Key Math Skills for Chemistry and Forensic Applications

Key Math Skills for Chemistry

  • Place Value Identification

    • Determining the place value of specific digits within numbers requires identifying position relative to the decimal point.
    • For the number 97.5689, the digit 5 is in the tenths place.
    • For the number 375.88, the digit 7 is in the tens place.
    • For the number 46.1000, the second 0 after the decimal point is in the hundredths place.
  • Evaluating Signed Numbers and Operations

    • Subtraction of a negative number is equivalent to adding its positive value:
      • 15−(−8)=15+8=2315 - (-8) = 15 + 8 = 23
    • Addition of two negative numbers yields a negative total:
      • −8+(−22)=−30-8 + (-22) = -30
    • Order of operations requires performing multiplication prior to addition:
      • 4×(−2)+6=−8+6=−24 \times (-2) + 6 = -8 + 6 = -2
    • Absolute value and signed operations:
      • −∣1∣−(−9)=−1+9=8-|1| - (-9) = -1 + 9 = 8
      • Alt notation solution: −11−(−9)=−2-11 - (-9) = -2
      • 34+(−55)=−2134 + (-55) = -21
    • Division involving a negative signed numerator:
      • −568=−7\frac{-56}{8} = -7
  • Solving Algebraic Equations for Variables

    • Solving for bb in linear single-variable equations:
      • Equation: 2b+7=b+102b + 7 = b + 10
        • Subtract bb from both sides: b+7=10b + 7 = 10
        • Subtract 7 from both sides: b=3b = 3
      • Equation: 3b−4=24−b3b - 4 = 24 - b
        • Add bb to both sides: 4b−4=244b - 4 = 24
        • Add 4 to both sides: 4b=284b = 28
        • Divide by 4: b=7b = 7
    • Solving for aa in linear single-variable equations:
      • Equation: 4a+4=404a + 4 = 40
        • Subtract 4 from both sides: 4a=364a = 36
        • Divide by 4: a=9a = 9
  • Clinical and Practical Percentage Calculations

    • Calculating percentage of patient flu shots:
      • A clinic has 25 patients on Friday morning, and 21 are given flu shots.
      • Percentage=(2125)×100=84%\text{Percentage} = \left(\frac{21}{25}\right) \times 100 = 84\%
      • Expressed to the ones place: 84%84\%
    • Calculating percentage of silver in an alloy:
      • An alloy contains 56 g56\,\text{g} of pure silver and 22 g22\,\text{g} of pure copper.
      • Total mass=56 g+22 g=78 g\text{Total mass} = 56\,\text{g} + 22\,\text{g} = 78\,\text{g}
      • Percentage silver=(56 g78 g)×100=71.79%≈72%\text{Percentage silver} = \left(\frac{56\,\text{g}}{78\,\text{g}}\right) \times 100 = 71.79\% \approx 72\%
      • Expressed to the ones place: 72%72\%
    • Calculating percentage of dimes in a coin collection:
      • A coin collection contains 11 nickels, 5 quarters, and 7 dimes.
      • Total coins=11+5+7=23\text{Total coins} = 11 + 5 + 7 = 23
      • Percentage dimes=(723)×100=30.43%≈30%\text{Percentage dimes} = \left(\frac{7}{23}\right) \times 100 = 30.43\% \approx 30\%
      • Expressed to the ones place: 30%30\%
    • Calculating percentage of male newborn babies:
      • 35 babies were born in May at a local hospital; 22 were boys.
      • Percentage boys=(2235)×100=62.86%≈63%\text{Percentage boys} = \left(\frac{22}{35}\right) \times 100 = 62.86\% \approx 63\%
      • Expressed to the ones place: 63%63\%
    • Calculating percentage of zinc in a metal alloy:
      • An alloy contains 67 g67\,\text{g} of pure gold and 35 g35\,\text{g} of pure zinc.
      • Total mass=67 g+35 g=102 g\text{Total mass} = 67\,\text{g} + 35\,\text{g} = 102\,\text{g}
      • Percentage zinc=(35 g102 g)×100=34.31%≈34%\text{Percentage zinc} = \left(\frac{35\,\text{g}}{102\,\text{g}}\right) \times 100 = 34.31\% \approx 34\%
      • Expressed to the ones place: 34%34\%
    • Calculating percentage of pennies in a collection:
      • A collection contains 15 pennies, 14 dimes, and 6 quarters.
      • Total coins=15+14+6=35\text{Total coins} = 15 + 14 + 6 = 35
      • Percentage pennies=(1535)×100=42.86%≈43%\text{Percentage pennies} = \left(\frac{15}{35}\right) \times 100 = 42.86\% \approx 43\%
      • Expressed to the ones place: 43%43\%

