BIO 184 E3 LECTURE 4
Law of Segregation and Independent Assortment
- The law of segregation comes from a monohybrid cross (e.g., Tt cross).
- The law of independent assortment comes from a dihybrid cross (two genes on different chromosomes).
- Linked genes are an exception; they are found on the same chromosome.
Dihybrid Cross and Gamete Types
- A dihybrid cross involves two genes and requires understanding its nuances.
- With independent assortment, a dihybrid cross yields four gamete types.
- Example: YyTt produces YT, Yt, yT, and yt gametes.
Fork-Line Method
- The fork-line method illustrates the law of segregation for each chromosome independently.
- It demonstrates how the law of independent assortment handles genes independently.
- The final gamete types must have one allele from each gene.
Number of Gamete Types
- The number of different gamete options is determined by the number of heterozygous loci.
- Formula: Number of gamete types = 2^n, where n is the number of heterozygous loci.
- Homozygous loci provide no choice, only one type of allele (e.g., TT produces only T).
- Example 1: One heterozygous locus (Tt) yields 2^1 = 2 gamete types.
- Example 2: Two heterozygous loci (YyTt) yields 2^2 = 4 gamete types.
- Example 3: Three heterozygous loci (YyTtCc) yields 2^3 = 8 gamete types.
Finding Gamete Types for a Trihybrid Cross
- For a trihybrid cross (e.g., YyTtCc), use the splitting method to find the eight gamete types:
- Y can go with T, which can go with C (e.g., YTC).
- Y can go with T, which can go with c (e.g., YTc).
- Continue methodically to find all combinations.
Ratios and Probabilities
- Each gamete type in a trihybrid cross represents 1/8 of the total possibilities.
Test Cross
- A test cross helps determine the genotype of an individual by crossing it with a homozygous recessive individual.
- The phenotype of the offspring reveals the genotype of the parent.
- Example: YyTt x yytt allows direct observation of the phenotype since the second parent doesn't contribute.
- The resulting phenotypes (tall, yellow, short, yellow, tall, green, short, green) are directly determined by the alleles from the first parent.
Dihybrid Cross with a Dihybrid
- Crossing two dihybrids (e.g., YyTt x YyTt) results in a 16-well Punnett square.
- Phenotype ratios in the offspring follow a 9:3:3:1 pattern.
- 9: Dominant-Dominant
- 3: Recessive-Dominant
- 3: Dominant-Recessive
- 1: Recessive-Recessive
Solving Dihybrid Crosses Without Punnett Square
- Separate the crosses and handle them independently due to the law of independent assortment.
- Example: Yy x Yy crossed with Tt x Tt
- Yy x Yy results in a 3:1 ratio (3/4 yellow, 1/4 green).
- Tt x Tt results in a 3:1 ratio (3/4 tall, 1/4 short).
- Multiply the ratios to find the combined probabilities:
- 3/4 (tall) x 3/4 (yellow) = 9/16 (tall, yellow).
- The 9:3:3:1 ratio is derived from these multiplications.
Example of Calculating Phenotype Fractions
- Cross: TtYy x TtYY
- Goal: Find the fraction of tall, yellow offspring.
- No green offspring are possible since one parent is YY.
- The cross Tt x Tt yields 3/4 tall.
- Since all offspring are yellow, the fraction of tall, yellow offspring is 3/4 x 1 = 3/4.
Simplified Method for Specific Phenotypes
- Instead of calculating all possible outcomes, focus only on the desired phenotype.
- Example: Finding the fraction of tall, yellow offspring.
- Fraction of tall from Tt x Tt is 3/4.
- Fraction of yellow from Yy x YY is 1.
- Multiply 3/4 * 1 = 3/4 to get the fraction of tall, yellow offspring.
Trihybrid Cross Example
- Cross: TtGgKk x ttggKk (where K is purple and k is not purple)
- Goal: Find the fraction of short, green, and purple offspring.
- Short: Tt x tt = 1/4 short.
- Green: Gg x gg = 1/4 green.
- Purple: Kk x Kk = 3/4 purple.
- Combined probability: 1/4 * 1/4 * 3/4 = 3/64.
Fork Line Method for Triple Hybrid Crosses
- The fork-line method can be used for trihybrid crosses, such as RrTtYy.
- First split: Tt (tall vs. short - 3/4 tall, 1/4 short).
- Second split: Rr (round vs. wrinkled - 3/4 round, 1/4 wrinkle).
- Third split: Yy (yellow vs. green - 3/4 yellow, 1/4 green).
- This method exhaustively shows every possible iteration of the triple hybrid.
Phenotype Ratios in Triple Hybrid Crosses
- In a trihybrid cross, there are 2^3 = 8 possible gamete types, resulting in 64 wells in a Punnett square.
- The numbers in numerators will add up to 64
- Example is TtRrYy x TtRrYy which has results in the ratios of each phenotype showing up.
Practice Problem
- Cross: TtYy x TtYy.
- Isolate crosses Tt and Yy.
- What is the fraction of offspring that are both tall and yellow?
- Tall (3/4), Yellow (1/2). Fraction of offspring that are both tall and yellow comes to be 9/32
Key Terminology
- Pure breeding, true breeding, and homozygous are equivalent terms.
- Hybrid refers to heterozygous individuals.
Loss-of-Function Alleles
- Recessive alleles often result from a loss of function in a gene.
- Example: Yellow vs. Green seed color is determined by pigment production where an enzyme is needed.
- One functional copy of the dominant allele is sufficient to produce the dominant phenotype.
- YY and Yy will yield a yellow pigment due to one functional enzyme copy.
- yy results in no yellow pigment (green) due to lack of a functional enzyme.
Dominance and Recessiveness
- Recessives are typically due to a loss of function.
- If you have one functional enzyme maker you don't necessarily need two.
- If you have two copies that don't work you won't have function.
Pedigrees: Basic Concepts
- Box: Male.
- Circle: Female.
- Diamond: Unknown sex.
- Colored shape: Individual has the disease.
- Half-shaded shape or mark in the center: Carrier (normal but carries the allele).
- Double line between mating pair: Inbreeding or consanguineous mating.
- Number inside shape: Number of children of that sex.
- Line through shape: Deceased.
- Generation numbers: Used to identify individuals (e.g., I-2).
- Single split: Twins.
- Line connecting twins: Identical twins.
Recessive vs. Dominant Patterns in Pedigrees
- Dominant traits: Appear in every generation without skipping.
- Recessive traits: May skip generations.
- Horizontal transmission: Affected individuals appear in the same generation (parents unaffected).
Deducing Genotypes from Pedigrees
- Dominant disorder: Affected individuals must have at least one dominant allele.
- Recessive disorder: Affected individuals must be homozygous recessive.
- If parents don't have it, then boom it pops up is a key signal!
Calculating Carrier Probabilities
- Parents who are carriers, and offspring do not have the disease: Calculate probabilities
- Consider the possible genotypes of the offsprings of the parent.
- Example: what is the chance that offspring are hetrozygous?
- Key: The simple answer is one half, and the answer is often wrong. The box may not be the correct option.
- Example: The answer is two thirds because you can rule out out being little c little c.
- We have 3 boxes left, it's a two thirds chance out of the remaining boxes.
- For 2-6, there's no doubt that they're hetozygous.