Complex Numbers – Polar Form, Operations, De Moivre & Roots

Complex Plane – Orientation & Plotting

  • Complex numbers are written a+bia + b i where:

    • aa = real part (plotted on horizontal axis)

    • bib i = imaginary part (plotted on vertical axis)

  • Quadrant summary (using the mnemonic "cos-first, sin-second”):

    • QI a>0,\;b>0 ⇒ \cos>0,\;\sin>0

    • QII a<0,\;b>0 ⇒ \cos<0,\;\sin>0

    • QIII a<0,\;b<0 ⇒ \cos<0,\;\sin<0

    • QIV a>0,\;b<0 ⇒ \cos>0,\;\sin<0

  • Purely real points lie on the horizontal axis (angle 00 or π\pi). Purely imaginary points lie on the vertical axis (angle ±π2\pm\tfrac{\pi}{2}).

Rectangular ↔ Polar Conversions

  • Polar form: z=r(cosθ+isinθ)z = r(\cos\theta + i\,\sin\theta)

    • r=z=a2+b2r = |z| = \sqrt{a^{2}+b^{2}} (modulus)

    • θ=argz\theta = \arg z (principal argument, measured in degrees or radians)

  • Converting polar → rectangular:

    1. Evaluate cosθ\cos\theta and sinθ\sin\theta.

    2. Multiply both by rr.

  • Example (from lecture)

    • Given 2(cos30+isin30)2(\cos30^{\circ} + i\,\sin30^{\circ})

    • cos30=32,  sin30=12\cos30^{\circ}=\tfrac{\sqrt3}{2},\; \sin30^{\circ}=\tfrac12

    • x=232=3x = 2\cdot\tfrac{\sqrt3}{2}=\sqrt3, y=212=1y = 2\cdot\tfrac12 = 1

    • Rectangular answer: 3+i\sqrt3 + i.

  • Example with r=10r=10, θ=270\theta = 270^{\circ}10(cos270+isin270)=10(0i)=10i10(\cos270^{\circ}+i\sin270^{\circ}) = 10(0- i) = -10i.

Products & Quotients in Polar Form (Section 5.3)

  • Product rule (very “friendly”): z<em>1z</em>2=r<em>1r</em>2(cos(θ<em>1+θ</em>2)+isin(θ<em>1+θ</em>2))z<em>1 z</em>2 = r<em>1 r</em>2\bigl(\cos(\theta<em>1+\theta</em>2)+i\,\sin(\theta<em>1+\theta</em>2)\bigr)

    • Multiply moduli, add arguments.

    • Order does NOT matter.

  • Quotient rule (be careful with order!) z<em>1z</em>2=r<em>1r</em>2(cos(θ<em>1θ</em>2)+isin(θ<em>1θ</em>2))\frac{z<em>1}{z</em>2}=\frac{r<em>1}{r</em>2}\Bigl(\cos(\theta<em>1-\theta</em>2)+i\,\sin(\theta<em>1-\theta</em>2)\Bigr)

    • Divide moduli, subtract arguments (top – bottom).

    • Adjust any negative or >360360^{\circ} angles by adding/subtracting 360360^{\circ} or 2π2\pi to land back in one revolution.

  • Worked example (textbook Ex. 1): z=3(cos20+isin20),  w=15(cos140+isin140)z=3(\cos20^{\circ}+i\sin20^{\circ}),\;w=15(\cos140^{\circ}+i\sin140^{\circ})

    • Product: 45(cos160+isin160)45\bigl(\cos160^{\circ}+i\sin160^{\circ}\bigr)

    • Quotient: 15(cos240+isin240)\tfrac15\bigl(\cos240^{\circ}+i\sin240^{\circ}\bigr) because 20140=12024020-140=-120 \rightarrow 240^{\circ}.

De Moivre’s Theorem – Powers

  • Statement: [r(cosθ+isinθ)]n=rn(cos(nθ)+isin(nθ))[r(\cos\theta+i\sin\theta)]^{n}=r^{n}\bigl(\cos(n\theta)+i\,\sin(n\theta)\bigr) for any integer nn.

  • Steps

    1. Raise modulus: rnr^{n}.

    2. Multiply angle: nθn\theta.

    3. If required, convert final polar result to rectangular by evaluating trig values.

  • Classroom examples

    • [2(cos20+isin20)]3=8(cos60+isin60)=8(12+i32)=4+4i3\bigl[2(\cos20^{\circ}+i\sin20^{\circ})\bigr]^{3}=8(\cos60^{\circ}+i\sin60^{\circ})=8\left(\tfrac12 + i\,\tfrac{\sqrt3}{2}\right)=4+4i\sqrt3

    • [6(cos60+isin60)]5=7776(cos300+isin300)=38883888i3\bigl[6(\cos60^{\circ}+i\sin60^{\circ})\bigr]^{5}=7776(\cos300^{\circ}+i\sin300^{\circ})=3888-3888i\sqrt3

    • Example mixing rectangular start:

    1. Convert 3i\sqrt3 - i to polar ⇒ r=2,  θ=300r=2,\;\theta=300^{\circ}.

    2. Raise to 6th power ⇒ 26(cos(1800)+isin(1800))=64(cosπ+isinπ)=642^{6}(\cos(1800^{\circ})+i\sin(1800^{\circ})) =64(\cos\pi+i\sin\pi)=-64.

