Unit 3 Study Guide: Pre-Linear Algebra, Equations, and Inequalities

Unit 3: Pre-Linear Algebra – Competences and Outline

  • Key Competence: By the conclusion of this unit, students should possess the ability to solve mathematical problems involving linear equations and inequalities, including the ability to represent these solutions graphically.
  • Core Unit Outline:
    • Linear functions
    • Equations
    • Inequalities

3.1 Linear Functions: Definitions and Forms

  • Definition of a Linear Function: A linear function describes a specific relationship between two variables (conventionally denoted as xx and yy) such that their graphical representation is a straight line.
  • Standard Equation Form: A linear function is expressed in the form y=mx+cy = mx + c.
    • mm: Represents the slope or gradient of the line.
    • cc: Represents the yy-intercept.
    • Both mm and cc function as constants.
  • General Examples:
    • y=x+1y = x + 1
    • y=2x3y = 2x - 3
    • y=3x+4y = -3x + 4
  • Special Cases:
    • Horizontal Lines: Occur when the value of yy is constant, expressed as y=cy = c. Examples provided include y=3y = 3 and y=32y = -\frac{3}{2}.
    • Vertical Lines: Graphical representations where the xx value remains constant, such as x=32x = \frac{3}{2} and x=2x = -2.

3.1.1 - 3.1.2 The Foundation: The Number Line

  • Role of the Number Line: It serves as a tool for locating and comparing rational numbers relative to a central point, zero (00).
  • Structure and Directions:
    • Origin: The point represented by the number 00.
    • Positive Numbers: Situated to the right of zero.
    • Negative Numbers: Situated to the left of zero.
  • Coordinates on a Line: Every point on a number line corresponds to a single number representing its distance and direction from the origin. This value is called the coordinate.
    • Verbatim Examples from Figure 3:
      • Point AA is 44 units to the right; represented as A(4)A(4).
      • Point BB is 33 units to the left; represented as B(3)B(-3).
      • Point CC is at 12\frac{1}{2}; represented as C(12)C(\frac{1}{2}).
      • Point DD is at 5-5; represented as D(5)D(-5).

3.1.3 Spatial Positioning: Points on a Plane Surface

  • Requirement for Localization: Placing a point on a flat plane requires two numbers (an ordered pair) rather than one, indicating position relative to a reference system.
  • The Ordered Pair Concept:
    • Expressed as (x,y)(x, y).
    • The first number denotes the horizontal position (e.g., a column).
    • The second number denotes the vertical position (e.g., a row).
  • Importance of Sequence: The order is critical because (3,5)(5,3)(3, 5) \neq (5, 3).
  • Desk Arrangement Metaphor: In a classroom grid, a shaded desk in the third column and fifth row is identified by the ordered pair (3,5)(3, 5).

3.1.4 - 3.1.5 Drawing and Labeling Axes

  • Reference System: To locate points accurately, two perpendicular lines are used: one horizontal and one vertical. They meet at a point called the Origin, denoted as OO.
  • Standard Tools: A standard grid system (e.g., 1cm1\,cm squares) known as graph paper is used for accurate representation.
  • Extension of Directions: A full coordinate system includes both positive and negative directions for both axes.
  • Mathematical Classification of Lines:
    • Vertical Lines: Exist in the form x=constantx = \text{constant}. They maintain a fixed distance from the vertical axis and are perpendicular to the horizontal axis.
    • Horizontal Lines: Exist in the form y=constanty = \text{constant}. They are parallel to the horizontal axis and perpendicular to the vertical axis.

