Methods of Integration Solved Exercises

Methods of Integration: High-Frequency Solved Exercises

  • This text presents a collection of 35 solved exercises from the "Higher Education EXTRA-MATH SERIES" authored by Hussein Raad.
  • The exercises focus on fundamental and advanced methods of integration, including linear substitution, substitution for transcendental functions, and integration by parts.

Power Rule and Linear Substitution Exercises

  • Exercise 1: (2x+1)3dx\int \sqrt{(2x+1)^3} \,dx     - Features a linear radical function where substitution u=2x+1u = 2x + 1 is applicable.
  • Exercise 2: 4(32x)5dx\int \frac{4}{(3-2x)^5} \,dx     - Involves a reciprocal power of a linear expression; utilizes the rule (ax+b)ndx=(ax+b)n+1a(n+1)+C\int (ax+b)^n \,dx = \frac{(ax+b)^{n+1}}{a(n+1)} + C.
  • Exercise 3: 2xx21dx\int 2x \sqrt{x^2-1} \,dx     - A basic substitution case where u=x21u = x^2 - 1 and du=2xdxdu = 2x \,dx.
  • Exercise 5: 3x2x3+4dx\int 3x^2 \sqrt{x^3+4} \,dx     - Demonstrates the substitution u=x3+4u = x^3 + 4, where the outer factor 3x23x^2 matches the derivative of the inner function.
  • Exercise 14: 3x2(1x+1)4dx\int \frac{3}{x^2(\frac{1}{x}+1)^4} \,dx     - A multi-step algebraic substitution where u=1x+1u = \frac{1}{x} + 1 leads to du=1x2dxdu = -\frac{1}{x^2} \,dx.
  • Exercise 23: dxx+1\int \frac{dx}{\sqrt{x}+1}     - Rationalization or substitution with u=xu = \sqrt{x} is required.
  • Exercise 24: x1xdx\int \frac{x}{1-x} \,dx     - Solved via algebraic manipulation (adding and subtracting 1 in the numerator) or substitution u=1xu = 1-x.
  • Exercise 26: x34+x2dx\int \frac{x^3}{4+x^2} \,dx     - Requires algebraic long division or the substitution u=4+x2u = 4+x^2.

Transcendental Function Substitution: Trigonometric and Hyperbolic

  • Exercise 4: (x+2)sin(x2+4x6)dx\int (x+2) \sin(x^2 + 4x - 6) \,dx     - The derivative of the inner quadratic function x2+4x6x^2 + 4x - 6 is 2x+42x + 4, which is a multiple of the outer factor (x+2)(x+2).
  • Exercise 6: cot(ln(x))xdx\int \frac{\cot(\ln(x))}{x} \,dx     - Substitution u=ln(x)u = \ln(x). Transforms the integral into the standard form cot(u)du\int \cot(u) \,du.
  • Exercise 11: cos(x+3)xdx\int \frac{\cos(\sqrt{x}+3)}{\sqrt{x}} \,dx     - Uses u=x+3u = \sqrt{x}+3; note that du=12xdxdu = \frac{1}{2\sqrt{x}} \,dx.
  • Exercise 12: tan(x)xdx\int \frac{\tan(\sqrt{x})}{\sqrt{x}} \,dx     - Similar to Exercise 11, focusing on the tangent function.
  • Exercise 13: 2xtanh(21x)dx\int 2^{-x} \tanh(2^{1-x}) \,dx     - A complex substitution involving exponential bases and hyperbolic functions. Often requires u=21xu = 2^{1-x}.
  • Exercise 15: exsin(ex)dx\int e^x \sin(e^x) \,dx     - Direct substitution of the exponential inner function: u=exu = e^x.
  • Exercise 18: 2sec2(4x)dx\int 2 \sec^2(4x) \,dx     - Direct application of the integral of sec2(ax)\sec^2(ax).
  • Exercise 34: xtan(x2)sec(x2)dx\int x \tan(x^2) \sec(x^2) \,dx     - Uses u=x2u = x^2, resulting in the standard integral of sec(u)tan(u)\sec(u)\tan(u), which is sec(u)+C\sec(u) + C.
  • Exercise 35: dxsin(x)cos(x)\int \frac{dx}{\sin(x) \cos(x)}     - Can be solved using trigonometric identities (e.g., multiplying by sec2(x)sec2(x)\frac{\sec^2(x)}{\sec^2(x)} or using the double angle identity sin(2x)=2sin(x)cos(x)\sin(2x) = 2 \sin(x) \cos(x)).

