Physics Quick-Review Notes

Fundamental SI (Base) Units

  • Time → s\text{s} (second)

  • Electric current → A\text{A} (ampere)

  • Amount of substance → mol\text{mol} (mole)

  • Temperature → K\text{K} (kelvin)

  • Length → m\text{m} (meter)

  • Mass → kg\text{kg} (kilogram)

  • Luminous intensity → cd\text{cd} (candela)

  • Liters (L\text{L}) = derived (NOT a base unit)

Core Kinematics

  • Average velocity: v=Δxtv = \dfrac{\Delta x}{t}

  • Average speed: s=distancets = \dfrac{\text{distance}}{t}

  • Acceleration (kinematics): a=Δvta = \dfrac{\Delta v}{t}

Three key constant-acceleration ("family") equations
  1. v<em>f=v</em>i+atv<em>f = v</em>i + a t

  2. Δx=vit+12at2\Delta x = v_i t + \dfrac12 a t^2

  3. v<em>f2=v</em>i2+2aΔxv<em>f^2 = v</em>i^2 + 2 a \Delta x

Uniform Circular Motion

  • Centripetal (radial) acceleration: ac=v2ra_c = \dfrac{v^2}{r}

  • vv tangent to circle; aca_c points to center; they are 9090^{\circ} apart.

Units to Recall

  • Velocity / speed → m/s\text{m\,/\,s}

  • Acceleration → \text{m\,/\,s^2}

  • Force → \text{N} = \text{kg·m\,/\,s^2}

  • Displacement / distance → m\text{m}

Problem-Solving Template (GUESS)

  • G – Given data

  • U – Unknown quantity

  • E – Equation to use

  • S – Substitute

  • S – Solve (include units)

Worked Examples

  • Linear motion: v<em>i=20m/sv<em>i = 20\,\text{m/s}, a = 1\,\text{m/s^2}, t=25st = 25\,\text{s}v</em>f=20+(1)(25)=45m/sv</em>f = 20 + (1)(25) = 45\,\text{m/s}

  • Circular motion: ac = 2\,\text{m/s^2}, r=8mr = 8\,\text{m}v=a</em>cr=(2)(8)=4m/sv = \sqrt{a</em>c r} = \sqrt{(2)(8)} = 4\,\text{m/s}

Significant-Figure Rules (quick)

  • With decimal: start left, first non-zero → count every digit after.

  • Without decimal: start right, first non-zero → count leftward; trailing zeros are NOT significant.

  • Examples:
    7.07.022 sig figs • 0.000970.0009722 • 90.05790.05755 • 150.150.33 (decimal forces zeros to count)

Interpreting Motion Graphs

  • Slope of distance–time graph ⇒ velocity.

  • Slope of velocity–time graph ⇒ acceleration.

  • Flat vvtt line above zero → constant speed.

  • Downward-sloping vvtt line → constant negative acceleration (deceleration).

  • Curved ddtt graph with decreasing steepness → high acceleration initially, decreasing later.

  1. Units of Measurement

1.1 Fundamental SI (Base) Units

  • Time
    s\text{s} (second)

  • Electric current
    A\text{A} (ampere)

  • Amount of substance
    mol\text{mol} (mole)

  • Temperature
    K\text{K} (kelvin)

  • Length
    m\text{m} (meter)

  • Mass
    kg\text{kg} (kilogram)

  • Luminous intensity
    cd\text{cd} (candela)

  • Liters (L\text{L}) = derived (NOT a base unit)

1.2 Common Derived Units for Motion and Force

  • Velocity / speed
    m/s\text{m/s} (meters per second)

  • Acceleration
    → \text{m/s^2} (meters per second squared)

  • Displacement / distance
    m\text{m} (meters)

  • Force
    → \text{N} = \text{kg·m/s^2} (Newtons, which are kilograms times meters per second squared)

  1. Kinematics and Motion Principles

2.1 Core Kinematics Formulas

  • Average velocity: v=Δxtv = \dfrac{\Delta x}{t} (change in position over time)

  • Average speed: s=distancets = \dfrac{\text{distance}}{t} (total distance over time)

  • Acceleration (kinematics): a=Δvta = \dfrac{\Delta v}{t} (change in velocity over time)

2.2 Constant-Acceleration Equations ("Family" Equations)

  • v<em>f=v</em>i+at\textit{v}<em>f = \textit{v}</em>i + \textit{at} (final velocity equals initial velocity plus acceleration times time)

