SF1625 Envariabel - Continuity
Continuity
Key Concepts
- Interior Point: A point within an interval that is not an endpoint.
- Endpoint: The boundary values of an interval.
- Continuity at a Point: A function is continuous at if is defined in a neighborhood of and .
- Right Continuity: A function is right-continuous at if is defined on some interval and .
- Left Continuity: A function is left-continuous at if is defined on some interval and .
- Continuous Function: A function that is continuous at every point in its domain.
- Discontinuous Function: A function that is not continuous at one or more points in its domain.
Intervals
- Open Interval: I = {x : a < x < b} = (a, b) (also )
- Closed Interval: ()
- Half-Open Interval: I = {x : a \leq x < b} = [a, b)
Definition 4 (Continuity at a Point)
- A function is continuous at a point if:
- is defined in a neighborhood of .
Right and Left Continuity
- Right Continuity at x = a: is defined in some interval and .
- Left Continuity at x = b: is defined in some interval and .
Theorem 5
A function is continuous at if and only if it is both right- and left-continuous at .
- A function is continuous at its left endpoint if it is right-continuous there.
- A function is continuous at its right endpoint if it is left-continuous there.
- A function is continuous on an interval if it is continuous at every point in the interval.
Definition 7
A function is a continuous function if it is continuous at every point in its domain.
Examples of Functions
Function 1:
Function 2:
Function 3:
Examples and Exercises
- Sketch the graphs of the three functions.
- Identify points of continuity and discontinuity for each function.
- Determine intervals on which the functions are continuous.
- Classify which functions are continuous functions.
Properties of Continuous Functions
Elementary functions are continuous, including:
- Polynomials
- Rational functions
- Trigonometric functions and their inverses (arcus functions)
- Power functions ()
- Exponential functions () and logarithmic functions (
- Absolute value function
Combinations and compositions of elementary functions using the four arithmetic operations are also continuous (Theorems 6 and 7).
- Example:
Example 5
Is a continuous function?
Example 6
Is the Heaviside function a continuous function?
Example 7
Let .
- a) Determine the domain of f.
- b) Identify points where f is continuous, right-continuous, and left-continuous.
- c) Determine if f is odd, even, or neither.
- d) Is f bounded?
Continuous Extensions
Example 8
Determine the constant such that the function is continuous:
Example 9
The function is defined for all . Can its definition be extended to such that the resulting function is continuous on all of ? In other words, does there exist a continuous function on such that for all ? If such a exists, it is a continuous extension of .
Properties of Continuous Functions
Theorem 8 – The Min-Max Theorem
If is continuous on the closed, finite interval , then there exist numbers and in such that for every in the interval, .
- has its absolute minimum value at , .
- has its absolute maximum value at , .
Theorem 9 – The Intermediate-Value Theorem
If is a continuous function on the interval , and is a number between and , then there exists a point , such that .
- If is not continuous, nothing can be said about intermediate values.
Example 10
Does the Intermediate-Value Theorem apply to the Heaviside function on the interval ?
- and , but there is no value in the interval that yields . This does not contradict the theorem because is not continuous.
Example 11
Show that the equation has a solution in the interval .
Bisection Method
If f(a) \cdot f(b) < 0 and is continuous on the interval , then a root can be numerically found using the bisection method with arbitrary accuracy.
Bisection Method Steps
- Take a new point in the middle of the interval: and calculate the function value at that point, .
- If has the same sign as , then there is a root between and . Let be the new lower bound of the interval.
- If has the same sign as , then there is a root between and . Let be the new upper bound of the interval.
- Repeat the process until the interval is sufficiently small.
Example 12
Determine the solution to the equation with an error of at most 0.2 using the bisection method.
Existence Proofs
- Why are existence proofs important?
- It ensures that calculations are meaningful and lead to valid solutions.
Example 13
Solve the system of equations:
- Subtracting equation 1 from equation 2 gives . Substituting into equation 1 gives . However, these values do not satisfy equation 3, indicating the system has no solution.
Example 14
Find the largest positive integer.
Assume the largest integer is . Then is also an integer, and .
The only positive integer solution is , which is incorrect.
This example illustrates that if a problem has no solution, calculations might produce an incorrect answer. Demonstrating existence of a solution before attempting to find it is important.