Gas Laws – Review Problems & Test Preparation

Review Problem #1 – Mixing Three Separate Gas Samples

• Scenario: Three rigid containers (each previously sealed) are connected via a volumeless valve; once the valve is opened, the gases freely inter-diffuse and occupy the combined space.

• Given data before mixing
– Container A (N₂): P<em>N</em>2,  initial=265  Torr,  V<em>A=1.0  LP<em>{N</em>2,\;initial}=265\;\text{Torr},\;V<em>{A}=1.0\;\text{L} – Container B (Ne): P</em>Ne,  initial=800  Torr,  V<em>B=1.0  LP</em>{Ne,\;initial}=800\;\text{Torr},\;V<em>{B}=1.0\;\text{L} – Container C (H₂): P</em>H<em>2,  initial=532  Torr,  V</em>C=0.50  LP</em>{H<em>2,\;initial}=532\;\text{Torr},\;V</em>{C}=0.50\;\text{L}
→ Total final volume after the valve is opened: Vtotal=1.0+1.0+0.50=2.5  LV_{total}=1.0+1.0+0.50=2.5\;\text{L}
(Temperature and amount of each gas are unchanged; the only variable that changes is volume.)

• Physics/chemistry principle: Boyle’s Law P<em>1V</em>1=P<em>2V</em>2P<em>1V</em>1=P<em>2V</em>2 for each gas separately, followed by Dalton’s Law of Partial Pressures P<em>tot=P</em>iP<em>{tot}=\sum P</em>i when all partial pressures refer to the same, common volume.

• Step-wise calculation (shown for each gas):

  1. Solve for new partial pressure P<em>i,  final=P</em>i,  initial(V<em>i,  initialV</em>total)P<em>{i,\;final}=P</em>{i,\;initial}\left(\dfrac{V<em>{i,\;initial}}{V</em>{total}}\right)

  2. Compute numerical values:
    – N₂ : P<em>N</em>2=265  Torr×1.02.5=106  TorrP<em>{N</em>2}=265\;\text{Torr}\times\dfrac{1.0}{2.5}=106\;\text{Torr}
    – Ne : P<em>Ne=800  Torr×1.02.5=320  TorrP<em>{Ne}=800\;\text{Torr}\times\dfrac{1.0}{2.5}=320\;\text{Torr} – H₂ : P</em>H2=532  Torr×0.502.5=106  Torr  (106.4  Torr rounded)P</em>{H_2}=532\;\text{Torr}\times\dfrac{0.50}{2.5}=106\;\text{Torr}\;(106.4\;\text{Torr rounded})

• Total pressure after mixing:
Ptot=106+320+106  Torr=532  TorrP_{tot}=106+320+106 \;\text{Torr}=532\;\text{Torr}

• Conceptual takeaways
– Each gas obeys Boyle’s Law independently because nn and TT are constant for that gas.
– Dalton’s Law assumes gas particles do not interact (ideal behaviour). Once the gases share a volume, each exerts its own pressure proportional to its mole fraction and the common T,VT,V.


Review Problem #2 – Gas Collected Over Water (Dalton’s Law + Combined Gas Law)

• Lab technique: A gas is captured by water displacement. The collected volume actually contains dry gas + water vapour. Measured pressure is the sum of the two.

• Given data
– Manometer reading: P<em>meas=103.64  kPaP<em>{meas}=103.64\;\text{kPa} – Water-vapour pressure at the bath temperature: P</em>H<em>2O=21.60  kPaP</em>{H<em>2O}=21.60\;\text{kPa} – Collected volume: V</em>1=500  mL=0.500  LV</em>1=500\;\text{mL}=0.500\;\text{L}
– Bath temperature: T<em>1=292  KT<em>1=292\;\text{K} – Target conditions: STP (P</em>2=1  atm=101.325  kPa,  T2=273  K)(P</em>2=1\;\text{atm}=101.325\;\text{kPa},\;T_2=273\;\text{K})

