Differentiating polynomials

Power Rule of Derivatives

  • The power rule states that the derivative with respect to x of xnx^n is equal to nxn1n \cdot x^{n-1} for n0n \neq 0.

  • It allows us to take the derivative of any polynomial, making it a fundamental concept in calculus.

Special Case for n = 0

  • When considering the case of n=0n = 0, we look at the derivative of x0x^0.

  • For any x0x \neq 0, x0=1x^0 = 1, which means:

    • ddx(x0)=ddx(1)\frac{d}{dx}(x^0) = \frac{d}{dx}(1)

  • Graphing the function f(x)=1f(x) = 1 shows it is a horizontal line on the Cartesian plane:

    • The slope of the tangent line at any point on this graph is 00.

  • Conclusion: The derivative of a constant function (such as f(x)=af(x) = a where aa is a constant) is always zero:

    • ddx(a)=0\frac{d}{dx}(a) = 0.

Properties of Derivatives

Scalar Multiplication Property

  • If AA is a constant and f(x)f(x) is a function, then:

    • ddx(Af(x))=Addx(f(x))\frac{d}{dx}(A \cdot f(x)) = A \cdot \frac{d}{dx}(f(x))

  • Example:

    • Find the derivative of 2x52 \cdot x^5:

    • Using the property: ddx(2x5)=2ddx(x5)\frac{d}{dx}(2 \cdot x^5) = 2 \cdot \frac{d}{dx}(x^5)

    • Applying the power rule:

      • ddx(x5)=5x51=5x4\frac{d}{dx}(x^5) = 5x^{5-1} = 5x^4

    • Therefore, the derivative is: 25x4=10x42 \cdot 5x^4 = 10x^4.

Sum Rule of Derivatives

  • For two functions f(x)f(x) and g(x)g(x), the derivative of their sum is:

    • ddx(f(x)+g(x))=ddx(f(x))+ddx(g(x))\frac{d}{dx}(f(x) + g(x)) = \frac{d}{dx}(f(x)) + \frac{d}{dx}(g(x))

  • Alternative notation:

    • If f(x)f'(x) denotes the derivative of f(x)f(x), then:

    • ddx(f(x)+g(x))=f(x)+g(x)\frac{d}{dx}(f(x) + g(x)) = f'(x) + g'(x)

  • Example:

    • Find the derivative of x3+x4x^3 + x^{-4}:

    • Using the sum rule, we differentiate each part:

      • ddx(x3)=3x31=3x2\frac{d}{dx}(x^3) = 3x^{3-1} = 3x^2

      • ddx(x4)=4x41=4x5\frac{d}{dx}(x^{-4}) = -4x^{-4-1} = -4x^{-5}

    • Combine the results:

      • 3x24x53x^2 - 4x^{-5}.

Composite Example Derivative Calculation

  • Given f(x)=2x37x2+3x100f(x) = 2x^3 - 7x^2 + 3x - 100, we calculate:

  1. ddx(2x3)\frac{d}{dx}(2x^3):

    • Use scalar multiplication and power rule:

    • 2ddx(x3)=2(3x31)=6x22 \cdot \frac{d}{dx}(x^3) = 2 \cdot (3x^{3-1}) = 6x^2

  2. ddx(7x2)\frac{d}{dx}(-7x^2):

    • 7ddx(x2)=7(2x21)=14x-7 \cdot \frac{d}{dx}(x^2) = -7 \cdot (2x^{2-1}) = -14x

  3. ddx(3x)\frac{d}{dx}(3x):

    • 3ddx(x)=31=33 \cdot \frac{d}{dx}(x) = 3 \cdot 1 = 3

  4. ddx(100)\frac{d}{dx}(-100):

    • Derivative of any constant is 00.

  • Combining these results, we find:

    • f(x)=6x214x+3f'(x) = 6x^2 - 14x + 3.

Implications and Applications

  • Understanding these rules enables us to easily find the derivatives of complex polynomials and develop further into more advanced calculus topics.

  • These foundational properties apply universally across a range of mathematical and engineering contexts, aiding in application problems involving rates of change, optimization processes, and graphical analysis.