Algebra, Trigonometry, and Geometry Revision Study Guide
Fundamental Definitions and Types of Matrices
Order of the Matrix: If a matrix has m rows and n columns, it is of order m×n. * Example: Matrix A=(2amp;3amp;−10amp;−4amp;5) is of order 2×3. The element a11=2, a12=3, and a23=5.
The Row Matrix: A matrix consisting of exactly one row and any number of columns. Example: (1,2,3).
The Column Matrix: A matrix consisting of exactly one column and any number of rows. Examples: (10) and (3−15).
The Square Matrix: A matrix where the number of rows equals the number of columns. Example: (3amp;2−1amp;0).
The Diagonal Matrix: A square matrix where all elements are zero except for the main diagonal, where at least one element is not zero. Examples: (3amp;00amp;1) and (1amp;0amp;00amp;0amp;00amp;0amp;−5).
The Zero Matrix (O): A matrix in which all elements are zero. Examples: (0amp;0amp;0) or (0amp;00amp;0).
The Unit Matrix (I): A diagonal matrix where all elements of the main diagonal are equal to one. Examples: (1amp;00amp;1) and (1amp;0amp;00amp;1amp;00amp;0amp;1).
Matrix Operations and Transposition
Matrix Transpose: The transpose of matrix A, denoted by At, is created by replacing rows with columns and columns with rows. * Example: If A=(5amp;−2amp;13amp;4amp;6), then At=(5amp;3−2amp;41amp;6).
Symmetric Matrix: A square matrix A is symmetric if and only if A=At. * Example: A=(1amp;−2amp;5−2amp;3amp;65amp;6amp;4) is symmetric because At=A.
Skew-Symmetric Matrix: A square matrix A is skew-symmetric if and only if A=−At. * Example: A=(0amp;−3amp;23amp;0amp;4−2amp;−4amp;0) is skew-symmetric because At=(0amp;3amp;−2−3amp;0amp;−42amp;4amp;0)=−A.
The Equality of Two Matrices: Two matrices A and B are equal if they have the same order and their corresponding elements are equal (aij=bij). * Example: Given (xamp;2amp;−3y−xamp;1amp;−2)=(3amp;2amp;−35amp;1amp;−2), then x=3 and y−x=5. Solving for y gives y=8.
Scalar Multiplication: To multiply a real number by a matrix, multiply that number by every element in the matrix. * Example: If A=(−4amp;1amp;52amp;−3amp;−1), then 2A=(−8amp;2amp;104amp;−6amp;−2).
Adding and Subtracting Matrices: Matrices must be of the same order m×n. * A+B: A matrix where every element is the sum of corresponding elements in A and B. * A−B=A+(−B): A matrix where every element is the sum of corresponding elements in A and −B. * Example: A=(3amp;−2amp;2−2amp;5amp;−4), B=(0amp;−3amp;4−1amp;2amp;−2). A−B=(3amp;1amp;−2−1amp;3amp;−2).
Multiplying Matrices: For matrices A (order m×l) and B (order r×n), product AB is possible if and only if l=r (columns of A = rows of B). The resulting matrix is of order m×n. * Example: A=(2amp;−1amp;03amp;1amp;−2) (2×3) and B=(3amp;2−1amp;04amp;5) (3×2). The product AB is order 2×2. * Calculation: AB=((2)(3)+(−1)(−1)+(0)(4)amp;(2)(2)+(−1)(0)+(0)(5)(3)(3)+(1)(−1)+(−2)(4)amp;(3)(2)+(1)(0)+(−2)(5))=(7amp;40amp;−4).
2×2 Determinants: If A=(a11amp;a12a21amp;a22), then ∣A∣=a11a22−a21a12. * Example: ∣(4amp;−72amp;6)∣=(4×6)−(2×−7)=24+14=38.
3×3 Determinants: Expand using minor determinants along any row/column following the sign pattern (+amp;−amp;+−amp;+amp;−+amp;−amp;+). * Formula: ∣A∣=a11a22amp;a23a32amp;a33−a12a21amp;a23a31amp;a33+a13a21amp;a22a31amp;a32. * Triangular Matrix Property: Determinant equals the product of main diagonal elements: |\begin{pmatrix} a_{11} & a_{12} & a_{13} \ 0 & a_{22} & a_{23} \ 0 & 0 & a_{33} \end{vmatrix}| = a_{11}a_{22}a_{33}.
Area of Triangle XYZ: If X(a,b), Y(c,d), and Z(e,f), the area is ∣A∣ where A=21aamp;bamp;1camp;damp;1eamp;famp;1. If ∣A∣=0, points are collinear.
Multiplicative Inverse (A−1): Exists if ∣A∣=Δ=0. For 2×2 matrix A=(aamp;bcamp;d), A−1=Δ1(damp;−b−camp;a). * Example: A=(−2amp;23amp;−4). Δ=(−2×−4)−(3×2)=2. A−1=21(−4amp;−2−3amp;−2)=(−2amp;−1−23amp;−1).
