Introductory Heat & Thermodynamics (PHY 102) – Comprehensive Bullet-Point Notes
Course Overview
Course Title & Code: Introductory Heat and Thermodynamics – PHY 102 (2 CU)
Prerequisites: High-school Physics & Mathematics
Broad Units Covered
• Thermometry
• Thermal Expansion
• Heat Energy
• Thermodynamics (1st & 2nd Laws, processes, Carnot cycle)
• CryogenicsRecommended Text: University Physics (15th ed.) by Young & Freedman
Topic 1 – Thermometry
1.1 Temperature
• Operational definition: proportional to average kinetic energy of particles
• Measured in °C, K, °F
• Zeroth Law: If A ↔ B and B ↔ C are in thermal equilibrium ⇒ A ↔ C. Provides logical foundation for temperature measurement and thermometer calibration.1.2 Thermometers & Observable Properties
• Measurement device exploiting a temperature-dependent property:
– Volume (liquid-in-glass, gas thermometers)
– Electrical resistance (metal wire resistance thermometers)
– Electromotive force (thermocouples)
– Pressure (constant-volume gas thermometer)
• Common types & principles
– Mercury/alcohol liquid-in-glass: \Delta V of fluid
– Gas thermometer: P \propto T at fixed volume
– Resistance (RTD): R = R_0\left(1+\alpha\Delta T\right)
– Thermocouple: Seebeck e.m.f. proportional to \Delta T
– Digital/electronic sensors: semiconductor band-gap shift → voltage/frequency output.1.3 Temperature Scales
• Celsius: based on 0\,°C (ice point) & 100\,°C (steam point).
• Kelvin: absolute scale starting at absolute zero; TK = T{°C} + 273.15.
• Fahrenheit: T{°F} = \tfrac{9}{5}T{°C} +32.
• Conversions – worked examples (link to practice problems).Illustrative Question Samples
• Convert 30\,°C → K & °F.
• A thermometer shows 100\,°F; find °C & K.
• Name two physical properties used in thermometers.
Topic 2 – Thermal Expansion
Thermal agitation → increased inter-atomic spacing → macroscopic size change.
2.1 Linear Expansion
• Formula: \Delta L = \alpha L_0\Delta T
• \alpha: linear coefficient ((\text{K}^{-1}) or °C⁻¹); typically 10^{-6}\text{–}10^{-5}\,\text{K}^{-1} for metals.
• Practical example: bridges, rails, metal rods stretching.2.2 Volumetric Expansion
• For isotropic solids/liquids: \Delta V = \beta V0\Delta T with \beta \approx 3\alpha. • Area expansion (sheets): \Delta A = 2\alpha A0\Delta T (useful for plate questions).2.3 Engineering/Everyday Applications
• Expansion joints in bridges & railways prevent buckling.
• Bimetallic strip thermostats bend due to differing \alpha values.
• Gaps under metal lids/glass to accommodate \Delta V.Practice Problems
• Metal rod: L0 = 2\,\text{m}, \Delta L = 0.004\,\text{m} at \Delta T = 50\,°C → \alpha? • Metal sheet A0 = 1.5\,\text{m}^2, \alpha = 2\times10^{-5}/°C, \Delta T = 30\,°C → \Delta A.
• Conceptual: why bridges need joints.
Topic 3 – Heat Energy
3.1 Heat vs. Temperature
• Heat Q: energy in transit due to \Delta T; unit J. 1 cal = 4.186 J.
• Temperature: state variable, not energy quantity.3.2 Specific Heat Capacity c
• Definition: heat required per kg for 1 K rise. Units \text{J·kg}^{-1}\text{K}^{-1}.
• Formula: Q = mc\Delta T.
• Water: high c = 4200\,\text{J·kg}^{-1}\text{K}^{-1} → climate moderation, coolant uses.
• Example: 2 kg water, 20\rightarrow30\,°C: Q = 84\,000\,\text{J}.3.3 Latent Heat L
• Heat for phase change at constant T.
• Fusion Lf (solid↔liquid), vaporization Lv (liquid↔gas).
• Equation: Q = mL.
• Everyday significance: ice melts absorbing heat without warming; perspiration cooling.
• Note: graph of T vs. heat shows plateau during phase change → constant T but increasing internal energy.Sample Questions (reinforce laws)
• Heat to raise 2 kg water from 20→100 °C?
• Heat to melt 0.5 kg ice at 0 °C (given L_f)?
• Define specific heat capacity & latent heat of fusion.
Topic 4 – Thermodynamics
4.1 First Law (Energy Conservation in Thermodynamic Form)
Statement: \Delta U = Q - W
• \Delta U: internal energy change
• Q: heat added (+) / removed (−)
• W: work done by system (+ when expansion).Work for piston-gas: W = P\Delta V (for constant P).
