Transformations in the Coordinate Plane: Translations, Reflections, and Rotations

Section 2.1: Translations in the Coordinate Plane

  • Overview of Translations:

    • A translation is a transformation that slides a figure from one position to another without changing its size or shape.
  • Example 2: Translating a Figure in the Coordinate Plane:

    • Problem Statement: Translate the red triangle 33 units right and 33 units down. Find the coordinates of the image.
    • Original Vertices:
    • A(−2,1)A(-2, 1)
    • B(2,5)B(2, 5)
    • C(1,2)C(1, 2)

Translating a triangle on a coordinate plane

  • Method 1: Graphical Approach (Using a Coordinate Plane):

    1. Move each vertex of triangle ABCABC 33 units to the right and 33 units down on the grid.
    2. Connect the translated vertices to form the image.
    3. Label the new vertices as A′A', B′B', and C′C'.
    4. Read the coordinates directly from the coordinate plane:
      • A′(1,−2)A'(1, -2)
      • B′(5,2)B'(5, 2)
      • C′(4,−1)C'(4, -1)
  • Method 2: Algebraic Approach (Using Coordinate Rules):

    1. Add 33 to the x-coordinates of each original vertex to shift the figure 33 units to the right.
    2. Add −3-3 (or subtract 33) from the y-coordinates of each original vertex to shift the figure 33 units down.
    3. Perform calculations for each vertex:
      • Vertex AA:          A(−2,1)→A′(−2+3,1−3)→A′(1,−2)A(-2, 1) \rightarrow A'(-2 + 3, 1 - 3) \rightarrow A'(1, -2)
      • Vertex BB:          B(2,5)→B′(2+3,5−3)→B′(5,2)B(2, 5) \rightarrow B'(2 + 3, 5 - 3) \rightarrow B'(5, 2)
      • Vertex CC:          C(1,2)→C′(1+3,2−3)→C′(4,−1)C(1, 2) \rightarrow C'(1 + 3, 2 - 3) \rightarrow C'(4, -1)
    4. The coordinates of the resulting image are A′(1,−2)A'(1, -2), B′(5,2)B'(5, 2), and C′(4,−1)C'(4, -1).
    • Try It Exercises:
  • Exercise 3 (WHAT IF?):

    • Problem: The red triangle with original vertices A(−2,1)A(-2, 1), B(2,5)B(2, 5), and C(1,2)C(1, 2) is translated 44 units left and 22 units up. What are the coordinates of the image?

    • Algebraic Translation Procedure:

      • Subtract 44 from the x-coordinates and add 22 to the y-coordinates:         (x,y)→(x−4,y+2)(x, y) \rightarrow (x - 4, y + 2)
      • A(−2,1)→A′(−2−4,1+2)→A′(−6,3)A(-2, 1) \rightarrow A'(-2 - 4, 1 + 2) \rightarrow A'(-6, 3)
      • B(2,5)→B′(2−4,5+2)→B′(−2,7)B(2, 5) \rightarrow B'(2 - 4, 5 + 2) \rightarrow B'(-2, 7)
      • C(1,2)→C′(1−4,2+2)→C′(−3,4)C(1, 2) \rightarrow C'(1 - 4, 2 + 2) \rightarrow C'(-3, 4)
    • Image Coordinates: A′(−6,3)A'(-6, 3), B′(−2,7)B'(-2, 7), and C′(−3,4)C'(-3, 4).

