GEMP 2023 PHYSICS
Outline
- Physics Reference Materials
- GEMP Physics Topics
- Mechanics
- Properties of matter
- Elastic & plastic
- Viscosity
- Vibrational motion
- Circular motion
- Oscillations
- Resonance
- Thermodynamics
- Kinetic theory
- Real and ideal gases
- Laws of thermodynamics
- Electromagnetic Properties of matter
- Magnetic materials
- Dielectrics
- Semiconductors
- Selected Topics in Modern Physics
- The photon
- Heisenberg Uncertainty Principle
- Particle in a box
- Selected Measuring instruments
- Spectrometers
Physics Reference Materials
- University Physics
- Fundamentals of Physics
- Physics: Principles with Applications
- Sears & Zemansky's University Physics with Modern Physics (Fifteenth Edition, Global Edition)
- Physics Principles with Applications by Douglas C. Giancoli
- Fundamentals of Physics by Jearl Walker
- Halliday & Resnick
- Previously sold as the 10th Edition
- Extended
Mechanics
Elastic Properties of Bodies
- Real bodies deform when stressed.
- For small deformations, stress is proportional to strain.
- Stress: ext{Stress} = rac{F}{A}
- Strain: ext{Strain} = rac{ riangle L}{L0} = rac{L - L0}{L_0}
- Young’s Modulus: E = rac{ ext{Stress}}{ ext{Strain}} = rac{rac{F}{A}}{rac{ riangle L}{L_0}}
Bulk Properties
- Bulk stress: ext{Bulk stress} = rac{F}{A}
- Bulk strain: ext{Bulk strain} = rac{ riangle V}{V_0}
- Bulk modulus: K = -rac{ riangle P}{rac{ riangle V}{V_0}}
- Compressibility: eta = rac{1}{K} = -rac{1}{V_0} rac{ riangle V}{ riangle P}
Shear Properties
- Shear stress: ext{Shear stress} = rac{F}{A}
- Shear strain: ext{Shear strain} = an{ heta}
- Shear modulus: G = rac{ ext{Shear stress}}{ ext{Shear strain}}
Poisson’s Ratio
-
u = -rac{ ext{transverse strain}}{ ext{longitudinal strain}} = -rac{rac{ riangle D}{D0}}{rac{ riangle L}{L0}}
- Alternative expressions:
u = rac{3(1-2
u)}{2(1+
u)}
- Alternative expressions:
Plastic Properties
- Typical stress-strain diagrams exhibit the following:
- Elastic limit or yield point: The maximum stress that can be subjected before permanent deformation.
- Proportional limit: The region of elastic behavior where stress is proportional to strain.
- Plastic deformation: Permanent deformation occurring after the yield point.
- Fracture point: The stress where the material finally breaks.
- Elastic hysteresis: The difference in stress-strain behavior under increasing vs. decreasing stress.
Example: Stress and Strain of an Elongated Rod
- A steel rod with:
- Radius: R = 9.5 ext{ mm}
- Length: L = 81 ext{ cm}
- Force applied: F = 62 ext{ kN}
- Key ideas:
- Stress calculation: ext{Stress} = rac{F}{A} where A = rac{ ext{π}R^2}.
- Elongation related to stress and Young's Modulus: riangle L = rac{F L}{AE} where E is Young's modulus.
- Strain is the ratio of elongation to the initial length: ext{Strain} = rac{ riangle L}{L}.
Calculations
Compute stress:
ext{Stress} = rac{62 imes 10^3 N}{ ext{π}(9.5 imes 10^{-3 m})^2} = 2.2 imes 10^8 N/m^2- The yield strength for structural steel is approximately 2.5 imes 10^8 N/m^2, indicating the rod is near its yield strength.
Young's modulus from table: E_{steel} = 2.0 imes 10^{11} N/m^2
- Elongation:
riangle L = rac{ST}{E} = rac{(2.2 imes 10^8 N/m^2)(0.81 m)}{(2.0 imes 10^{11} N/m^2)} = 0.00089 m = 0.89 mm
- Elongation:
Strain:
ext{Strain} = rac{0.00089 m}{0.81 m} = 0.0011 = 0.11 ext{%}
Example: Young's Modulus Calculation
- Given:
- Young's modulus = 42 GPa, Poisson ratio:
u = rac{2}{5}.
