Lecture 5 Vectors
1. Vectors in Mechanics
1.1 Velocity Vector
Definition: Velocity vector, denoted as v = dr/dt, describes the instantaneous direction of motion and the rate of change of position.
Example:
If r(t) = (1 + t)ˆı + 2tˆȷ + 3tˆk,
For t = -1: r(-1) = -2ˆȷ - 3ˆk
For t = 0: r(0) = ˆı
For t = 1: r(1) = 2ˆı + 2ˆȷ + 3ˆk
For t = 2: r(2) = 3ˆı + 4ˆȷ + 6ˆk
1.2 Calculating Velocity
Calculation: v = dr/dt = (0 + 1)ˆı + (2)ˆȷ + (3)ˆk = ˆı + 2ˆȷ + 3ˆk
Note: Velocity is independent of time; hence, the tangent vector remains constant along the path indicating motion along a line.
1.3 Non-constant Velocity Example
Example: For r(t) = tˆı + (t^2/2)ˆȷ + ˆk,
Velocity is v = dr/dt = (1)ˆı + (t)ˆȷ + (0)ˆk = ˆı + tˆȷ.
2. Acceleration Vector
2.1 Definition
Acceleration vector is the rate of change of velocity with respect to time: a = dv/dt.
2.2 Example of Acceleration
If v = ˆı + tˆȷ,
Then, a = dv/dt = ˆȷ.
Notation:
a = dv/dt = d²r/dt² (second derivative of r with respect to time).
Shorthand: v = ˙r, a = ˙v = ¨r, where • indicates a time derivative.
3. Vector Equation of a Line
3.1 Constant Velocity
Equation: If a particle moves with constant velocity ˙r = u = u1ˆı + u2ˆȷ + u3ˆk:
ẋ = u1 (constant),
ẏ = u2 (constant),
ż = u3 (constant).
Parametric form:
x = u1t + C (where C is a constant).
If r = r0 at t = 0, then:
x = x0 + u1t.
3.2 Vector Representation
Complete Equation: r = r0 + tu (vector equation of a line through r0 in the direction of u).
4. Comparison with Standard Line Description
4.1 Description in XY Plane
Given initial point r0 and velocity u:
x = x0 + u1t
y = y0 + u2t
From this, we can derive the standard form:
y − y0 = (u2/u1)(x − x0) (standard equation of a line).
Angles:
If u1 = 0, then ϕ = 90°; if u2 = 0, then ϕ = 0°.
5. Example of Line Equations
5.1 Line through a Point
Example: For a line through (1, 4, -1) in direction of ˆı - 3ˆk:
r = (1 + t)ˆı + 4ˆȷ - (1 + 3t)ˆk.
5.2 Line through Two Points
Example: For points (-1, 0, 2) and (2, 1, 3):
r0 = -ˆı + 2ˆk, r1 = 2ˆı + ˆȷ + 3ˆk.
Direction: r1 - r0 = 3ˆı + ˆȷ + ˆk
Line equation: r = -ˆı + 2ˆk + t(3ˆı + ˆȷ + ˆk).
Verification: r(0) = r0, r(1) = r1 (correct).
6. Newton’s Laws in Two or Three Dimensions
6.1 Newton’s Second Law
Statement: The acceleration produced by a force is proportional to that force.
Formula: F = ma (F is the total force vector).
Multiple Forces: Total force from several acting forces is given by:
F = F1 + F2 + ...
In component form, add their components.
6.2 Example of Forces
Example: Given forces F1 = ˆı + ˆȷ, F2 = -2ˆı + ˆk, and F3 = ˆȷ - ˆk:
Total force: F = (1 - 2 + 0)ˆı + (1 + 0 + 1)ˆȷ + (0 + 1 - 1)ˆk = -ˆı + 2ˆȷ.
6.3 Newton’s First Law
Statement: F = 0 implies a = 0; therefore, v is constant (v = u, the initial velocity).
Equation of Motion: r(t) = r0 + tu (particle moves with constant velocity in absence of force).