Net Ionic Equations & Redox Reaction Types – Comprehensive Study Notes Overview of Net Ionic Equations and Redox Logic Key idea: Formation of ionic compounds and many other reactions is driven by electron transfer (oxidation–reduction), not merely the presence of ions in solution.Spectator ions: Ions that appear in the same form on both sides of a reaction. Removed to generate the net ionic equation (NIE) , which highlights only the chemical change. Rules for Writing Net Ionic Equations Aqueous species (aq) → dissociate into constituent ions.Solids (s), liquids (l), gases (g) → kept intact in the NIE.Procedure: Write the balanced molecular equation. Split all strong electrolytes (aq) into ions → complete ionic equation. Cancel spectator ions → net ionic equation. Example: Single-Displacement Reaction Molecular: Zn (s) + CuSO < e m > 4 ( a q ) → Cu (s) + ZnSO < / e m > 4 ( a q ) \text{Zn (s)} + \text{CuSO}<em>4\,(aq) \rightarrow \text{Cu (s)} + \text{ZnSO}</em>4\,(aq) Zn (s) + CuSO < e m > 4 ( a q ) → Cu (s) + ZnSO < / e m > 4 ( a q ) Complete ionic: Zn (s) + Cu 2 + ( a q ) + SO < e m > 4 2 − ( a q ) → Cu (s) + Zn 2 + ( a q ) + SO < / e m > 4 2 − ( a q ) \text{Zn (s)} + \text{Cu}^{2+}\,(aq) + \text{SO}<em>4^{2-}\,(aq) \rightarrow \text{Cu (s)} + \text{Zn}^{2+}\,(aq) + \text{SO}</em>4^{2-}\,(aq) Zn (s) + Cu 2 + ( a q ) + SO < e m > 4 2 − ( a q ) → Cu (s) + Zn 2 + ( a q ) + SO < / e m > 4 2 − ( a q ) Spectator: SO 4 2 − \text{SO}_4^{2-} SO 4 2 − Net ionic: Zn (s) + Cu 2 + ( a q ) → Cu (s) + Zn 2 + ( a q ) \text{Zn (s)} + \text{Cu}^{2+}\,(aq) \rightarrow \text{Cu (s)} + \text{Zn}^{2+}\,(aq) Zn (s) + Cu 2 + ( a q ) → Cu (s) + Zn 2 + ( a q ) Reaction Types Revisited Through a Redox Lens 1. Combination (Synthesis) Reactions General: A + B → A B A + B \rightarrow AB A + B → A B Example: H < e m > 2 ( g ) + F < / e m > 2 ( g ) → 2 HF ( a q ) \text{H}<em>2\,(g) + \text{F}</em>2\,(g) \rightarrow 2\,\text{HF}\,(aq) H < e m > 2 ( g ) + F < / e m > 2 ( g ) → 2 HF ( a q ) Oxidation numbers (ON): H : 0 → + 1 ; F : 0 → − 1 \text{H}:0 \rightarrow +1;\; \text{F}:0 \rightarrow -1 H : 0 → + 1 ; F : 0 → − 1 Half-reactions: H 2 → 2 H + + 2 e − \text{H}_2 \rightarrow 2\,\text{H}^+ + 2e^- H 2 → 2 H + + 2 e − (oxidation; H₂ = reducing agent)F 2 + 2 e − → 2 F − \text{F}_2 + 2e^- \rightarrow 2\,\text{F}^- F 2 + 2 e − → 2 F − (reduction; F₂ = oxidizing agent)Net ionic = molecular (no spectators): H < e m > 2 + F < / e m > 2 → 2 H + + 2 F − \text{H}<em>2 + \text{F}</em>2 \rightarrow 2\,\text{H}^+ + 2\,\text{F}^- H < e m > 2 + F < / e m > 2 → 2 H + + 2 F − 2. Decomposition Reactions General: A B → A + B AB \rightarrow A + B A B → A + B Example: ( NH < e m > 4 ) < / e m > 2 Cr < e m > 2 O < / e m > 7 ( a q ) → N < e m > 2 ( g ) + Cr < / e m > 2 O < e m > 3 ( s ) + 4 H < / e m > 2 O ( g ) (\text{NH}<em>4)</em>2\text{Cr}<em>2\text{O}</em>7\,(aq) \rightarrow \text{N}<em>2\,(g) + \text{Cr}</em>2\text{O}<em>3\,(s) + 4\,\text{H}</em>2\text{O}\,(g) ( NH < e m > 4 ) < / e m > 2 Cr < e m > 2 O < / e m > 7 ( a q ) → N < e m > 2 ( g ) + Cr < / e m > 2 O < e m > 3 ( s ) + 4 H < / e m > 2 O ( g ) ON changes: N : + 3 → 0 ; Cr : + 6 → + 3 \text{N}:+3 \rightarrow 0;\; \text{Cr}:+6 \rightarrow +3 N : + 3 → 0 ; Cr : + 6 → + 3 Half-reactions: 2 NH < e m > 4 + → N < / e m > 2 + 8 H + + 6 e − 2\,\text{NH}<em>4^+ \rightarrow \text{N}</em>2 + 8\,\text{H}^+ + 6e^- 2 NH < e m > 4 + → N < / e m > 2 + 8 H + + 6 e − Cr < e m > 2 O < / e m > 7 2 − + 8 H + + 6 e − → Cr < e m > 2 O < / e m > 3 + 4 H 2 O \text{Cr}<em>2\text{O}</em>7^{2-} + 8\,\text{H}^+ + 6e^- \rightarrow \text{Cr}<em>2\text{O}</em>3 + 4\,\text{H}_2\text{O} Cr < e m > 2 O < / e m > 7 2 − + 8 H + + 6 e − → Cr < e m > 2 O < / e m > 3 + 4 H 2 O Net ionic: 2 NH < e m > 4 + + Cr < / e m > 2 O < e m > 7 2 − → N < / e m > 2 + Cr < e m > 2 O < / e m > 3 + 4 H 2 O 2\,\text{NH}<em>4^+ + \text{Cr}</em>2\text{O}<em>7^{2-} \rightarrow \text{N}</em>2 + \text{Cr}<em>2\text{O}</em>3 + 4\,\text{H}_2\text{O} 2 NH < e m > 4 + + Cr < / e m > 2 O < e m > 7 2 − → N < / e m > 2 + Cr < e m > 2 O < / e m > 3 + 4 H 2 O No spectator ions. N acts as reducing agent; Cr as oxidizing agent. 3. Combustion Reactions Fuel (often hydrocarbon) + O < e m > 2 \text{O}<em>2 O < e m > 2 → CO < / e m > 2 + H 2 O \text{CO}</em>2 + \text{H}_2\text{O} CO < / e m > 2 + H 2 O (plus energy) Example: CH < e m > 4 ( g ) + 2 O < / e m > 2 ( g ) → CO < e m > 2 ( g ) + 2 H < / e m > 2 O ( l ) \text{CH}<em>4\,(g) + 2\,\text{O}</em>2\,(g) \rightarrow \text{CO}<em>2\,(g) + 2\,\text{H}</em>2\text{O}\,(l) CH < e m > 4 ( g ) + 2 O < / e m > 2 ( g ) → CO < e m > 2 ( g ) + 2 H < / e m > 2 O ( l ) ON changes: C : − 4 → + 4 ( o x i d a t i o n ) ; O : 0 → − 2 ( r e d u c t i o n ) \text{C}:-4 \rightarrow +4\;(oxidation);\; \text{O}:0 \rightarrow -2\;(reduction) C : − 4 → + 4 ( o x i d a t i o n ) ; O : 0 → − 2 ( re d u c t i o n ) Half-reactions (acidic medium shown): CH < e m > 4 + 2 H < / e m > 2 O → CO 2 + 8 H + + 8 e − \text{CH}<em>4 + 2\,\text{H}</em>2\text{O} \rightarrow \text{CO}_2 + 8\,\text{H}^+ + 8e^- CH < e m > 4 + 2 H < / e m > 2 O → CO 2 + 8 H + + 8 e − 2 O < e m > 2 + 8 H + + 8 e − → 4 H < / e m > 2 O 2\,\text{O}<em>2 + 8\,\text{H}^+ + 8e^- \rightarrow 4\,\text{H}</em>2\text{O} 2 O < e m > 2 + 8 H + + 8 e − → 4 H < / e m > 2 O Entire balanced equation is already the NIE (no aqueous ions, no spectators). General: A B + C D → A D + C B AB + CD \rightarrow AD + CB A B + C D → A D + CB (swap of counter-ions) Typically not redox because oxidation states stay the same. Molecular: AgNO < e m > 3 ( a q ) + HCl ( a q ) → HNO < / e m > 3 ( a q ) + AgCl ( s ) \text{AgNO}<em>3\,(aq) + \text{HCl}\,(aq) \rightarrow \text{HNO}</em>3\,(aq) + \text{AgCl}\,(s) AgNO < e m > 3 ( a q ) + HCl ( a q ) → HNO < / e m > 3 ( a q ) + AgCl ( s ) Spectators: NO 3 − \text{NO}_3^- NO 3 − and H + \text{H}^+ H + Net ionic: Ag + ( a q ) + Cl − ( a q ) → AgCl ( s ) \text{Ag}^+\,(aq) + \text{Cl}^-\,(aq) \rightarrow \text{AgCl}\,(s) Ag + ( a q ) + Cl − ( a q ) → AgCl ( s ) Example with all aqueous species (no NIE) NaNO < e m > 3 ( a q ) + HCl ( a q ) → HNO < / e m > 3 ( a q ) + NaCl ( a q ) \text{NaNO}<em>3\,(aq) + \text{HCl}\,(aq) \rightarrow \text{HNO}</em>3\,(aq) + \text{NaCl}\,(aq) NaNO < e m > 3 ( a q ) + HCl ( a q ) → HNO < / e m > 3 ( a q ) + NaCl ( a q ) Complete ionic shows every ion on both sides → no net reaction . 