Graphical Analysis of Cooling and Post-Mortem Data

  • Graph Analysis: Temperature of Tea versus Time for Cooling

    • Title Significance: Indicates the relationship between the cooling temperature of tea and elapsed time.
    • Vertical Axis (Y-axis):
      • Measures: Temperature (∘C^\circ\text{C}).
      • Range of values: 0 to 80 ∘C0\,\text{to } 80\,^\circ\text{C}.
    • Horizontal Axis (X-axis):
      • Measures: Time (min).
      • Range of values: 0 to 100 min0\,\text{to } 100\,\text{min}.
    • Observed Trend: Temperature decreases as time increases.
    • Data Interpolation:
      • Temperature of tea after 20 min20\,\text{min}: Approximately 50 ∘C50\,^\circ\text{C}.
      • Time required to reach 45 ∘C45\,^\circ\text{C}: Approximately 38 min38\,\text{min}.
  • Graph Analysis: Post-Mortem Body Temperature versus Time

    • Title Significance: Displays post-mortem body temperature decline as time progresses following death.
    • Vertical Axis (Y-axis):
      • Measures: Post-Mortem Body Temperature (∘C^\circ\text{C}).
      • Range of values: 20 to 40 ∘C20\,\text{to } 40\,^\circ\text{C}.
    • Horizontal Axis (X-axis):
      • Measures: Time (hours) Since Death.
      • Range of values: 0 to 25 hours0\,\text{to } 25\,\text{hours}.
    • Observed Trend: Body temperature decreases over time following death.
    • Data Interpolation:
      • Time needed to reach a body temperature of 28 ∘C28\,^\circ\text{C}: 11.5 hours11.5\,\text{hours}.
  • Forensic Application: Estimating Time of Death

    • Case Scenario: Gloria's body temperature was measured by the coroner at 9 P.M. as 34 ∘C34\,^\circ\text{C}.
    • Determination using graph:
      • A body temperature of 34 ∘C34\,^\circ\text{C} corresponds to 5 hours5\,\text{hours} elapsed since death.
      • Calculation of time of death: 9 P.M.−5 hours=4 P.M.9\,\text{P.M.} - 5\,\text{hours} = 4\,\text{P.M.}

Writing and Comparing Numbers in Scientific Notation

  • Converting Standard Numbers to Scientific Notation

    • Numbers greater than 1 (positive exponent):
      • 55 000=5.5×10455\,000 = 5.5 \times 10^4
      • 480=4.8×102480 = 4.8 \times 10^2
      • 670 000=6.7×105670\,000 = 6.7 \times 10^5
      • 180 000 000=1.8×108180\,000\,000 = 1.8 \times 10^8
      • 750=7.5×102750 = 7.5 \times 10^2
      • 1500=1.5×1031500 = 1.5 \times 10^3
    • Numbers less than 1 (negative exponent):
      • 0.000 005=5×10−60.000\,005 = 5 \times 10^{-6}
      • 0.000 14=1.4×10−40.000\,14 = 1.4 \times 10^{-4}
      • 0.0072=7.2×10−30.0072 = 7.2 \times 10^{-3}
      • 0.000 06=6×10−50.000\,06 = 6 \times 10^{-5}
      • 0.15=1.5×10−10.15 = 1.5 \times 10^{-1}
      • 0.024=2.4×10−20.024 = 2.4 \times 10^{-2}
  • Comparing Magnitudes in Pairs of Numbers