3.1.6 The Cartesian Plane

  • Definition: A two-dimensional coordinate system formed by two perpendicular axes.
    • x-axis: The horizontal number line.
    • y-axis: The vertical number line.
  • The Origin: The intersection of the two axes, denoted as O(0,0)O(0, 0).
  • Quadrants: The axes divide the surface into four distinct regions.
  • Interpreting Coordinates:
    • Starting from O(0,0)O(0, 0), the first number signals movement along the xx-axis (left/negative or right/positive).
    • The second number signals movement along the yy-axis (down/negative or up/positive).
  • Cartesian Coordinates Nomenclature:
    • x-coordinate: Represents horizontal distance from the origin.
    • y-coordinate: Represents vertical distance from the origin.
    • Example: In the pair (5,7)(5, 7), 55 is the xx-coordinate and 77 is the yy-coordinate.

3.1.7 Systematic Procedure for Plotting Points

  • The Plotting Process:
    1. Begin at the origin (OO).
    2. Navigate along the xx-axis according to the amount and direction indicated by the xx-coordinate.
    3. Move vertically (up or down) parallel to the yy-axis according to the yy-coordinate.
    4. Mark the final position with a dot (..) or a cross (×\times).
  • Selecting an Appropriate Scale:
    • Evaluate the highest and lowest values in the data set for both xx and yy.
    • The scale should encompass all values while remaining large enough for clarity and precision.
    • Standard Increment Scale: 1cm1\,cm usually represents 1,2,5,10,20,50, or 1001, 2, 5, 10, 20, 50, \text{ or } 100 units.
  • Example 3.1: Plotting (2,3)(2, -3) and (2.4,1.8)(-2.4, 1.8):
    • For (2,3)(2, -3): Navigate 22 steps positively on the xx-axis, then 33 steps negatively on the yy-axis.
    • For (2.4,1.8)(-2.4, 1.8): Navigate 2.42.4 steps left on the xx-axis, then 1.81.8 steps up parallel to the yy-axis.
  • Example 3.2: Quadrilateral Vertices:
    • Points: A(7.5,5)A(-7.5, -5), B(0,5)B(0, -5), C(7.5,7.5)C(7.5, 7.5), D(0,7.5)D(0, 7.5).
    • Scaling Insight: A scale of 2cm2\,cm representing 55 units was deemed appropriate.
    • Result: Joining these points forms a parallelogram, with diagonal intersection at (0,1.25)(0, 1.25).

3.1.8 - 3.1.9 Linear Graphs and Tables of Values

  • Linear Graph Property: This is a graph whose equation represents a straight line. They are essential for modeling relationships with a constant rate of change.
  • Linear Equation definition: An equation where the highest power of any variable is 11.
  • Variable Dynamics:
    • Independent Variable (x): The input, which is chosen freely.
    • Dependent Variable (y): The output, determined by the rule of the equation.
  • Using a Table of Values:
    • A systematic method to generate ordered pairs by substituting selected xx values into the equation.
    • Reliability Rule: While two points uniquely determine a line, it is practical to plot three points. If all three align, the calculations are confirmed as accurate.
  • Analysis of y=2x+3y = 2x + 3:
    • The coefficient of xx (22) dictates the slope: as xx increases by 11, yy increases by 22.
    • The constant (33) identifies where the line crosses the yy-axis.
    • Table values: (0,3)(0, 3), (1,5)(1, 5), (2,7)(2, 7), (3,9)(3, 9), (4,11)(4, 11).

3.1.10 - 3.1.11 Intercepts: X and Y

  • Oblique Lines: Straight lines that are neither horizontal nor vertical. These always intersect both axes exactly once.
  • The Y-Intercept:
    • The point where the graph crosses the vertical axis.
    • Condition: x=0x = 0.
  • The X-Intercept:
    • The point where the graph crosses the horizontal axis.
    • Condition: y=0y = 0.
  • Algebraic Determination:
    • Example: 3x+2y=43x + 2y = 4
      • In slope-intercept form (y=32x+2y = -\frac{3}{2}x + 2), the yy-intercept is (0,2)(0, 2).
      • Setting y=0y=0: 3x+2(0)=43x=4x=433x + 2(0) = 4 \Rightarrow 3x = 4 \Rightarrow x = \frac{4}{3}. The xx-intercept is (43,0)(\frac{4}{3}, 0).
    • Example: xy=3x - y = 3
      • Setting x=0x=0: y=3y = -3. The yy-intercept is (0,3)(0, -3).
      • Setting y=0y=0: x=3x = 3. The xx-intercept is (3,0)(3, 0).