Consequences:
• If Q>W ⇒ \Delta U>0 (heating or compression).
• If W>Q ⇒ \Delta U<0 (cooling during expansion).
4.2 Quasi-Static Thermodynamic Processes
Isothermal (T = const)
• \Delta U = 0 ⇒ Q = W.
• Achieved via slow change with thermal reservoir.
• Example: gas in bath slowly compressed.Adiabatic (Q = 0)
• \Delta U = -W.
• Fast or perfectly insulated.
• Expansion: T drops; compression: T rises.Isochoric / Isovolumetric (V = const)
• W = 0 ⇒ Q = \Delta U.
• Rigid container heating.Isobaric (P = const)
• Q = \Delta U + W.
• Example: boiling water at atmospheric pressure.Practice & Concept Checks (selected)
Gas expands isothermally, does 500 J work → Q = 500 J in.
In isothermal expansion, internal energy? (unchanged).
Adiabatic compression, \Delta U = +600 J → work done = −600 J (on gas).
Isochoric heating of 2 kg gas, \Delta U = +800 J → W = 0.
Isobaric heat in: 1200 J, work 300 J → \Delta U = 900 J.
4.3 Second Law (Directionality & Limits)
Clausius Statement: Heat does not flow spontaneously cold→hot.
Kelvin-Planck: Impossible to convert all heat from single reservoir into work (η<100%).
Entropy Statement: Total entropy of isolated system never decreases; increases for irreversible processes.
Entropy, S: measure of disorder; \Delta S = \frac{Q_{rev}}{T} for reversible path.
4.4 Heat Engines
Definition: Cyclic device converting heat QH from hot reservoir into work W while discarding QC to cold reservoir.
Energy balance: QH = W + QC; W = QH - QC.
Thermal efficiency: \eta = \frac{W}{QH} = 1 - \frac{QC}{Q_H} (always <1).
Ideal Limit – Carnot Engine • Reversible cycle with max efficiency: \eta{Carnot} = 1 - \frac{TC}{T_H} (K). • Four reversible steps:
Isothermal expansion at T_H (heat in)
Adiabatic expansion (T drops to T_C)
Isothermal compression at T_C (heat out)
Adiabatic compression (T rises to TH). • No engine surpasses Carnot efficiency for same TH, T_C.
Real-World Analogy: Car engine—fuel combustion provides QH, piston does W, exhaust heats air (big QC). Improving design aims to lower Q_C.
Sample Problems
• Engine: QH = 600 J, QC = 400 J → \eta = 0.33 or 33 %.
• Carnot at TH=500 K, TC=300 K → \eta_{max}= 1-\tfrac{300}{500}=0.40 (40 %).
Topic 5 – Cryogenics
Definition: Physics & technology of temperatures below −150 °C (123 K); includes liquefaction of gases, effects on materials.
Key Applications
• Gas liquefaction (O₂, N₂, He): medical O₂ supply, rocket oxidizers.
• Biological storage: blood, semen, ova; organ preservation.
• Superconductivity & quantum computing: requires ≲10 K.
• Space tech: propellant storage, IR detectors cooled for sensitivity.Important Data: Nitrogen boils at 77\,\text{K} (−196 °C).
Practice Qs
• Define cryogenics.
• List two uses of cryogenic liquids.
• At what T does N₂ liquefy? (77 K).
Consolidated Numerical Constants & Conversions
1 cal = 4.186 J (food Calorie = 1000 cal).
Water c = 4200\,\text{J·kg}^{-1}\text{K}^{-1}.
Ice latent heat of fusion L_f = 334\,000\,\text{J·kg}^{-1}.
Liquid-to-gas latent heats: water L_v ≈ 2.26\times10^{6}\,\text{J·kg}^{-1}.
Typical \alpha metals: steel 1.2\times10^{-5}\,\text{K}^{-1}, aluminum 2.4\times10^{-5}\,\text{K}^{-1}.
Conceptual & Practical Connections
Climate & Engineering: High water c moderates coastal temperatures; expansion coefficients inform structural gaps.
Energy Technology: 2nd Law justifies real-world efficiency limits in power plants, motivates waste-heat recovery.
Medical Ethics: Cryogenic preservation raises debates on long-term viability & consent.
Sustainability: Understanding thermodynamic limits guides renewable-energy system design.
Study Strategy Tips
Memorize fundamental formulas in boxed form.
Practice unit conversions (°C↔K↔°F, grams↔kg, J↔cal).
Draw P$–$V diagrams for each thermodynamic process to visualize work (area under curve).
For efficiency questions, always track heat in, heat out, and sign conventions carefully.