• Step 1 – Isolate the pressure of the dry gas (Dalton):
P<em>dry=P</em>measP<em>H</em>2O=103.6421.60=82.04  kPaP<em>{dry}=P</em>{meas}-P<em>{H</em>2O}=103.64-21.60=82.04\;\text{kPa}

• Step 2 – Use the Combined Gas Law to convert to STP volume:
P<em>1V</em>1T<em>1=P</em>2V<em>2T</em>2V<em>2=P</em>1V<em>1T</em>2P<em>2T</em>1\frac{P<em>1V</em>1}{T<em>1}=\frac{P</em>2V<em>2}{T</em>2}\quad\Rightarrow\quad V<em>2=\frac{P</em>1V<em>1T</em>2}{P<em>2T</em>1}
V2=82.04  kPa×0.500  L×273  K101.325  kPa×292  K=0.378  L=378  mLV_2=\frac{82.04\;\text{kPa}\times0.500\;\text{L}\times273\;\text{K}}{101.325\;\text{kPa}\times292\;\text{K}}=0.378\;\text{L}=378\;\text{mL}

• Key facts & reminders
– Always subtract the vapour pressure of water to obtain the pressure of the dry sample.
– STP is 0 °C (273 K) and 1 atm (101.325 kPa).
– Temperatures must be in Kelvin for gas-law calculations.


Review Problem #3 – Initial–Final State with Constant V & T (Gay-Lussac-Type)

• Scenario: Rigid 500 mL vessel at constant room temperature T=295  KT=295\;\text{K} initially holds 100 g of CO₂. An additional 50 g CO₂ is injected. Find the new pressure.

• Quantities that stay constant: V,  TV,\;T
Quantity changing: nn (moles) → pressure will scale with nn.

• Relationship (Gay-Lussac variant): P<em>1n</em>1=P<em>2n</em>2P<em>2=P</em>1(n<em>2n</em>1)\displaystyle\frac{P<em>1}{n</em>1}=\frac{P<em>2}{n</em>2}\quad\Rightarrow\quad P<em>2=P</em>1\left(\frac{n<em>2}{n</em>1}\right)

• Convert masses to moles using molar mass M<em>CO</em>2=44.007  gmol1M<em>{CO</em>2}=44.007\;\text{g\,mol}^{-1}
– Initial: n<em>1=10044.007=2.272  moln<em>1=\frac{100}{44.007}=2.272\;\text{mol} – Final: n</em>2=15044.007=3.408  moln</em>2=\frac{150}{44.007}=3.408\;\text{mol}

• Compute new pressure:
P2=765  mmHg×3.4082.272=1.148×103  mmHg  (1.148  atm×760  mmHg/atm)P_2=765\;\text{mmHg}\times\frac{3.408}{2.272}=1.148\times10^{3}\;\text{mmHg}\;(1.148\;\text{atm}\times760\;\text{mmHg/atm})

• Practical considerations
– Rigid, constant-temperature container ⇒ only PP scales with nn.
– If any variable other than PP or nn were allowed to change, the ideal gas law or another combined relationship would be required.


Exam & Conceptual Guide (Chs 18 & 19)

1. Standard Temperature and Pressure (STP)

• Definition: T=273  KT=273\;\text{K} (0 °C), P=1  atm=101.325  kPa=760  Torr=760  mmHgP=1\;\text{atm}=101.325\;\text{kPa}=760\;\text{Torr}=760\;\text{mmHg}
• Questions may simply say “STP”; know both the concept and the numerical values.

2. Ideal vs. Real Gases

• Ideal-gas postulates:
– Point-like particles with negligible volume.
– No intermolecular forces; collisions are perfectly elastic.
– Gas obeys PV=nRTPV=nRT at all T,P,n,VT,P,n,V.

