Thermodynamics Lecture – Power Cycles, Refrigeration, Transient Analysis & Intro to 2nd Law
Course Logistics / Administrative Remarks
- Instructor is currently grading the mid-term; solutions will be reviewed in an upcoming lecture once marking is complete.
- Grades will be posted on Brightspace; arrangements will be made for students to view their marked copies (possible on-campus office hours).
- Upcoming tutorials will centre on steady-state, steady-flow (SSSF) device analysis (Chapter 4 problems).
- No quiz next week; lectures continue with Chapter 5 and beyond.
Quick Recap – SSSF Devices (from previous lecture)
- Devices treated as open systems operating at steady state–steady flow:
- Heat exchangers (boiler, condenser, recuperators, etc.)
- Turbines & compressors
- Pumps (for liquids) / throttling valves
- Nozzles & diffusers
- Key idea:
For each device, if you know its purpose you may safely neglect certain terms in \dot Q,\;\dot W,\;\Delta KE,\;\Delta PE when writing the 1st-law rate form
\dot Q{cv}+\sum \dot min h{in} = \dot W{cv}+\sum \dot m{out} h{out} \;\Bigl( + \text{KE} + \text{PE terms}\Bigr). - Pumps/Compressors: work into device (usually small heat losses, (\Delta KE\approx\Delta PE\approx0)).
- Turbines: work out of device (adiabatic, (\Delta KE\approx\Delta PE\approx0)).
- Heat exchangers: large \dot Q, negligible \dot W, often operate at approximately constant pressure.
- Throttles: h{in}!\approx!h{out} (isenthalpic), large pressure drop, no work.
Basic Rankine (Steam) Power-Plant Cycle
- Purpose: Convert a positive heat input Q{B} (boiler) into net work output via turbine WT.
- Working fluid: liquid water / steam.
- Four fundamental devices composing the closed loop
- Pump: 1 → 2 – increases pressure of sub-cooled liquid at almost constant specific volume.
- Boiler: 2 → 3 – constant-pressure heat addition; liquid is vaporised to super-heated steam.
- Turbine: 3 → 4 – adiabatic expansion; high-pressure steam produces shaft work.
- Condenser: 4 → 1 – constant-pressure heat rejection; condenses exhaust to saturated/sub-cooled liquid.
- Two operating pressures only: low (condenser) and high (boiler/turbine inlet).
- T–v diagram characteristics
- Pump stroke ≈ vertical line (tiny \Delta v).
- Boiler: horizontal rightward path (constant (P_{high})).
- Turbine: downward/rightward curve to low pressure inside or just outside vapour dome.
- Condenser: horizontal leftward to compressed-liquid region.
- Rule of thumb for turbine exhaust: stay near saturated-vapour line (quality x \gtrsim 0.9) to limit blade erosion but avoid excessive condenser load.
Detailed Worked Example – Basic Steam Power Plant
Given
- \dot m = 10\;\mathrm{kg\,s^{-1}} (water)
- Pump power input W_P = 200\;\text{kW}
- Pressures: P1=P4=15\;\text{kPa},\;P2=P3=2\;\text{MPa}
- Temperatures / qualities:
T1 = 45^{\circ}\text{C}\; (\text{compressed liquid}),\quad T3 = 300^{\circ}\text{C}\; (\text{super-heated}),\quad x_4 = 0.90
(A) Turbine power
Assumptions: adiabatic, SSSF, negligible KE/PE.
\dot WT = \dot m\,(h3-h4)
Values (steam tables):
h3=3023.5\;\text{kJ kg}^{-1}, \; h4 = 2361.7\;\text{kJ kg}^{-1}
Result
\boxed{\dot WT = 6.62\;\text{MW}}
(B) Pump exit temperature
First-law (pump): -\dot WP = \dot m\,(h1-h2)
Compressed-liquid approximation h\approx hf(T)
h1 = 188.42\;\text{kJ kg}^{-1}\;@\;45^{\circ}\text{C}\Rightarrow h2 = 208.42\;\text{kJ kg}^{-1}
Interpolate hf(T) ⇒ T2 \approx 49.8^{\circ}\text{C}
(C) Boiler heat input
Heat-exchanger, SSSF, \dot W=0, \Delta KE,\Delta PE\approx0
\dot QB = \dot m\,(h3-h_2) = 10\,(3023.5-208.4) \approx 28.15\;\text{MW}
(D) Observations
Thermal efficiency (ideal) \eta = \dfrac{\dot W{net}}{\dot QB} \approx \tfrac{6.62\;\text{MW}}{28.15\;\text{MW}} \approx 0.235 (≈ 23.5 %).
Real plants add feed-water heaters, reheat stages, etc., to raise (\eta).
Refrigerator (Vapour-Compression) Cycle
- Goal: Remove heat Q{in} from a low-temperature region (refrigerated space) and reject Q{out} to ambient while consuming work W_{comp}.
