Three-Dimensional Geometry Fundamentals

Perpendicular Distance of a Point from Coordinate Planes

  • Distance of a point P(x,y,z)P(x, y, z) from the xy planexy\text{ plane} is equal to the absolute value of its zz-coordinate:   dxy=∣z∣d_{xy} = |z|

  • Distance of a point P(x,y,z)P(x, y, z) from the yz planeyz\text{ plane} is equal to the absolute value of its xx-coordinate:   dyz=∣x∣d_{yz} = |x|

  • Distance of a point P(x,y,z)P(x, y, z) from the zx planezx\text{ plane} is equal to the absolute value of its yy-coordinate:   dzx=∣y∣d_{zx} = |y|

Distance Formula in Three Dimensions

  • For any two points A(x1,y1,z1)A(x_1, y_1, z_1) and B(x2,y2,z2)B(x_2, y_2, z_2) in three-dimensional space, the straight-line distance dd between AA and BB is given by:   d=(x2−x1)2+(y2−y1)2+(z2−z1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}

Section Formula in Three Dimensions

  • Consider two points A(x1,y1,z1)A(x_1, y_1, z_1) and B(x2,y2,z2)B(x_2, y_2, z_2). Let a point C(x,y,z)C(x, y, z) divide the line segment joining AA and BB in the ratio m:nm : n.

  • Internal Division:   When the point C(x,y,z)C(x, y, z) divides the line segment ABAB internally in the ratio m:nm : n, its coordinates are:   x=mx2+nx1m+nx = \frac{mx_2 + nx_1}{m + n}   y=my2+ny1m+ny = \frac{my_2 + ny_1}{m + n}   z=mz2+nz1m+nz = \frac{mz_2 + nz_1}{m + n}

  • External Division:   When the point C(x,y,z)C(x, y, z) divides the line segment ABAB externally in the ratio m:nm : n, its coordinates are:   x=mx2−nx1m−nx = \frac{mx_2 - nx_1}{m - n}   y=my2−ny1m−ny = \frac{my_2 - ny_1}{m - n}   z=mz2−nz1m−nz = \frac{mz_2 - nz_1}{m - n}