    extlim<em>xocf(x)ext{lim}<em>{x o c} f(x) exists but does not equal f(c) or f(c) is undefined. Example: extLim</em>xo2f(x)=5extbutf(2)=10ext{Lim}</em>{x o 2} f(x) = 5 ext{ but } f(2) = 10.

  • Jump Discontinuity: Both one-sided limits exist but are not equal.

  • Infinite Discontinuity: One or both one-sided limits approach infinity at c.

  • Essential Discontinuity: Limits do not converge or approach infinity.

4. Differentiation

4.1 Definition of Derivative
  • The derivative of a function f at a point a is defined as:
    f(a)=extlimho0racf(a+h)f(a)hf'(a) = ext{lim}_{h o 0} rac{f(a + h) - f(a)}{h}

4.2 Tangent Line and Application
  • The tangent line's equation at point (a, f(a)) can be constructed as:
    yf(a)=f(a)(xa)y - f(a) = f'(a)(x - a)

4.3 Higher-Order Derivatives
  • n-th Order Derivative (denoted as f(n)(x)): Function obtained by deriving n times.

  • Example: For s(t) = 25t - 0.3t^3:

    • First derivative:
      s(t)=250.9t2s'(t) = 25 - 0.9t^2

    • Second derivative:
      s(t)=1.8s''(t) = -1.8

  • Acceleration interpreted as the second derivative.

4.4 Rates of Change
  • The derivative represents the instantaneous velocity when applied to displacement over time.

  • Example: Area function
    A(r)=extπr2A(r) = ext{π}r^2 has a derivative
    A(r)=2extπrA'(r) = 2 ext{π}r representing the circumference of a disk.

5. Trigonometric Functions

5.1 Definitions and the Unit Circle
  • Trigonometric functions defined as ratios in a right triangle.

  • Usage of radian as the preferred measure:
    heta=racsrheta = rac{s}{r} where s is arc length on the unit circle.

5.2 Fundamental Theorems about Derivatives
  • Theorems regarding primary trigonometric functions:
    racddx(extsinx)=extcosxrac{d}{dx}( ext{sin } x) = ext{cos } x
    racddx(extcosx)=extsinxrac{d}{dx}( ext{cos } x) = - ext{sin } x.

  • Lemmas (Addition Formulas):
    extsin(hetaimesextcos(β)+extsin(β))</p></li></ul><h4id="bf8d781cd6484331bf0189d478a325f1"datatocid="bf8d781cd6484331bf0189d478a325f1"collapsed="false"seolevelmigrated="true">6.TheChainRule</h4><h5id="98791ae944c24316acb72ab8a7c1a7eb"datatocid="98791ae944c24316acb72ab8a7c1a7eb"collapsed="false"seolevelmigrated="true">6.1DefinitionandApplications</h5><ul><li><p>Providedif<strong>f</strong>and<strong>g</strong>aredifferentiable,thechainrulestates:<br>ext{sin}( heta imes ext{cos}(\beta) + ext{sin}(\beta))</p></li></ul><h4 id="bf8d781c-d648-4331-bf01-89d478a325f1" data-toc-id="bf8d781c-d648-4331-bf01-89d478a325f1" collapsed="false" seolevelmigrated="true">6. The Chain Rule</h4><h5 id="98791ae9-44c2-4316-acb7-2ab8a7c1a7eb" data-toc-id="98791ae9-44c2-4316-acb7-2ab8a7c1a7eb" collapsed="false" seolevelmigrated="true">6.1 Definition and Applications</h5><ul><li><p>Provided if <strong>f</strong> and <strong>g</strong> are differentiable, the chain rule states: <br> rac{d}{dx}(f(g(x))) = f'(g(x))g'(x)</p></li></ul><h5id="756683376bf247ffa3b182b17771de9b"datatocid="756683376bf247ffa3b182b17771de9b"collapsed="false"seolevelmigrated="true">6.2ExampleofApplyingtheChainRule</h5><ul><li><p>Tocompute<br></p></li></ul><h5 id="75668337-6bf2-47ff-a3b1-82b17771de9b" data-toc-id="75668337-6bf2-47ff-a3b1-82b17771de9b" collapsed="false" seolevelmigrated="true">6.2 Example of Applying the Chain Rule</h5><ul><li><p>To compute <br> rac{d}{dx}[ ext{sin}(2x)] = 2 ext{cos}(2x).</p></li><li><p>Fordoublecompositions,applythechainrulerepetitively.</p></li></ul><h4id="6fe02678b0f04c26ab8575e7b689e659"datatocid="6fe02678b0f04c26ab8575e7b689e659"collapsed="false"seolevelmigrated="true">7.ImplicitDifferentiation</h4><h5id="39aaa69ffbb94acdbc0b3d36b64757e3"datatocid="39aaa69ffbb94acdbc0b3d36b64757e3"collapsed="false"seolevelmigrated="true">7.1ConceptOverview</h5><ul><li><p>Tangentlinescanexistevenifthefunctionisnotexplicitlygiven.</p></li></ul><h5id="5a6f0fc4d10143f2af7c059002f65649"datatocid="5a6f0fc4d10143f2af7c059002f65649"collapsed="false"seolevelmigrated="true">7.2Example:ImplicitDifferentiation</h5><ul><li><p>Giventhecircleequation<strong>x2+y2=1</strong>,findingtangentinvolvesdifferentiatingbothsidesimplicitly:<br>.</p></li><li><p>For double compositions, apply the chain rule repetitively.</p></li></ul><h4 id="6fe02678-b0f0-4c26-ab85-75e7b689e659" data-toc-id="6fe02678-b0f0-4c26-ab85-75e7b689e659" collapsed="false" seolevelmigrated="true">7. Implicit Differentiation</h4><h5 id="39aaa69f-fbb9-4acd-bc0b-3d36b64757e3" data-toc-id="39aaa69f-fbb9-4acd-bc0b-3d36b64757e3" collapsed="false" seolevelmigrated="true">7.1 Concept Overview</h5><ul><li><p>Tangent lines can exist even if the function is not explicitly given.</p></li></ul><h5 id="5a6f0fc4-d101-43f2-af7c-059002f65649" data-toc-id="5a6f0fc4-d101-43f2-af7c-059002f65649" collapsed="false" seolevelmigrated="true">7.2 Example: Implicit Differentiation</h5><ul><li><p>Given the circle equation <strong>x² + y² = 1</strong>, finding tangent involves differentiating both sides implicitly: <br>2x + 2y rac{dy}{dx} = 0
    ightarrow rac{dy}{dx} = - rac{x}{y}$$.