3.1.11 - 3.1.12 The Gradient (Slope) of a Straight Line

  • Conceptual Steepness: Gradient is the measure of how steep a line is, calculated as the ratio of vertical change to horizontal change.
  • The Ladder Analogy:
    • Moving vertically (BC=2.8mBC = 2.8\,m) vs horizontally (AB=2mAB = 2\,m).
    • Gradient=Vertical DistanceHorizontal Distance=2.82=1.4\text{Gradient} = \frac{\text{Vertical Distance}}{\text{Horizontal Distance}} = \frac{2.8}{2} = 1.4.
    • A second position (BD=2.5mBD = 2.5\,m) yields Gradient=2.82.5=1.12\text{Gradient} = \frac{2.8}{2.5} = 1.12. Because 1.12<1.41.12 < 1.4, this position is less steep.
  • General Formula for Gradient (mm):
    • Given points P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2), the gradient is:
    • m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
  • Gradient Directions:
    • Positive Gradient: Increasing xx results in increasing yy; the line rises from left to right.
    • Negative Gradient: Increasing xx results in decreasing yy; the line falls from left to right.
  • Example 3.3 Calculation:
    • Segment ABAB involving A(4,0)A(4, 0) and B(6,4)B(6, 4): m=4064=42=2m = \frac{4 - 0}{6 - 4} = \frac{4}{2} = 2.
    • Segment ACAC involving A(4,0)A(4, 0) and C(0,6)C(0, 6): m=6004=64=1.5m = \frac{6 - 0}{0 - 4} = \frac{6}{-4} = -1.5.

3.1.13 Forming the Equation of a Line Using Two Points

  • Step-by-Step Procedure:
    1. Calculate the Gradient (mm): Use m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.
    2. Apply Point-Slope Form: Utilize the formula yy1=m(xx1)y - y_1 = m(x - x_1).
    3. Simplify: Rearrange into Slope-Intercept form (y=mx+cy = mx + c) or Standard form (ax+by+c=0ax + by + c = 0).
  • Demonstration Examples:
    • Line through (2,3)(2, 3) and (6,11)(6, 11):
      • m=11362=2m = \frac{11 - 3}{6 - 2} = 2.
      • y3=2(x2)y3=2x4y=2x1y - 3 = 2(x - 2) \rightarrow y - 3 = 2x - 4 \rightarrow y = 2x - 1.
    • Line through (1,4)(-1, 4) and (3,2)(3, -2):
      • m=243(1)=64=1.5m = \frac{-2 - 4}{3 - (-1)} = \frac{-6}{4} = -1.5.
      • y4=1.5(x+1)y=1.5x+2.5y - 4 = -1.5(x + 1) \rightarrow y = -1.5x + 2.5.

3.1.14 Fundamentals of Linear Equations

  • Terminology:
    • Equation: A mathematical sentence utilizing the symbol == to express equality.
    • Conditional Equation: Satisfied by specific values of the unknown (e.g., x+11=15x + 11 = 15, true only if x=4x = 4).
    • Identity: An equation that remains true regardless of the values substituted for the unknown variable (e.g., 2x+2=2(x+1)2x + 2 = 2(x + 1)).
    • Linear Equation: An equation where the unknown has a power of 11.
    • Solution: The specific value of the unknown that makes the equation true.
  • Algebraic Conventions:
    • Early alphabet letters (a,b,ca, b, c) represent constant values.
    • Late alphabet letters (x,y,zx, y, z) represent unknown values to be solved.