    • Self-Assessment for Concepts & Skills:

  • Identifying a Translation:

    • Exercise 4: Compare the red figure and blue figure. Determine if the blue figure is a translation of the red figure.
      • Explanation: The blue parallelogram has the same orientation and shape as the red parallelogram, shifted diagonally. Thus, it is a translation.
    • Exercise 5: Compare the red triangle and blue triangle. Determine if the blue figure is a translation of the red figure.
      • Explanation: The red triangle points downward while the blue triangle points upward (inverted). Because the orientation has changed, the blue figure is not a translation of the red figure.
  • Translating a Figure Exercise:

    • Exercise 6:
      • Given: Vertices of a triangle are A(−2,−2)A(-2, -2), B(0,2)B(0, 2), and C(3,0)C(3, 0).
      • Transformation: Translate the triangle 11 unit left and 22 units up.
      • Coordinate Rule: (x,y)→(x−1,y+2)(x, y) \rightarrow (x - 1, y + 2)
      • Step-by-Step Calculation:
      • A(−2,−2)→A′(−2−1,−2+2)→A′(−3,0)A(-2, -2) \rightarrow A'(-2 - 1, -2 + 2) \rightarrow A'(-3, 0)
      • B(0,2)→B′(0−1,2+2)→B′(−1,4)B(0, 2) \rightarrow B'(0 - 1, 2 + 2) \rightarrow B'(-1, 4)
      • C(3,0)→C′(3−1,0+2)→C′(2,2)C(3, 0) \rightarrow C'(3 - 1, 0 + 2) \rightarrow C'(2, 2)
      • Image Coordinates: A′(−3,0)A'(-3, 0), B′(−1,4)B'(-1, 4), and C′(2,2)C'(2, 2).

Section 2.2: Reflections in the Coordinate Plane

  • Overview of Reflections:

    • A reflection is a transformation that flips a figure over a line of reflection (such as the x-axis or y-axis) to create a mirror image.
  • Example 2: Reflecting Figures:

    • Given Vertices: Triangle with vertices A(1,1)A(1, 1), B(1,4)B(1, 4), and C(3,4)C(3, 4).
    • Goal: Draw the figure and its reflection in (a) the x-axis and (b) the y-axis, and state the coordinates of the image.

Reflecting a triangle across the x-axis and y-axis

  • Part (a): Reflection in the x-axis:

    • Geometric Method:
      • Point AA is 11 unit above the x-axis; plot image point A′A' 11 unit below the x-axis.
      • Points BB and CC are 44 units above the x-axis; plot image points B′B' and C′C' 44 units below the x-axis.
      • Coordinates of image: A′(1,−1)A'(1, -1), B′(1,−4)B'(1, -4), and C′(3,−4)C'(3, -4).
    • Coordinate Rule (Another Method):
      • Take the opposite of each y-coordinate while keeping x-coordinates unchanged:         (x,y)→(x,−y)(x, y) \rightarrow (x, -y)
      • A(1,1)→A′(1,−1)A(1, 1) \rightarrow A'(1, -1)
      • B(1,4)→B′(1,−4)B(1, 4) \rightarrow B'(1, -4)
      • C(3,4)→C′(3,−4)C(3, 4) \rightarrow C'(3, -4)
  • Part (b): Reflection in the y-axis:

    • Geometric Method:

      • Points AA and BB are 11 unit to the right of the y-axis; plot image points A′A' and B′B' 11 unit to the left of the y-axis.
      • Point CC is 33 units to the right of the y-axis; plot image point C′C' 33 units to the left of the y-axis.
      • Coordinates of image: A′(−1,1)A'(-1, 1), B′(−1,4)B'(-1, 4), and C′(−3,4)C'(-3, 4).
    • Coordinate Rule:

      • Take the opposite of each x-coordinate while keeping y-coordinates unchanged:         (x,y)→(−x,y)(x, y) \rightarrow (-x, y)
      • A(1,1)→A′(−1,1)A(1, 1) \rightarrow A'(-1, 1)
      • B(1,4)→B′(−1,4)B(1, 4) \rightarrow B'(-1, 4)
      • C(3,4)→C′(−3,4)C(3, 4) \rightarrow C'(-3, 4)
    • Try It Exercises:

  • Exercise 3:

    • Given: Rectangle vertices A(−4,−3)A(-4, -3), B(−4,−1)B(-4, -1), C(−1,−1)C(-1, -1), and D(−1,−3)D(-1, -3).

