Circuit Resistance Analysis

Parallel and Series Branches

  • Current divides at junctions, creating parallel branches.
  • Current is the same through elements in series.

Top Branch Resistance

  • Two resistors in series (6Ω6 \Omega and 1Ω1 \Omega) can be combined: 6Ω+1Ω=7Ω6 \Omega + 1 \Omega = 7 \Omega.
  • A 6Ω6 \Omega resistor is in parallel with the combined 6Ω6 \Omega resistor.
  • Equivalent resistance of parallel branches: R<em>eq=(1/R</em>1+1/R2)1R<em>{eq} = (1/R</em>1 + 1/R_2)^{-1}.
  • Req=(1/6+1/6)1=3ΩR_{eq} = (1/6 + 1/6)^{-1} = 3 \Omega.
  • Combined with a 3Ω3 \Omega resistor in series: 3Ω+3Ω=6Ω3 \Omega + 3 \Omega = 6 \Omega.

Bottom Branch Resistance

  • Parallel resistors: 1/4Ω1/4 \Omega and 1/12Ω1/12 \Omega.
  • Equivalent resistance: (1/(1/4)+1/(1/12))1=(4+12)1=3Ω(1/(1/4) + 1/(1/12))^{-1} = (4 + 12)^{-1} = 3 \Omega.
  • Combined with a 9Ω9 \Omega resistor in series: 3Ω+9Ω=12Ω3 \Omega + 9 \Omega = 12 \Omega.

Total Circuit Resistance

  • Two parallel branches with 6Ω6 \Omega and 12Ω12 \Omega resistances.
  • Equivalent resistance: (1/6+1/12)1=4Ω(1/6 + 1/12)^{-1} = 4 \Omega.
  • Total resistance: 3Ω+4Ω=7Ω3 \Omega + 4 \Omega = 7 \Omega (series resistances added).