Notes on Simple Harmonic Motion

Class 1: Simple Harmonic Motion

Date: 17 March 2026
Time: 17:20

Definition of Periodic Motion

  • Oscillatory Motion: Movement characterized by back-and-forth motion, exemplified by a child swinging on a swing.

  • Periodic Function: Motion that repeats after a fixed interval of time. The mathematical representation is:

    • f(t+nT)=f(t)f(t+nT) = f(t)

  • Time Period (T): The time taken to complete one full cycle of periodic motion. Example: Earth's motion around the Sun takes about 365 days and 4 hours.

Simple Harmonic Motion (SHM)

  • SHM Definition: A type of periodic motion where an object oscillates back and forth along the same path.

    • The motion is driven by a restoring force that is directly proportional to the object's displacement from its equilibrium position and directed towards that position.

Everyday Examples of SHM
  • Child swinging on a swing

  • Ticking of a clock's pendulum

  • A plucked guitar string

Restoring Force

  • Restoring Force (F_R):

    • F= -Kx

    • Defined as the force acting to restore an object to its equilibrium position.

    • The restoring force is opposite to the displacement (x) and proportional in magnitude, where K is the spring constant.

Newton's Second Law in SHM
  • The relationship between force, mass, and acceleration is given by:

    • F=maF = ma

    • Thus, when considering SHM, we have:

    • ma=kxma = -kx

    • Rearranging gives:

    • a=rackmxa = - rac{k}{m}x

Characteristics of SHM

  • The acceleration (a) of the object is directly proportional to its displacement (x) and acts in the opposite direction:

    • aextisproportionaltoxa ext{ is proportional to } -x

Systems Exhibiting SHM

  • Different systems can exhibit SHM; notable examples include:

    • Object-Ideal Spring System

    • Pendulum

Conditions for Simple Harmonic Motion

  • The presence of a restoring force that acts in the opposite direction of the object's displacement is necessary.

  • The restoring force must be directly proportional to the object's displacement from equilibrium.

Pendulum Conditions
  • A pendulum involves angular displacement, requiring a restoring torque:

    • The restoring torque must also be proportional to angular displacement but directed oppositely.

  • Applicable only for small angular displacements.

Mathematical Relationships for Pendulum

  • Angular relationships for small angles involve using:

    • hetaextinradiansheta ext{ in radians}

    • For small angles, an(heta)extandhetaextareapproximatelyequalan( heta) ext{ and } heta ext{ are approximately equal}

Kinematics and Dynamics in SHM

  • For SHM, the period (T) can be expressed as:

    • T=2racextπωT = 2 rac{ ext{π}}{ω}

    • The angular frequency (ω) relationships:

    • ω2=racgLω^2 = rac{g}{L}

    • where g is the acceleration due to gravity and L is the length of the pendulum.

Key Parameters in SHM

  • Amplitude: Maximum distance from the equilibrium position.

  • Equilibrium Position: The point where net force is zero.

  • Restoring Force: Force acting to bring the object back to equilibrium.

  • Period (T): Time to complete one cycle of motion.

  • Frequency (f): Number of cycles per second, represented as:

    • f=rac1Tf = rac{1}{T}

Kinematics Relationships
  • For maximum velocity in an SHM, use:

    • Vmax=AimesωV_{max} = A imes ω

Sample Problem A

Problem: Calculating the spring constant (k) of a spring stretched by a mass weight.

  • Given: Mass (m) = 0.55 kg, stretch from equilibrium position (x) = 2.0 cm = 0.02 m.

    • k=racmgxk = rac{mg}{x}

    • Calculate gravitational force:

    • mg=0.55imes9.81ext(whichresultsin5.3955N)mg = 0.55 imes 9.81 ext{ (which results in 5.3955 N)}

    • Now using the earlier equation for k:

    • k=rac5.39550.02=269.775extN/mk = rac{5.3955}{0.02} = 269.775 ext{ N/m}

Energy Considerations
  • Potential energy in the spring is calculated by:

    • EP.E=rac12kA2E_P.E = rac{1}{2} k A^2

  • At maximum displacement (amplitude), potential energy is maximized while kinetic energy (E_K) is zero.

  • At equilibrium position, potential energy is zero and kinetic energy is maximized:

    • E.P.Emax=rac12kA2E.P.E_{max} = rac{1}{2}kA^2

    • Using conservation of energy, we can derive the maximum speed:

    • Vmax=racAext,kextandωV_{max} = rac{A ext{, k} ext{ and } ω}

Final Kinematic Relationships

  • For an oscillating mass on a spring, the expressions are as follows:

    • x(t)=Aextcos(ωt)x(t) = A ext{cos(}ωt)

    • Vmax=ωAV_{max} = ωA

    • extWhere:ω=extangularfrequency=rac2extπText{Where: } ω = ext{angular frequency} = rac{2 ext{π}}{T}

Conclusion

  • All learned principles apply to multiple systems, underscoring the universality of SHM across various physical contexts.

  • The relationship between force, displacement, and acceleration in SHM provides foundational insights for more complex oscillatory systems.