    • Part (a) Reflection in the x-axis:

      • Rule: (x,y)→(x,−y)(x, y) \rightarrow (x, -y)
      • A(−4,−3)→A′(−4,3)A(-4, -3) \rightarrow A'(-4, 3)
      • B(−4,−1)→B′(−4,1)B(-4, -1) \rightarrow B'(-4, 1)
      • C(−1,−1)→C′(−1,1)C(-1, -1) \rightarrow C'(-1, 1)
      • D(−1,−3)→D′(−1,3)D(-1, -3) \rightarrow D'(-1, 3)
    • Part (b) Reflection in the y-axis:

      • Rule: (x,y)→(−x,y)(x, y) \rightarrow (-x, y)
      • A(−4,−3)→A′(4,−3)A(-4, -3) \rightarrow A'(4, -3)
      • B(−4,−1)→B′(4,−1)B(-4, -1) \rightarrow B'(4, -1)
      • C(−1,−1)→C′(1,−1)C(-1, -1) \rightarrow C'(1, -1)
      • D(−1,−3)→D′(1,−3)D(-1, -3) \rightarrow D'(1, -3)
    • Self-Assessment for Concepts & Skills:

  • Exercise 4: Reflecting a Figure:

    • Given: Vertices J(−3,−5)J(-3, -5), K(−2,2)K(-2, 2), and L(1,−4)L(1, -4).
    • Part (a) Reflection in the x-axis:
      • J(−3,−5)→J′(−3,5)J(-3, -5) \rightarrow J'(-3, 5)
      • K(−2,2)→K′(−2,−2)K(-2, 2) \rightarrow K'(-2, -2)
      • L(1,−4)→L′(1,4)L(1, -4) \rightarrow L'(1, 4)
    • Part (b) Reflection in the y-axis:
      • J(−3,−5)→J′(3,−5)J(-3, -5) \rightarrow J'(3, -5)
      • K(−2,2)→K′(2,2)K(-2, 2) \rightarrow K'(2, 2)
      • L(1,−4)→L′(−1,−4)L(1, -4) \rightarrow L'(-1, -4)
  • Exercise 5: Which One Doesn't Belong?:

    • Task: Determine which transformation of a baseball cap figure does not belong with the other three and explain reasoning.
    • Analysis:
      • Option 1: Two hats facing opposite directions mirrored across a vertical line (Reflection).
      • Option 2: Two hats facing the exact same direction shifted horizontally (Translation).
      • Option 3: Two hats facing opposite directions mirrored across a vertical line (Reflection).
      • Option 4: Two hats facing opposite directions mirrored across a vertical line (Reflection).
    • Conclusion & Reasoning: The second pair does not belong because it represents a translation (slide) where the orientation remains identical. The other three pairs represent reflections across a vertical line.

Section 2.3: Rotations in the Coordinate Plane

  • Key Concepts & Rules for Rotations:
    • Equivalence of Rotation Angles:
    • A counterclockwise rotation of n∘n^\circ is equivalent to a clockwise rotation of (360−n)∘(360 - n)^\circ.
    • A clockwise rotation of n∘n^\circ is equivalent to a counterclockwise rotation of (360−n)∘(360 - n)^\circ.
    • Congruence / Identity:
    • In a rotation, the original figure and its image are identical (congruent).
    • Coordinate Rules for Counterclockwise Rotations About the Origin (0,0)(0, 0):
    • 90∘90^\circ Counterclockwise Rotation:       (x,y)→(−y,x)(x, y) \rightarrow (-y, x)
    • 180∘180^\circ Rotation:       (x,y)→(−x,−y)(x, y) \rightarrow (-x, -y)
    • 270∘270^\circ Counterclockwise Rotation:       (x,y)→(y,−x)(x, y) \rightarrow (y, -x)
    • Direction Directionality for 180∘180^\circ Rotations:
    • A 180∘180^\circ clockwise rotation and a 180∘180^\circ counterclockwise rotation produce the exact same image. Therefore, direction does not need to be specified when rotating a figure 180∘180^\circ.