5. Disproportionation (Dismutation) Reactions Definition: The same element is simultaneously oxidized and reduced.Catalase Reaction (biological) 2 H < e m > 2 O < / e m > 2 ( a q ) → catalase 2 H < e m > 2 O ( l ) + O < / e m > 2 ( g ) 2\,\text{H}<em>2\text{O}</em>2\,(aq) \xrightarrow{\text{catalase}} 2\,\text{H}<em>2\text{O}\,(l) + \text{O}</em>2\,(g) 2 H < e m > 2 O < / e m > 2 ( a q ) catalase 2 H < e m > 2 O ( l ) + O < / e m > 2 ( g ) ON of O: − 1 → − 2 -1 \rightarrow -2 − 1 → − 2 (reduction in H₂O) and − 1 → 0 -1 \rightarrow 0 − 1 → 0 (oxidation in O₂). Protects cells from reactive oxygen species (ROS). Superoxide Dismutase (SOD) 2 O < e m > 2 ∙ − + 2 H + → H < / e m > 2 O < e m > 2 + O < / e m > 2 2\,\text{O}<em>2^{\bullet-} + 2\,\text{H}^+ \rightarrow \text{H}</em>2\text{O}<em>2 + \text{O}</em>2 2 O < e m > 2 ∙− + 2 H + → H < / e m > 2 O < e m > 2 + O < / e m > 2 ON of O in O 2 ∙ − : − 1 2 \text{O}_2^{\bullet-}: -\tfrac{1}{2} O 2 ∙− : − 2 1 → − 1 -1 − 1 in peroxide (reduction) and 0 0 0 in O₂ (oxidation). Enzyme cofactors: Commonly Cu, Zn; metals cycle between ONs to shuttle electrons.Oxidation–Reduction Titrations Purpose: Quantify an unknown via controlled electron transfer; equivalence is detected by potential (E) rather than pH.Indicators: Change color at defined voltages.Bipyridine complexes, diphenylamine, sulfonin, etc. (voltages ≈ + 1 V , + 0.76 V , + 0.24 / − 0.29 V \approx +1\,\text{V}, +0.76\,\text{V}, +0.24/-0.29\,\text{V} ≈ + 1 V , + 0.76 V , + 0.24/ − 0.29 V respectively) Potentiometric titration: Measures voltage continuously with a voltmeter; no color indicator needed (analogous to pH meter setups).Iodometric / Iodimetric Titration (Classic Lab Example) Concept: Free iodine forms a deep blue complex with starch; disappearance of color marks endpoint.Stepwise mechanism used in lab standardization Generation of triiodide IO < e m > 3 − + 8 I − + 6 H + → 3 I < / e m > 3 − + 3 H 2 O \text{IO}<em>3^- + 8\,\text{I}^- + 6\,\text{H}^+ \rightarrow 3\,\text{I}</em>3^- + 3\,\text{H}_2\text{O} IO < e m > 3 − + 8 I − + 6 H + → 3 I < / e m > 3 − + 3 H 2 O Titration with thiosulfate I < e m > 3 − + 2 S < / e m > 2 O < e m > 3 2 − → 3 I − + S < / e m > 4 O 6 2 − \text{I}<em>3^- + 2\,\text{S}</em>2\text{O}<em>3^{2-} \rightarrow 3\,\text{I}^- + \text{S}</em>4\text{O}_6^{2-} I < e m > 3 − + 2 S < / e m > 2 O < e m > 3 2 − → 3 I − + S < / e m > 4 O 6 2 − Stoichiometry: 6 S < e m > 2 O < / e m > 3 2 − : 1 IO 3 − 6\,\text{S}<em>2\text{O}</em>3^{2-} : 1\,\text{IO}_3^- 6 S < e m > 2 O < / e m > 3 2 − : 1 IO 3 − overall.Sample Calculation (from transcript) Given:50 mL 50\,\text{mL} 50 mL of 0.010 M KIO 3 0.010\,\text{M}\,\text{KIO}_3 0.010 M KIO 3 32 mL 32\,\text{mL} 32 mL of Na < e m > 2 S < / e m > 2 O 3 \text{Na}<em>2\text{S}</em>2\text{O}_3 Na < e m > 2 S < / e m > 2 O 3 used to reach equivalence. Moles IO 3 − \text{IO}_3^- IO 3 − :n = 0.010 mol/L × 0.050 L = 5.0 × 10 − 4 mol n = 0.010\,\text{mol/L} \times 0.050\,\text{L} = 5.0\times10^{-4}\,\text{mol} n = 0.010 mol/L × 0.050 L = 5.0 × 1 0 − 4 mol Moles S < e m > 2 O < / e m > 3 2 − \text{S}<em>2\text{O}</em>3^{2-} S < e m > 2 O < / e m > 3 2 − needed:n = 5.0 × 10 − 4 mol × 6 = 3.0 × 10 − 3 mol n = 5.0\times10^{-4}\,\text{mol} \times 6 = 3.0\times10^{-3}\,\text{mol} n = 5.0 × 1 0 − 4 mol × 6 = 3.0 × 1 0 − 3 mol Molarity M thiosulfate M_{\text{thiosulfate}} M thiosulfate :M = 3.0 × 10 − 3 mol 0.032 L ≈ 0.094 M M = \frac{3.0\times10^{-3}\,\text{mol}}{0.032\,\text{L}} \approx 0.094\,\text{M} M = 0.032 L 3.0 × 1 0 − 3 mol ≈ 0.094 M Endpoint detection: First, iodine color fades (I₃⁻ consumed). Starch added → deep blue; continues titration until solution goes colorless. Practical / Biological Significance & Connections Redox underlies cellular respiration, photosynthesis, detoxification of ROS, metabolic & immune function . Enzyme-bound metals (Cu, Zn, Fe, Mn) facilitate biological redox by alternating oxidation states, mirroring lab electron shuttles. Mastery of oxidation numbers, half-reaction balancing, Stoichiometric relationships, and NIEs is foundational for:Electrochemical cells (next chapter). Organic oxidation/reduction (carbonyl chemistry, etc.). Biochemical pathways (electron transport chain, oxidative stress response). Clinical relevance: Defects in redox enzymes → mitochondrial diseases, immune deficiencies, oxidative-stress disorders.Key Take-Home Procedures & Equations Assigning Oxidation Numbers: Free element = 0. Monatomic ion = its charge. Group-I/II metals = + 1 , + 2 +1, +2 + 1 , + 2 respectively in compounds. Hydrogen = + 1 +1 + 1 (non-metals) or − 1 -1 − 1 (metals). Oxygen = − 2 -2 − 2 (except peroxides − 1 -1 − 1 ; superoxides − 1 2 -\tfrac{1}{2} − 2 1 ). Halogens = − 1 -1 − 1 unless with O or higher electronegative atom. Balancing Redox (acidic medium): Split into half-reactions. Balance atoms other than O & H. Balance O with H 2 O \text{H}_2\text{O} H 2 O , H with H + \text{H}^+ H + . Balance charge with electrons. Equalize electrons & recombine. (Basic medium) neutralize H + \text{H}^+ H + with OH − \text{OH}^- OH − → water. Nernst-style link: Voltage at equivalence in potentiometric titrations relates to the Nernst equation E = E ∘ − 0.0592 n log Q E = E^\circ - \frac{0.0592}{n}\log Q E = E ∘ − n 0.0592 log Q (conceptual recall for MCAT).Bottom line: Accurate net ionic equations reveal the essential electron flow in reactions and set the stage for quantitative techniques (titrations, electrochemistry) and biological energy transformations.