Chemistry Notes on Mole, Mass, and Composition
The Mole
9.1 Relative Masses
- Relative Masses: Commonly used masses compared to a standard, often the isotope Carbon-12 ($^{12}C$).
Relative Molecular Mass
- Elements as Molecules: Examples include $O2$ (oxygen) and $CO2$ (carbon dioxide).
- Relative Molecular Mass ($M_r$): Determined for these molecular substances.
Example: Calculating Relative Molecular Mass of Nitric Acid ($HNO_3$)
Identify atomic masses from the periodic table:
- A$_{(H)} = 1.008$
- A$_{(N)} = 14.01$
- A$_{(O)} = 16.00$
Calculate:
Mr = 1 imes A{(H)} + 1 imes A{(N)} + 3 imes A{(O)}
M_r = 1.008 + 14.01 + 3 imes 16.00 = 63.02
Relative Formula Mass
- Ionic Compounds: For compounds like $NaCl$, use the term Relative Formula Mass instead of Molecular Mass.
Example: Calculating Relative Formula Mass of Copper(II) Nitrate ($Cu(NO3)2$)
Atomic masses:
- A$_{(Cu)} = 63.55$
- A$_{(N)} = 14.01$
- A$_{(O)} = 16.00$
Calculation:
M{formula} = 1 imes A{(Cu)} + 2 imes A{(N)} + 6 imes A{(O)}
= 63.55 + 2(14.01) + 6(16.00) = 187.6
9.2 Introducing the Mole
- Mole (mol): Standard unit for the amount of substance indicated by $n$.
- Example: For hydrogen atoms, $n(H)$.
- Avogadro's Number ($N_A$): 1 mol of substance contains $6.022 imes 10^{23}$ particles.
Examples of Using the Mole to Measure Particles
- $1 mol$ of $H_2$: $2$ moles of $H$ atoms.
- $2 mol$ of $H_2O$ (water):
- Equivalent to $4$ mol of $H$ atoms.
- $10 mol$ of $C6H{12}O_6$ (glucose): Regular conversions between moles of substances and atoms/ions.
Calculating Moles from Molecules
- Example: To find H atoms from sulfuric acid ($H2SO4$).
- Given $3.6$ mol, thus:
n(H) = n(H2SO4) imes 2 - Result: $n(H) = 3.6 imes 2 = 7.2$ mol.
- Given $3.6$ mol, thus:
Relationship Between Avogadro's Number, Particles and Amount
- Formula:
n = rac{N}{N_A}
- Where $N$ is particles, $n$ is moles, and $N_A$ is Avogadro’s number.
Example: Calculate Number of Molecules in 3.5 mol of $H_2O$
- Given:
- $n(H_2O) = 3.5$ mol
- Use:
N = n imes N_A
- $N(H_2O) = 3.5 imes 6.022 imes 10^{23} = 2.1 imes 10^{24}$ molecules.
9.3 Molar Mass
- Definition: Mass in grams of one mole of substance, denoted by $M$ (g/mol).
- Molar mass of elements equals their atomic mass in grams.
- Molar Mass for Compounds: Equivalent to relative molecular/formula mass in grams.
Example of Molar Mass Calculation
| Substance | Relative Atomic Masses | Molar Mass |
|---|---|---|
| Na | 22.99 | $22.99$ g/mol |
| $O_2$ | 16.00 | $32.00$ g/mol |
| $H_2O$ | (2 x 1.008) + 16.00 | $18.016$ g/mol |
| $CO_2$ | 12.01 + (2 x 16.00) | $44.01$ g/mol |
Calculating Mass of a Substance (Example: $Mg(NO3)2$)
- Given 0.35 mol:
- Use:
M(Mg(NO3)2) = 24.31 + (2 imes 14.01) + (6 imes 16.00) = 148.33 g/mol - m = n imes M = 0.35 imes 148.33
ightarrow m = 52 g
- Use:
9.4 Percentage Composition
- Definition: Proportion by mass of different elements in a compound.
Example: Calculate % Composition of Aluminium in $Al2O3$
- Molar mass: 101.96 g/mol.
- Total mass of Aluminium = $53.96$ g (from $2 imes M(Al)$).
- ext{% of Al} = rac{53.96}{101.96} imes 100 = 52.92 ext{%}
Practice Questions
- Complete assigned chapter review questions for reinforcement.