Algebra 2: 6.1 - Review Notes

Exponential Growth and Decay

  • Definition of Exponential Functions: An exponential function can represent either growth or decay based on its form.   - Exponential Growth: The function has a positive base greater than 1.   - Exponential Decay: The function has a base between 0 and 1.

Examples
  1. Function Analysis: Determine if functions represent growth or decay.    - Example: y=5imese0.7xy = 5 imes e^{0.7x} \      - Analysis: This represents exponential growth since the base (e^{0.7}) > 1.    - Example: y=3imes(0.5)xy = 3 imes (0.5)^x \      - Analysis: This represents exponential decay since the base (0.5) < 1.

Compound Interest Calculation

  • When money is deposited, it earns interest, which may be compounded at different frequencies.

  • Formula for Compound Interest: A=Pimes(1+racrn)ntA = P imes \bigg(1 + rac{r}{n}\bigg)^{nt}   - Where:     - AA = the amount of money accumulated after n years, including interest.     - PP = principal amount (the initial amount of money).     - rr = annual interest rate (decimal).     - nn = number of times that interest is compounded per year.     - tt = number of years the money is invested or borrowed.

Application Example
  • You deposit $6,000 into an account at an interest rate of 3.25%.

a. Compounding Monthly
  • Parameters: P=6000,r=0.0325,n=12,t=8P = 6000, r = 0.0325, n = 12, t = 8

  • Formula: A=6000imes(1+rac0.032512)12imes8A = 6000 imes \bigg(1 + rac{0.0325}{12}\bigg)^{12 imes 8}

b. Compounding Quarterly
  • Parameters: n=4n = 4

  • Formula: A=6000imes(1+rac0.03254)4imes8A = 6000 imes \bigg(1 + rac{0.0325}{4}\bigg)^{4 imes 8}

c. Compounding Daily
  • Parameters: n=365n = 365

  • Formula: A=6000imes(1+rac0.0325365)365imes8A = 6000 imes \bigg(1 + rac{0.0325}{365}\bigg)^{365 imes 8}

d. Compounding Continuously
  • Formula: A=PertA = Pe^{rt}

  • Substituting Values: A=6000imese0.0325imes8A = 6000 imes e^{0.0325 imes 8}

Depreciation of Asset Value

  • Depreciation Formula: A=Pimes(1r)tA = P imes (1 - r)^t   - Where:     - AA = value after t years.     - PP = initial value.     - rr = rate of depreciation (as a decimal).     - tt = number of years.

Application Example
  • You bought a boat for $120,000 with a depreciation rate of 8.5%.

  • Formula: A=120000imes(10.085)5A = 120000 imes (1 - 0.085)^5

Value of a Rare Coin

  • The value of the rare coin is described by the function: Y=0.25(1.06)tY = 0.25(1.06)^t   - Where:     - YY = value of the coin in dollars.     - tt = number of years since minted.

Analysis
  1. Growth or Decay: The model represents exponential growth since the base (1.06) > 1.

  2. Annual Percent Increase: The annual percent increase is 6% (derived from (1.06 - 1) imes 100).

  3. Original Value: The original value of the coin is 0.250.25 dollars (when t = 0).

  4. Estimate Future Value: To find when the coin's value will be 0.600.60, set up the equation:    - 0.60=0.25(1.06)t0.60 = 0.25(1.06)^t    - Solve for tt.

Simplifying Expressions with Exponential Components

  • Examples of simplifying exponential expressions include:   1. e4imese1ightarrowe41=e3e^4 imes e^{-1} ightarrow e^{4-1} = e^3   2. (2e3x)5ightarrow25imese15x=32e15x(2e^{3x})^5 ightarrow 2^5 imes e^{15x} = 32e^{15x}   3. e3imese8ightarrowe5e^{-3} imes e^{8} ightarrow e^{5}   4. 12e5imes4e2ightarrow(12imes4)e5+2=48e712e^5 imes 4e^{2} ightarrow (12 imes 4)e^{5+2} = 48e^{7}    

  • Operations involving multiple exponentials also involve adding exponents with like bases and applying multiplication rules.