- Key components (ideal single-stage cycle)
- Evaporator (low-pressure): liquid–vapour mixture absorbs Q_{in} → becomes super-heated vapour.
- Compressor: raises pressure & T of vapour (work input).
- Condenser (high-pressure): vapour rejects Q_{out} → saturated liquid.
- Throttle / Expansion Valve: isenthalpic drop back to low pressure, producing 2-phase mixture.
- T–v diagram: two pressure levels; horizontal constant-p heat transfer in evaporator & condenser; vertical-ish compression; throttling follows constant enthalpy line inside dome.
- Performance metric: Coefficient of performance \text{COP}R = \dfrac{Q{in}}{W_{comp}}.
- Must select refrigerant with low boiling point at evaporator pressure (e.g., R-134a, ammonia).
Transient-Flow (Unsteady) Analysis (Chapter 4, Topic 4)
When SSSF assumptions break down (e.g., tanks being filled/emptied):
- Control volume properties change with time but are assumed uniform at any instant (lumped parameter).
- Inlet/outlet streams: constant (\dot m) and constant state during the process.
Mass conservation over finite interval \Delta t:
m2-m1 = m{in}-m{out}
General 1st-law form (no a priori simplifications):
Q{1\rightarrow2}+m{in}h{in}-m{out}h{out}=\bigl(m2u2-m1u1\bigr)+\bigl(KE+PE\bigr)+W{1\rightarrow2}
Worked Example – Filling a Rigid Ammonia Tank
Data
- Rigid tank volume V=0.35\;\text{m}^3 initially contains NH(3) at T1=-20^{\circ}\text{C},\;x_1=0.5.
- Supply line (inlet): T{in}=80^{\circ}\text{C},\;P{in}=800\;\text{kPa} (super-heated).
- Valve opened until tank reaches P2=600\;\text{kPa} with final quality x2=1 (sat. vapour); tank still rigid (no work).
Find (a) T2, (b) m{in}, (c) Q_{1\rightarrow2}.
Results
- (a) Interpolating NH(3) saturation tables: T2=9.2^{\circ}\text{C}.
- (b) Masses using m=V/v:
- m1 = 1.12\;\text{kg},\quad m2 = 1.658\;\text{kg}
⇒ \boxed{m_{in}=0.537\;\text{kg}}.
- m1 = 1.12\;\text{kg},\quad m2 = 1.658\;\text{kg}
- (c) Energy balance (no shaft work, no outlet stream):
Q{1\to2}=m2u2-m1u1-m{in}h_{in} = \boxed{548.5\;\text{kJ (heat in)}}
Motivation for the Second Law (Start of Chapter 5)
- First Law is an energy balance; does not predict direction of processes.
- Everyday observation: hot coffee cools to room temperature; the reverse (room air spontaneously heating coffee) never happens even though 1st Law would allow it energy-wise.
- Example tank-and-fan “cycle” from earlier lecture operates only in one direction; reversing violates observed reality.
- Therefore, a second restriction on processes is required → 2nd Law.
Heat Engines – Definition & Conceptual Example
Definition
- A heat engine is a closed cycle that
- Receives net positive heat Q_H>0 from a high-temperature reservoir (source),
- Rejects heat Q_L<0 to a low-temperature reservoir (sink),
- Delivers net positive work W_{net}>0.
Thought-experiment engine (single piston, removable mass)
- Stage 1 (1→2): Add heat Q_H from hot source → gas pressure rises, piston lifts heavy mass ⇒ positive work.
- Stage 2 (2→1): Remove mass, cool gas against cold sink (heat Q_L out) until piston returns to stops ⇒ small negative work.
- Net cycle work W{net}=W{1\to2}+W_{2\to1}>0 (area enclosed on P–V diagram).
- Energy flows from hot to cold; part converted to useful work.
- Previews later 2nd-Law results: efficiency bound, irreversibility concept, Carnot limits.
Miscellaneous Study Tips & Connections
- Always start with mass conservation then 1st Law; add 2nd Law constraints where applicable (Ch 5-7).
- Know how to read property tables (saturated, super-heated, compressed-liquid) and perform linear interpolation.
- Memorise sign conventions:
Q{cv}>0 (heat into system), W{cv}>0 (work by system). - Compressed-liquid approximation: {u,h,v}{\text{CL}}\approx{uf,hf,vf}_{T} when high-pressure data absent.
- For ideal gases: u=u(T)=\int cv\,dT, h=h(T)=\int cp\,dT independent of pressure.
- Typical exam pitfalls: forgetting to convert kJ↔J, dropping sign, neglecting kinetic/potential energy assumptions when invalid.
Suggested Further Resources
- Brightspace PDF of curated YouTube links for visualisations (turbines, compressors, refrigeration animations, etc.).
- Re-work tutorial/lecture examples with tables open to gain property-lookup speed.
- Preview Chapter 5 sections on entropy, reversibility, Carnot cycle before next lecture.