Systems of Equations
Simultaneous Equations (2×2): Solving a1x+b1y=c1 and a2x+b2y=c2. * Cramer's Rule: Δ=a1amp;b1a2amp;b2, Δx=c1amp;b1c2amp;b2, Δy=a1amp;c1a2amp;c2. Then x=ΔΔx and y=ΔΔy. * Matrix Inverse Method: Write as AX=C where A=(a1amp;b1a2amp;b2), X=(xy), and C=(c1c2). Then X=A−1C.
Simultaneous Equations (3×3): For equations with variables x,y,z, calculate Δ, Δx, Δy, and Δz using determinants. x=ΔΔx, y=ΔΔy, z=ΔΔz.
Linear Programming and Optimization
Boundary Lines: * Inequalities with ≥ or ≤ are represented by solid lines (boundary is part of the solution). * Inequalities with > or < are represented by dashed lines (boundary is not part of the solution).
Graphical Solution Set: Determine the region for each individual inequality. The overlap of all regions is the common solution set.
Objective Function Optimization: To maximize or minimize P=ax+by, evaluate the function at the corner points (vertices) of the shaded solution region. * Example: Region defined by x≥0,y≥0,x+2y≤8,3x+2y≤12. Objective function P=50x+75y. Evaluated at: A(4,0)→P=200, B(2,3)→P=325, C(0,4)→P=300. Maximum value is 325 at (2,3).
General Solutions for Trigonometric Equations (β is smallest positive angle, n∈Z): * cos(θ)=a⇒θ=±β+2πn. * sin(θ)=a⇒θ=β+2πn or θ=(π−β)+2πn. * tan(θ)=a⇒θ=β+πn.
Solving Right-Angled Triangles: Use Pythagoras (AC2=AB2+BC2) and ratios (SOH CAH TOA).
Angles of Elevation and Depression: * Elevation: Point of target is above horizontal line. * Depression: Point of target is below horizontal line. * Elevation angle of B from A equals depression angle of A from B.
Triangles and Polygons Areas: * General Triangle: 21base×height or 21absin(θ). * Equilateral Triangle: 43s2. * Regular Hexagon: 233s2. * Quadrilateral: 21d1d2sin(θ). * Regular Polygon (n sides, side x): Area A=41nx2cot(nπ).
Definitions: A directed line segment has starting/ending points and direction (AB=−BA).
Equivalence: AB=CD if they have the same norm (length) and same direction.
Norm: For point A(x,y), ∥A∥=x2+y2.
Polar Form: Expressed as (∥A∥,θ). * Components: x=∥A∥cos(θ), y=∥A∥sin(θ).
Unit Vector: A vector with norm 1. Fundamental unit vectors: i=(1,0) and j=(0,1).
Vector Operations: * Geometric: AB+BC=AC. * Parallelogram rule: AB+AC=AD where AD is the diagonal. * Algebraic: A+B=(x1+x2,y1+y2).
Parallel and Perpendicular Vectors: * Parallel (A//B): Slopes are equal (x1y1=x2y2). * Perpendicular (A⊥B): Product of slopes is −1 (x1x2+y1y2=0).
Lines and Physical Applications
Resultant Force: F=F1+F2+…
Relative Velocity: Velocity of B relative to A is VBA=VB−VA.
Division of Line Segment: Point C(x,y) divides segment between (x1,y1) and (x2,y2) with ratio m2:m1. * Formula: x=m1+m2m1x1+m2x2, y=m1+m2m1y1+m2y2. * Internally: m_2/m_1 > 0. Externally: m_2/m_1 < 0.
Slope of Straight Line: * From points: m=x2−x1y2−y1. * From angle: m=tan(θ). * From equation ax+by+c=0: m=−ba.
Different Forms of Line Equation: * Vector Form: r=A+ku. * Cartesian Form: y−y1=m(x−x1). * Intercept Form: ax+by=1.
Angle between Lines: tan(θ)=∣1+m1m2m1−m2∣ for θ∈[0,2π].
Perpendicular Length from Point (x1,y1) to line ax+by+c=0: * L=a2+b2∣ax1+by1+c∣.
Questions & Discussion
Q: Given B=(2amp;43amp;1) and AB=I, find matrix A. * A: A=B−1. Construct Δ=(2×1)−(3×4)=−10. A=−101(1amp;−4−3amp;2)=(−101amp;52103amp;−51).
Q: Does (xamp;49amp;x) have no inverse? * A: If Δ=x2−36=0, then x=±6.
Q: Determine if points (3,5) and (1,5) satisfy x+y≤8. * A: 3+5=8≤8 (True) and 1+5=6≤8 (True).
Q: Find the area of the triangle with vertices (1,−2), (3,2), (5,3). * A: Using determinant formula: 21∣1(2−3)−(−2)(3−5)+1(9−10)∣=21∣−1−4−1∣=3. Result: 3 square units.
Q: A person observes a plane at 1000m height with elevation angle 40∘. Find the observer-plane distance. * A: sin(40∘)=x1000⇒x=sin(40∘)1000≈1556 meters.