  • Δx=vit+12at2\Delta x = \textit{v}_i \textit{t} + \frac{1}{2} \textit{a} \textit{t}^2 (change in position equals initial velocity times time plus one-half acceleration times time squared)

  • v<em>f2=v</em>i2+2aΔx\textit{v}<em>f^2 = \textit{v}</em>i^2 + 2\textit{a}\Delta x (final velocity squared equals initial velocity squared plus two times acceleration times change in position)

2.3 Uniform Circular Motion

  • Centripetal (radial) acceleration: ac=v2r\textit{a}_c = \dfrac{\textit{v}^2}{\textit{r}} (centripetal acceleration equals velocity squared divided by radius)

  • v\textit{v} is tangent to the circle (points along the circle's edge); ac\textit{a}_c points to the center of the circle; they are 9090^{\circ} apart (perpendicular).

2.4 Interpreting Motion Graphs

  • The slope of a distance–time graph tells you the object's velocity.

  • The slope of a velocity–time graph tells you the object's acceleration.

  • A flat line on a velocity–time (vt\textit{v} – \textit{t}) graph, above zero, means the object has constant speed.

  • A downward-sloping line on a velocity–time (vt\textit{v} – \textit{t}) graph means the object has constant negative acceleration (it's slowing down or accelerating in the negative direction).

  • A curved line on a distance–time (dt\textit{d} – \textit{t}) graph that gets less steep means the object had high acceleration initially, but it is decreasing later.

  1. Problem-Solving and Data Handling

3.1 Problem-Solving Template (GUESS Method)

  • GGiven data: Write down all the numerical values provided in the problem.

  • UUnknown quantity: Identify what you need to find.

  • EEquation to use: Choose the appropriate formula or equation that connects your given data to your unknown.

  • SSubstitute: Plug the given numerical values into your chosen equation.

  • SSolve: Calculate the answer and make sure to include the correct units.

3.2 Worked Examples

  • Linear motion: If initial velocity (vi\textit{v}_i) = 20m/s20\,\text{m/s}, acceleration (a\textit{a}) = 1\,\text{m/s^2}, and time (t\textit{t}) = 25s25\,\text{s}:

    Use formula: v<em>f=v</em>i+at\textit{v}<em>f = \textit{v}</em>i + \textit{at}

    Substitute: vf=20+(1)(25)\textit{v}_f = 20 + (1)(25)

    Solve: vf=45m/s\textit{v}_f = 45\,\text{m/s} (final velocity)

  • Circular motion: If centripetal acceleration (ac\textit{a}_c) = 2\,\text{m/s^2} and radius (r\textit{r}) = 8m8\,\text{m}:

    Use formula: a<em>c=v2r\textit{a}<em>c = \dfrac{\textit{v}^2}{\textit{r}} which can be rearranged to v=a</em>cr\textit{v} = \sqrt{\textit{a}</em>c \textit{r}}

    Substitute: v=(2)(8)\textit{v} = \sqrt{(2)(8)}

    Solve: v=16=4m/s\textit{v} = \sqrt{16} = 4\,\text{m/s} (speed of the object)

3.3 Significant-Figure Rules (Quick Reference – Simplified)

Significant figures (or sig figs) tell you how precise a measurement is. Here’s how to count them:

  • Rule 1: If there is a decimal point in the number (Explicit Decimal)

    • Start counting from the leftmost non-zero digit.

    • Count all digits from that point, including any zeros that follow, even if they are at the very end.

    • Examples:

      • 7.07.0
        → Counts 7 and 0. So, 22 significant figures.

      • 0.000970.00097
        → Start at 9. Counts 9 and 7. So, 22 significant figures.

      • 90.05790.057
        → Start at 9. Counts 9, 0, 0, 5, 7. So, 55 significant figures.

      • 150.150.
        → The decimal point is present. Start at 1. Counts 1, 5, 0. So, 33 significant figures.

  • Rule 2: If there is NO decimal point in the number (Implicit Decimal)

    • Start counting from the rightmost non-zero digit.

    • Count all digits leftward from that point.

    • Trailing zeros (zeros at the very end of the number) are NOT considered significant if there's no decimal point.

    • Example:

      • 150150 (no decimal point)
        → Start counting from 5 (the rightmost non-zero digit). Counts 1 and 5. The 0 is a trailing zero and is not counted. So, 22 significant figures.