- Young's modulus = 42 GPa, Poisson ratio:
- Find:
- Bulk modulus: K = rac{3(1-2
u)}{2(1+
u)} = 70 ext{ GPa} - Shear modulus: G = rac{E}{2(1+
u)} = 15 ext{ GPa}
- Bulk modulus: K = rac{3(1-2
Example: Ideal Gas Law
- State: PV = nRT
- Isothermal bulk modulus: K = -rac{PV}{nR},
- Evaluation under pressure: P = 100 kPa
ightarrow compressibility = 1/(K) ext{ at temperature T}
- Evaluation under pressure: P = 100 kPa
Common Problems
- Biceps Muscle Example:
- When relaxed requires 25.0 N for elongation of 3.0 cm.
- Maximum tension requires 500 N for same elongation.
- Determine Young's modulus for both conditions assuming uniform cylinder properties.
Viscosity
- Defined as the internal friction in a fluid.
- Influences and relates flow rate to pressure gradient through the Poiseuille equation.
- Volume flow rate:
Q = ext{velocity} imes ext{Area}
Example: Water Flow in Capillary Tube
- Given:
- Pressure differential: 1.5 mm
- Viscosity: 0.801 cP.
- Calculation of water flow in 30 seconds across stated tube diameter:
Q = 5.17 imes 10^{-6} m^3 s^{-1}
Vibrational Motion
- Discussed in context of circular motion with critical acceleration related computations.
- Centripetal acceleration defined:
a_c = rac{v^2}{r} - Uniform circular motion is characterized by constant speed and periodic motion.
Example: Kinetic Energy in Circular Motion
- Object of mass 2kg moving in a circle of radius 20m under centripetal force of 800 N:
KE = rac{mv^2}{2} = rac{20m imes 800N}{2}=8000 J
Resonance
- Occurs when the driving frequency matches the system's natural frequency.
- Characterized by motion equations of damped driven oscillators
- Damping behaviors detail amplitude decay related to system design frequency:
m rac{d^2x}{dt^2} + b rac{dx}{dt} + kx = 0
Laws of Thermodynamics
- Zeroth Law: If system A is in equilibrium with system B, and B is in equilibrium with system C, then A and C are in equilibrium.
- First Law: riangle U = Q - W (energy conservation)
- Second Law: States that all heat cannot be converted into mechanical work without losses.
- Carnot Efficiency Equation: ext{Efficiency} = 1-rac{Tc}{Th}
Real Gases
- Discuss Van der Waals equation of state and deviations from ideal gas behavior at high pressures or low temperatures.
Example: Ice Melting
- Determine the energy efficiency when 1 kg of ice melts at 0°C, specific latent heat of ice is 3.34 imes 10^5 J kg^{-1} resulting in riangle S = rac{1kg imes 3.34 imes 10^5 J}{273.15 K}.
Electromagnetic Properties of Materials
- Discuss magnetic materials, dielectrics, and semiconductors.
Magnetic Properties
- Diamagnetism: Overall negative magnetization, weakly repelled by external fields.
- Paramagnetism: Material with unpaired electrons, characterized by a positive weak magnetic susceptibility of about 10^{-4}.
- Ferromagnetism: Materials like iron, cobalt, and nickel: strong interactions exist between magnetic dipoles.
- Magnetization is also dependent on temperature and exhibits hysteresis behaviors.
Semiconductor Properties
- Discuss intrinsic and extrinsic semiconductors, their band structures, and charge carrier behavior.
Example: Transistor Applications
- Bipolar junction transistors (BJTs) demonstrate critical current amplification characteristics in circuits.
Selected Topics in Modern Physics
- The photon is a quantum of the electromagnetic field.
- Heisenberg Uncertainty Principle: Constraints on precision measurements of conjugate variables.
- Solve examples related to motion of particles in quantum systems described by the Schrödinger equation.
Example: Mass Spectrometry
- Explanation of ionized particle dynamics in magnetic fields to quantify masses in atomic units, with specific calculations indicated.