    • Identifying the larger number in a pair:
      • Between 7.2×1037.2 \times 10^3 and 8.2×1038.2 \times 10^3: The larger number is 8.2×1038.2 \times 10^3.
      • Between 4.5×10−44.5 \times 10^{-4} and 3.2×10−23.2 \times 10^{-2}: The larger number is 3.2×10−23.2 \times 10^{-2}.
      • Between 1×1041 \times 10^4 and 1×10−41 \times 10^{-4}: The larger number is 1×1041 \times 10^4.
      • Between 0.000 5520.000\,552 (5.52×10−45.52 \times 10^{-4}) and 6.8×10−26.8 \times 10^{-2}: The larger number is 6.8×10−26.8 \times 10^{-2}.
    • Identifying the smaller number in a pair:
      • Between 4.9×10−34.9 \times 10^{-3} and 5.5×10−45.5 \times 10^{-4}: The smaller number is 5.5×10−45.5 \times 10^{-4}.
      • Between 12501250 (1.25×1031.25 \times 10^3) and 3.4×1023.4 \times 10^2 (340340): The smaller number is 3.4×1023.4 \times 10^2.
      • Between 0.000 000 40.000\,000\,4 (4.0×10−74.0 \times 10^{-7}) and 5.0×1025.0 \times 10^2: The smaller number is 0.000 000 40.000\,000\,4.
      • Between 2.50×10−22.50 \times 10^{-2} and 4×1054 \times 10^5: The smaller number is 2.50×10−22.50 \times 10^{-2}.

Clinical Update and Forensic Toxicology

  • Forensic Investigation Summary: Ethylene Glycol Poisoning

    • Forensic scientist Sarah conducted laboratory tests on victim blood samples and identified ethylene glycol.
    • Quantitative blood tests revealed that the victim had ingested 125 g125\,\text{g} of ethylene glycol.
    • Analysis of liquid from a glass at the crime scene confirmed ethylene glycol had been added to an alcoholic beverage.
    • Fingerprint evidence on the glass containing ethylene glycol matched the victim's husband.
    • A container of antifreeze found in the pantry/home matched the color of the liquid in the glass.
    • Combined physical and chemical evidence led to the arrest and conviction of the husband for poisoning his wife.
  • Chemical and Physical Properties of Ethylene Glycol

    • Appearance: Clear, thick liquid.
    • Taste: Sweet-tasting.
    • Odor: Odorless.
    • Solubility: Readily mixes with water.
    • Availability: Readily accessible due to common application as automobile antifreeze and brake fluid component.
  • Toxicology, Symptoms, and Treatment

    • Initial Symptoms: Mimic alcohol intoxication, leaving victims unaware of ingestion.
    • Systemic Toxicity: Causes central nervous system depression, cardiovascular damage, and renal (kidney) failure.
    • Medical Treatment: Hemodialysis can be performed to extract ethylene glycol from the bloodstream if detected early.
    • Toxicity Thresholds:
      • Toxic Threshold Ratio: 1.5 g1.5\,\text{g} of ethylene glycol per 1 kg1\,\text{kg} of body mass (1.5 g/kg1.5\,\text{g/kg}).
      • Fatal Dose Example: A dose of 75 g75\,\text{g} can be fatal for a 50-kg50\text{-kg} (110-lb110\text{-lb}) individual.
  • Categorization of Forensic Police Report Statements

    • Statement 1: "Gloria may have had a heart attack."
      • Classification: Hypothesis
    • Statement 2: "Test results indicate that Gloria was poisoned."
      • Classification: Conclusion
    • Statement 3: "The liquid in the glass was analyzed."
      • Classification: Experiment
    • Statement 4: "The antifreeze in the pantry was the same color as the liquid in the glass."
      • Classification: Observation
    • Statement 5: "Gloria may have committed suicide."
      • Classification: Hypothesis
    • Statement 6: "Sarah ran blood tests to identify any toxic substances."
      • Classification: Experiment
    • Statement 7: "The temperature of Gloria's body was 34 ∘C34\,^\circ\text{C}."
      • Classification: Observation
    • Statement 8: "The fingerprints found on the glass were determined to be her husband's."
      • Classification: Conclusion
  • Quantitative Forensic Calculations

    • Calculating Ethylene Glycol Percentage in Crime Scene Liquid:
      • A container found in the victim's home contained 120 g120\,\text{g} of ethylene glycol in 450 g450\,\text{g} of liquid.
      • Percentage=(120 g450 g)×100=26.67%≈27%\text{Percentage} = \left(\frac{120\,\text{g}}{450\,\text{g}}\right) \times 100 = 26.67\% \approx 27\%
      • Expressed to the ones place: 27%27\%
    • Calculating Fatal Percentage Threshold of Body Mass:
      • Toxic quantity is defined as 1.5 g1.5\,\text{g} of ethylene glycol per 1000 g1000\,\text{g} of body mass.
      • Fatal Percentage=(1.5 g1000 g)×100=0.15%\text{Fatal Percentage} = \left(\frac{1.5\,\text{g}}{1000\,\text{g}}\right) \times 100 = 0.15\%