marek

Physics - Equations of Motion

Key Equation

  • The equation for uniformly accelerated motion is given by: V2=u2+2asV^2 = u^2 + 2as where:

    • VV = final velocity

    • uu = initial velocity

    • aa = acceleration

    • ss = displacement

Example Calculation

  • Given:

    • Initial velocity, u=36extm/su = 36 ext{ m/s}

    • Acceleration, a=105extm/s2a = 105 ext{ m/s}^2

  • Plugging the values into the equation:

    • V2=(36)2+2imes105imessV^2 = (36)^2 + 2 imes 105 imes s

Solving for Displacement (s)
  • From the context, we can assume a scenario where the total displacement is calculated or related to the energy or work done:

    • If substituting values, such as 2500 for total energy or final states:

    • The equation can be structured as: 2500=900+20s2500 = 900 + 20s where

      • 900 represents kinetic energy or some initial state value

      • 20 being another constant in the context of this equation.

  • Rearranging the equation to find ss:

    • 2500−900=20s2500 - 900 = 20s

    • 1600=20s1600 = 20s

    • Dividing both sides by 20 gives:
      s=rac160020=80extms = rac{1600}{20} = 80 ext{ m}

Conclusion

  • In this specific instance, if we used the listed math properly and correctly identified initial parameters and transformations, we could solve for (s) yielding:

    • s=80extms = 80 ext{ m}

  • Clearly highlight how these equations interrelate, especially in problems involving kinematics and energy calculations.