Solving Linear Equations: Methods

  • The Balancing Method: Treat the equation like a scale. To maintain balance, perform identical operations on both sides:
    • Add/Subtract the same number.
    • Multiply/Divide by the same non-zero number.
  • Example 3.9 Balancing Process for 8x6=5x+98x - 6 = 5x + 9:
    1. Add 66: 8x=5x+158x = 5x + 15.
    2. Subtract 5x5x: 3x=153x = 15.
    3. Divide by 33: x=5x = 5.
  • The Cover-up Technique: Useful for simple equations. Example: In 2x+3=172x + 3 = 17, if something+3=17\text{something} + 3 = 17, then the "something" (2x2x) must be 1414. If 2x=142x = 14, xx must be 77.
  • Dealing with Fractions: Algebraic fractions (e.g., x43\frac{x - 4}{3}) are solved by multiplying every term by the LCM (Least Common Multiple) of all denominators to "clear" the fractions.
    • Example 3.12: 2y5+34=10+y2\frac{2y}{5} + \frac{3}{4} = 10 + \frac{y}{2}.
    • LCM of 5,4,2=205, 4, 2 = 20.
    • 20(2y5)+20(34)=20(10)+20(y2)20(\frac{2y}{5}) + 20(\frac{3}{4}) = 20(10) + 20(\frac{y}{2}).
    • 8y+15=200+10y2y=185y=92.58y + 15 = 200 + 10y \rightarrow -2y = 185 \rightarrow y = -92.5.
  • Equations involving Brackets:
    • Brackets express multiplication across quantities: 3(x+4)=3x+123(x + 4) = 3x + 12.
    • Rule: Multiply the factor outside by each term inside. Pay careful attention to signs (e.g., a(a+b)=a2ab-a(a + b) = -a^2 - ab).

Forming and Solving Linear Equations (Word Problems)

  • Translation Table (Keywords to Signs):
    • Sum, total, altogether: Add (++)
    • Difference, less than: Subtract (-)
    • Twice a number: 2x2x
    • Shared equally: Divide (÷\div)
    • Is equal to: ==
  • General Steps:
    1. Carefully identify the unknown quantity.
    2. Let a variable (usually xx) represent the unknown.
    3. Translate the verbal statements into a linear equation.
    4. Solve using balancing/algebraic methods.
    5. Verify the answer against the original problem context.
  • Tom and Mary Example (FRW 450 total):
    • Mary gets 54 FRW54\text{ FRW} less than Tom.
    • Let Tom = xx; Mary = x54x - 54.
    • x+(x54)=4502x=504x=252x + (x - 54) = 450 \Rightarrow 2x = 504 \Rightarrow x = 252.
    • Tom receives 252 FRW252\text{ FRW}; Mary receives 198 FRW198\text{ FRW}.

3.3 Inequalities

  • Definition: Statements expressing comparisons such as "greater than" or "fewer than," using symbols rather than an equal sign.
  • Core Symbols:
    • >>: Greater than
    • <<: Less than
    • \ge: Greater than or equal to
    • \le: Less than or equal to
  • Representation on a Number Line:
    • Open Circle (o): Indicates the endpoint is not included (used for >> and <<).
    • Closed Dot (•): Indicates the endpoint is included (used for \ge and \le).
  • Solving Rules:
    • Add or subtract the same number from both sides.
    • Multiply or divide by a positive number.
    • Critical Rule: If multiplying or dividing by a negative number, you must reverse the inequality sign.
  • Compound Statements: Express that a variable lies between two values, e.g., a<x<ba < x < b
  • Word Problem Example (Mangoes):
    • Lucy had mm mangoes. Gave away 44. Half the remainder is less than 1717.
    • m42<17m4<34m<38\frac{m - 4}{2} < 17 \Rightarrow m - 4 < 34 \Rightarrow m < 38.
    • Maximum whole number of mangoes is 3737.
  • Word Problem Example (Bus Capacity):
    • Bus carries at most 6060 passengers. 1818 are already on board.
    • 18+p60p4218 + p \le 60 \Rightarrow p \le 42. Maximum additional boarders = 4242.