De Moivre’s Theorem – n-th Roots

  • Formula for all nn roots (k=0,1,,n1k=0,1,\dots,n-1):
    <br>zn=rn  (cosθ+360kn+isinθ+360kn)<br><br>\sqrt[n]{z}=\sqrt[n]{r}\;\Bigl(\cos\tfrac{\theta+360^{\circ}k}{n}+ i\,\sin\tfrac{\theta+360^{\circ}k}{n}\Bigr)<br>

  • Geometric facts

    • Exactly nn roots, equally spaced by Δθ=360n\Delta \theta = \tfrac{360^{\circ}}{n}.

    • All roots lie on a circle of radius rn\sqrt[n]{r}.

  • 5th-root example (lecture):

    1. Original number: 12+i32=2(cos120+isin120)-\tfrac12 + i\tfrac{\sqrt3}{2}=2\bigl(\cos120^{\circ}+i\sin120^{\circ}\bigr).

    2. 5th-root modulus: 25\sqrt[5]{2}.

    3. Base angle: 1205=24\tfrac{120^{\circ}}{5}=24^{\circ}.

    4. Add 7272^{\circ} (because 360/5360/5) repeatedly:

    • 24,<br>96,<br>168,<br>240,<br>31224^{\circ},<br>96^{\circ},<br>168^{\circ},<br>240^{\circ},<br>312^{\circ}.

    1. Full root list: 25(cos24+isin24),  \sqrt[5]{2}\Bigl(\cos24^{\circ}+i\sin24^{\circ}\Bigr),\;\dots (five total).

  • 4th-root example with an existing square-root modulus:

    • z=1iz=-1-ir=2,  θ=225r=\sqrt2,\;\theta=225^{\circ}.

    • Careful with the combined index: current radical already has index 2, new root index 4 ⇒ overall 28\sqrt[8]{2}.

    • First root angle =2254=56.25=\tfrac{225^{\circ}}{4}=56.25^{\circ}, spacing =90=90^{\circ}.

    • Subsequent angles: 146.25,236.25,326.25146.25^{\circ},236.25^{\circ},326.25^{\circ}.

Handling Indices Inside Existing Radicals

  • If modulus already appears as rm\sqrt[m]{r} and you take an nn-th root, total index becomes mnm\,n.

  • Example shown: 2\sqrt{2} (index 22) then 4th root ⇒ overall 28\sqrt[8]{2}.

Common Pitfalls & Instructor Warnings

  • Product: easy; quotient: angle order matters (top – bottom).

  • Always reduce final angles to the 0^{\circ}!\le!\theta<360^{\circ} (or 0\le\theta<2\pi) range.

  • In root problems NEVER forget to divide the original principal angle by nn before adding multiples of 360n\tfrac{360^{\circ}}{n}.

  • Keep ii outside square-roots; writing ii\sqrt{\cdot} inside the radical is incorrect.

  • When converting rectangular → polar, match signs to pick the correct quadrant.

Real-World / Course Logistics Mentioned

  • Quiz 40 answer key posted on D2L (file B-12).

  • Test #3 scheduled for “tonight”.

  • Final exam: Tuesday the 11th.

  • Course evaluation earns up to 5 bonus points (submit after final for reliable credit).

  • Instructor catch-phrase: “multiplication is friendly, division is tricky”; “our best friend Jesus wants to live in your heart.”

Quick Reference Sheet

  • Modulus: r=a2+b2r=\sqrt{a^{2}+b^{2}}

  • Argument (deg): θ=atan2(b,a)  (adjust to quadrant)\theta=\operatorname{atan2}(b,a)\;(\text{adjust to quadrant})

  • Polar → Rectangular: x=rcosθ,  y=rsinθx=r\cos\theta,\;y=r\sin\theta

  • Product: r<em>1r</em>2,  θ<em>1+θ</em>2r<em>1r</em>2,\;\theta<em>1+\theta</em>2

  • Quotient: r<em>1r</em>2,  θ<em>1θ</em>2\tfrac{r<em>1}{r</em>2},\;\theta<em>1-\theta</em>2

  • Power: rn,  nθr^{n},\;n\theta

  • Roots (nn): rn,  θ+360kn  (k=0n1)\sqrt[n]{r},\;\tfrac{\theta+360k}{n}\;(k=0\dots n-1)

Practice, double-check your angle reductions, and you’ll avoid almost every arithmetic trap discussed in class!