Thermodynamics Class Notes 04: Internal Energy and First Law Calculations
Problem Solving: Isothermal Expansion and Internal Energy
- Scenario Analysis: A gas undergoes expansion under isothermal conditions against a constant external pressure (Pext).
- Initial Volume (V1): 10dm3
- Final Volume (V2): 20dm3
- Heat Exchange (q): The system absorbs 800J of energy from its surroundings (q=+800J).
- Unit Conversions provided in Class Notes:
- 1dm3=1L
- 1atm⋅L=101.3J (The calculation shown in the notes uses the approximation 101J).
- Work Calculation (w):
- Formula: w=−PextΔV
- Calculation: w=−1×(20−10)
- Result in atm⋅L: w=−10atm⋅L
- Conversion to Joules: w=−10×101=−1010J
- Internal Energy Calculation (ΔU):
- First Law of Thermodynamics Formula: ΔU=q+w
- Substitution: ΔU=+800+(−1010)
- Final Calculation: ΔU=−210J
- Options Provided:
- −312J
- +123J
- −213J (Note: The slide's manual calculation results in −210J, while this is the closest option listed).
- +231J
Problem Solving: Change in Internal Energy via Work and Heat
- Problem Statement: Calculate the change in internal energy when specific quantities of work and heat are involved.
- Work (w): 4kJ of work is done on the system (w=+4kJ).
- Heat (q): 1kJ of heat is given out by the system (q=−1kJ).
- Calculation of ΔU:
- Formula: ΔU=q+w
- Substitution: ΔU=−1kJ+4kJ
- Final Result: ΔU=+3kJ
- Options Provided:
- +1kJ
- −5kJ
- +5kJ
- +3kJ (Correct Answer Marked)
Concepts of the First Law of Thermodynamics
- Definition: The First Law of Thermodynamics is fundamentally established as the law of conservation of energy.
- Theoretical Context:
- Option 1: The law of conservation of energy (Correct Identification).
- Option 2: The law of conservation of mass.
- Option 3: The law of conservation of momentum.
- Option 4: Both (1) and (2).
- Key Takeaway: The primary focus of the first law is the principle that energy cannot be created or destroyed, only transformed from one form to another within a thermodynamic system.
Mathematical Notations and Unit Reference
- Standard Equation: ΔU=q+w
- Expansion Work: w=−Pext(V2−V1)
- Unit Identity: 1dm3=1L
- Pressure-Volume Work Conversion: 1atm⋅L≈101.3J