Methods of Integration: High-Frequency Solved Exercises
This text presents a collection of 35 solved exercises from the "Higher Education EXTRA-MATH SERIES" authored by Hussein Raad.
The exercises focus on fundamental and advanced methods of integration, including linear substitution, substitution for transcendental functions, and integration by parts.
Power Rule and Linear Substitution Exercises
Exercise 1: ∫(2x+1)3dx
- Features a linear radical function where substitution u=2x+1 is applicable.
Exercise 2: ∫(3−2x)54dx
- Involves a reciprocal power of a linear expression; utilizes the rule ∫(ax+b)ndx=a(n+1)(ax+b)n+1+C.
Exercise 3: ∫2xx2−1dx
- A basic substitution case where u=x2−1 and du=2xdx.
Exercise 5: ∫3x2x3+4dx
- Demonstrates the substitution u=x3+4, where the outer factor 3x2 matches the derivative of the inner function.
Exercise 14: ∫x2(x1+1)43dx
- A multi-step algebraic substitution where u=x1+1 leads to du=−x21dx.
Exercise 23: ∫x+1dx
- Rationalization or substitution with u=x is required.
Exercise 24: ∫1−xxdx
- Solved via algebraic manipulation (adding and subtracting 1 in the numerator) or substitution u=1−x.
Exercise 26: ∫4+x2x3dx
- Requires algebraic long division or the substitution u=4+x2.
Transcendental Function Substitution: Trigonometric and Hyperbolic
Exercise 4: ∫(x+2)sin(x2+4x−6)dx
- The derivative of the inner quadratic function x2+4x−6 is 2x+4, which is a multiple of the outer factor (x+2).
Exercise 6: ∫xcot(ln(x))dx
- Substitution u=ln(x). Transforms the integral into the standard form ∫cot(u)du.
Exercise 11: ∫xcos(x+3)dx
- Uses u=x+3; note that du=2x1dx.
Exercise 12: ∫xtan(x)dx
- Similar to Exercise 11, focusing on the tangent function.
Exercise 13: ∫2−xtanh(21−x)dx
- A complex substitution involving exponential bases and hyperbolic functions. Often requires u=21−x.
Exercise 15: ∫exsin(ex)dx
- Direct substitution of the exponential inner function: u=ex.
Exercise 18: ∫2sec2(4x)dx
- Direct application of the integral of sec2(ax).
Exercise 34: ∫xtan(x2)sec(x2)dx
- Uses u=x2, resulting in the standard integral of sec(u)tan(u), which is sec(u)+C.
Exercise 35: ∫sin(x)cos(x)dx
- Can be solved using trigonometric identities (e.g., multiplying by sec2(x)sec2(x) or using the double angle identity sin(2x)=2sin(x)cos(x)).
Exponential and Logarithmic Integration
Exercise 7: ∫x2ex3dx
- Chain rule inverse with u=x3.
Exercise 8: ∫eex+xdx
- Relies on the property ea+b=eaeb. The expression simplifies to ∫eexexdx, allowing for u=ex.
Exercise 9: ∫1+exexdx
- Results in the natural log form ln∣1+ex∣+C.
Exercise 10: ∫xexdx
- Substitution u=x.
Exercise 21: ∫ex−x2ex−2xdx
- A logarithmic form integral where the numerator is the derivative of the denominator: dxd(ex−x2)=ex−2x.
Exercise 27: ∫1+e2xexdx
- Leads to the arctangent form arctan(ex)+C by substituting u=ex.
Exercise 28: ∫ln(x1)dx
- Simplified using log properties as ∫−ln(x)dx, then integrated by parts.
Exercise 29: ∫xln2(x)3dx
- Substitution u=ln(x) transforms this into a power rule integral ∫3u−2du.
Exercise 33: ∫xln(x)dx
- Substitution u=ln(x).
Advanced Techniques: Integration by Parts
Exercise 16: ∫(3x+2)exdx
- Let u=3x+2 and dv=exdx.
Exercise 17: ∫xe−2xdx
- Let u=x and dv=e−2xdx.
Exercise 19: ∫(2x−1)cos(x)dx
- Let u=2x−1 and dv=cos(x)dx.
Exercise 20: ∫(1−x)sin(x)dx
- Let u=1−x and dv=sin(x)dx.
Exercise 30: ∫ln(x)dx
- Standard entry-level integration by parts where u=ln(x) and dv=dx.
Exercise 31: ∫xln(x)dx
- Part of the logarithmic series; let u=ln(x) and dv=xdx.
Exercise 32: ∫x2ln(x)dx
- Let u=ln(x) and dv=x−2dx.
Inverse Trigonometric Forms
Exercise 22: ∫1+x4xdx
- Substitution u=x2 converts this to the form ∫1+u21du, leading to 21arctan(x2)+C.
Exercise 25: ∫1−x2arcsin(x)dx
- Substitution u=arcsin(x) simplifies the expression significantly as du=1−x21dx.