Circuit Resistance Analysis
Parallel and Series Branches
- Current divides at junctions, creating parallel branches.
- Current is the same through elements in series.
Top Branch Resistance
- Two resistors in series (6Ω and 1Ω) can be combined: 6Ω+1Ω=7Ω.
- A 6Ω resistor is in parallel with the combined 6Ω resistor.
- Equivalent resistance of parallel branches: R<em>eq=(1/R</em>1+1/R2)−1.
- Req=(1/6+1/6)−1=3Ω.
- Combined with a 3Ω resistor in series: 3Ω+3Ω=6Ω.
Bottom Branch Resistance
- Parallel resistors: 1/4Ω and 1/12Ω.
- Equivalent resistance: (1/(1/4)+1/(1/12))−1=(4+12)−1=3Ω.
- Combined with a 9Ω resistor in series: 3Ω+9Ω=12Ω.
Total Circuit Resistance
- Two parallel branches with 6Ω and 12Ω resistances.
- Equivalent resistance: (1/6+1/12)−1=4Ω.
- Total resistance: 3Ω+4Ω=7Ω (series resistances added).