Exponential and Logarithmic Integration

  • Exercise 7: x2ex3dx\int x^2 e^{x^3} \,dx     - Chain rule inverse with u=x3u = x^3.
  • Exercise 8: eex+xdx\int e^{e^x+x} \,dx     - Relies on the property ea+b=eaebe^{a+b} = e^a e^b. The expression simplifies to eexexdx\int e^{e^x} e^x \,dx, allowing for u=exu = e^x.
  • Exercise 9: ex1+exdx\int \frac{e^x}{1+e^x} \,dx     - Results in the natural log form ln1+ex+C\ln|1+e^x| + C.
  • Exercise 10: exxdx\int \frac{e^{\sqrt{x}}}{\sqrt{x}} \,dx     - Substitution u=xu = \sqrt{x}.
  • Exercise 21: ex2xexx2dx\int \frac{e^x-2x}{e^x-x^2} \,dx     - A logarithmic form integral where the numerator is the derivative of the denominator: ddx(exx2)=ex2x\frac{d}{dx}(e^x - x^2) = e^x - 2x.
  • Exercise 27: ex1+e2xdx\int \frac{e^x}{1+e^{2x}} \,dx     - Leads to the arctangent form arctan(ex)+C\arctan(e^x) + C by substituting u=exu = e^x.
  • Exercise 28: ln(1x)dx\int \ln\left(\frac{1}{x}\right) \,dx     - Simplified using log properties as ln(x)dx\int -\ln(x) \,dx, then integrated by parts.
  • Exercise 29: 3xln2(x)dx\int \frac{3}{x \ln^2(x)} \,dx     - Substitution u=ln(x)u = \ln(x) transforms this into a power rule integral 3u2du\int 3 u^{-2} \,du.
  • Exercise 33: ln(x)xdx\int \frac{\sqrt{\ln(x)}}{x} \,dx     - Substitution u=ln(x)u = \ln(x).

Advanced Techniques: Integration by Parts

  • Exercise 16: (3x+2)exdx\int (3x+2) e^x \,dx     - Let u=3x+2u = 3x+2 and dv=exdxdv = e^x \,dx.
  • Exercise 17: xe2xdx\int x e^{-2x} \,dx     - Let u=xu = x and dv=e2xdxdv = e^{-2x} \,dx.
  • Exercise 19: (2x1)cos(x)dx\int (2x-1) \cos(x) \,dx     - Let u=2x1u = 2x-1 and dv=cos(x)dxdv = \cos(x) \,dx.
  • Exercise 20: (1x)sin(x)dx\int (1-x) \sin(x) \,dx     - Let u=1xu = 1-x and dv=sin(x)dxdv = \sin(x) \,dx.
  • Exercise 30: ln(x)dx\int \ln(x) \,dx     - Standard entry-level integration by parts where u=ln(x)u = \ln(x) and dv=dxdv = dx.
  • Exercise 31: xln(x)dx\int x \ln(x) \,dx     - Part of the logarithmic series; let u=ln(x)u = \ln(x) and dv=xdxdv = x \,dx.
  • Exercise 32: ln(x)x2dx\int \frac{\ln(x)}{x^2} \,dx     - Let u=ln(x)u = \ln(x) and dv=x2dxdv = x^{-2} \,dx.

Inverse Trigonometric Forms

  • Exercise 22: x1+x4dx\int \frac{x}{1+x^4} \,dx     - Substitution u=x2u = x^2 converts this to the form 11+u2du\int \frac{1}{1+u^2} \,du, leading to 12arctan(x2)+C\frac{1}{2}\arctan(x^2) + C.
  • Exercise 25: arcsin(x)1x2dx\int \frac{\arcsin(x)}{\sqrt{1-x^2}} \,dx     - Substitution u=arcsin(x)u = \arcsin(x) simplifies the expression significantly as du=11x2dxdu = \frac{1}{\sqrt{1-x^2}} \,dx.