• Real gases deviate at:
– High pressure: particles are forced close together → finite molecular volume + significant Coulombic attractions (reduced PP).
– Low temperature: kinetic energy (12mv2)\left(\tfrac12 m v^2\right) is insufficient to overcome attractions → trajectory deviates, effective PP drops.

3. Graphical & Mathematical Relationships

• Direct vs inverse proportionalities (e.g., Boyle, Charles, Gay-Lussac).
• Be able to recognize or sketch linear vs hyperbolic plots.

4. Units & Conversions

• Common pressure units: atm,  kPa,  Torr,  mmHg\text{atm},\;\text{kPa},\;\text{Torr},\;\text{mmHg}.
• Always convert Celsius → Kelvin before calculation.
• Occasional problems may embed mixed units; be ready.

5. Diffusion & Graham’s Law

• Concept: rate of diffusion/effusion 1M\propto\dfrac{1}{\sqrt{M}} (
v<em>1v</em>2=M<em>2M</em>1\dfrac{v<em>1}{v</em>2}=\sqrt{\dfrac{M<em>2}{M</em>1}}).
• Two common tasks:

  1. “How many times faster/slower?” (velocity ratio).

  2. “How long will it take?” (time inversely proportional to velocity).

6. Dalton’s Law Variants

• Total vs partial pressures in a mixture.
• Gas collected over water (subtract vapour pressure).
• Partial-pressure adjustment when volume changes (as in Review Problem #1).

7. “Initial → Final” State Problems

• Identify which variables change; apply the appropriate simplified law or the full combined gas law.
• Examples: constant V,TV,T (Gay-Lussac-type), constant P,TP,T (Charles-type), constant P,VP,V (Avogadro-type), etc.

8. Allowed Resources

• You may use a personal formula sheet during the test.
• Extensive practice worksheets + answer keys are posted (check Edmodo).

9. Practical Study Tips

• Work through assorted practice problems to build speed.
• Focus on unit consistency; many errors are unit-related.
• Understand why each law applies, not just which plugged-in numbers produce an answer.
• Email the instructor for clarification as needed.


Ethical & Real-World Connections

• Gas-law deviations underpin industrial liquefaction (e.g., LNG plants), high-pressure scuba considerations, and atmospheric science.
• Understanding vapour-pressure corrections is vital in environmental monitoring where humidity skews sensor readings.
• Awareness of ideal-vs-real behaviour prevents unsafe assumptions—e.g., cylinder filling under high pressure.


Formula Summary (Quick Reference)

• Ideal gas law: PV=nRTPV=nRT
• Boyle’s: P<em>1V</em>1=P<em>2V</em>2P<em>1V</em>1=P<em>2V</em>2 (constant n,Tn,T)
• Charles’s: V<em>1T</em>1=V<em>2T</em>2\dfrac{V<em>1}{T</em>1}=\dfrac{V<em>2}{T</em>2} (constant n,Pn,P)
• Gay-Lussac’s: P<em>1T</em>1=P<em>2T</em>2\dfrac{P<em>1}{T</em>1}=\dfrac{P<em>2}{T</em>2} (constant n,Vn,V)
• Combined: P<em>1V</em>1T<em>1=P</em>2V<em>2T</em>2\dfrac{P<em>1V</em>1}{T<em>1}=\dfrac{P</em>2V<em>2}{T</em>2}
• Dalton’s: P<em>tot=</em>iP<em>iP<em>{tot}=\sum</em>i P<em>i • Graham’s: v</em>1v<em>2=M</em>2M<em>1\dfrac{v</em>1}{v<em>2}=\sqrt{\dfrac{M</em>2}{M<em>1}} • Mole fraction: X</em>i=n<em>in</em>tot,  P<em>i=X</em>iPtotX</em>i=\dfrac{n<em>i}{n</em>{tot}},\;P<em>i=X</em>iP_{tot}

Use the reference sheet during practice to ensure fluency with variable isolation and unit handling.