Rotations on a coordinate plane and rotating a trapezoid 180 degrees

  • Example 2: Rotating a Figure:

    • Problem: Vertices of a trapezoid are W(−4,2)W(-4, 2), X(−3,4)X(-3, 4), Y(−1,4)Y(-1, 4), and Z(−1,2)Z(-1, 2). Rotate the trapezoid 180∘180^\circ about the origin. What are the coordinates of the image?
    • Applied Coordinate Rule:
    • A point (x,y)(x, y) rotated 180∘180^\circ about the origin results in an image with coordinates (−x,−y)(-x, -y).
    • Step-by-Step Coordinate Transformations:
    • W(−4,2)→W′(4,−2)W(-4, 2) \rightarrow W'(4, -2)
    • X(−3,4)→X′(3,−4)X(-3, 4) \rightarrow X'(3, -4)
    • Y(−1,4)→Y′(1,−4)Y(-1, 4) \rightarrow Y'(1, -4)
    • Z(−1,2)→Z′(1,−2)Z(-1, 2) \rightarrow Z'(1, -2)
    • Image Coordinates: W′(4,−2)W'(4, -2), X′(3,−4)X'(3, -4), Y′(1,−4)Y'(1, -4), and Z′(1,−2)Z'(1, -2).
  • Try It Exercises:

    • Exercise 3:
    • Given Vertices: J(−4,−4)J(-4, -4), K(−4,2)K(-4, 2), L(−1,0)L(-1, 0), and M(−2,−3)M(-2, -3).
    • Transformation: Rotate 180∘180^\circ about the origin.
    • Rule: (x,y)→(−x,−y)(x, y) \rightarrow (-x, -y)
    • Calculations:
      • J(−4,−4)→J′(4,4)J(-4, -4) \rightarrow J'(4, 4)
      • K(−4,2)→K′(4,−2)K(-4, 2) \rightarrow K'(4, -2)
      • L(−1,0)→L′(1,0)L(-1, 0) \rightarrow L'(1, 0)
      • M(−2,−3)→M′(2,3)M(-2, -3) \rightarrow M'(2, 3)
    • Image Coordinates: J′(4,4)J'(4, 4), K′(4,−2)K'(4, -2), L′(1,0)L'(1, 0), and M′(2,3)M'(2, 3).
    • Exercise 4:
    • Given Vertices: P(−3,2)P(-3, 2), Q(6,1)Q(6, 1), and R(−1,−5)R(-1, -5).
    • Transformation: Rotate 90∘90^\circ counterclockwise about the origin.
    • Rule: (x,y)→(−y,x)(x, y) \rightarrow (-y, x)
    • Calculations:
      • P(−3,2)→P′(−2,−3)P(-3, 2) \rightarrow P'(-2, -3)
      • Q(6,1)→Q′(−1,6)Q(6, 1) \rightarrow Q'(-1, 6)
      • R(−1,−5)→R′(5,−1)R(-1, -5) \rightarrow R'(5, -1)
    • Image Coordinates: P′(−2,−3)P'(-2, -3), Q′(−1,6)Q'(-1, 6), and R′(5,−1)R'(5, -1).
    • Exercise 5:
    • Given Vertices: A(5,3)A(5, 3), B(4,−1)B(4, -1), and C(1,−1)C(1, -1).
    • Transformation: Rotate 90∘90^\circ clockwise about the origin.
    • Equivalence Note: A 90∘90^\circ clockwise rotation is equivalent to a 270∘270^\circ counterclockwise rotation.
    • Rule: (x,y)→(y,−x)(x, y) \rightarrow (y, -x)
    • Calculations:
      • A(5,3)→A′(3,−5)A(5, 3) \rightarrow A'(3, -5)
      • B(4,−1)→B′(−1,−4)B(4, -1) \rightarrow B'(-1, -4)
      • C(1,−1)→C′(−1,−1)C(1, -1) \rightarrow C'(-1, -1)
    • Image Coordinates: A′(3,−5)A'(3, -5), B′(−1,−4)B'(-1, -4), and C′(−1,−1)C'(-1, -1).