Sum and Difference Identities in Trigonometry

The Number One Mistake in Trigonometry

  • The common mistake is assuming that the sine of a sum of angles is equal to the sum of their sines.
    sin(a + b) ≠ sin(a) + sin(b)
  • This incorrect assumption would simplify trigonometry, but it's not valid.

Illustration with Sine of 75 Degrees

  • To demonstrate the mistake, let's calculate sin(75°).
  • 75 degrees can be expressed as 45° + 30°.
  • If the initial assumption were correct:
    sin(75°) = sin(45°) + sin(30°)

Calculations Using Special Angles

  • sin(45°) = sin(\frac{π}{4}) = \frac{\sqrt{2}}{2}
  • sin(30°) = sin(\frac{π}{6}) = \frac{1}{2}
  • Adding these:
    \frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{\sqrt{2} + 1}{2}
  • Approximation:
    \frac{1.4 + 1}{2} ≈ 1.2
  • This would imply that sin(75°) = 1.2.

The Contradiction

  • The sine of any angle cannot be greater than 1 because on the unit circle, the y-coordinate of any point is always less than or equal to 1.
  • Therefore, the initial assumption sin(a + b) = sin(a) + sin(b) is incorrect.

The Correct Formula: Sine of a Sum Identity

  • The correct identity for the sine of a sum is:
    sin(a + b) = sin(a)cos(b) + cos(a)sin(b)

Applying the Correct Formula to Sine of 75 Degrees

  • Using the correct formula to find sin(75°)
    sin(75°) = sin(45°)cos(30°) + cos(45°)sin(30°)

Calculations with the Sine of a Sum Identity

  • sin(45°) = \frac{\sqrt{2}}{2}
  • cos(30°) = \frac{\sqrt{3}}{2}
  • cos(45°) = \frac{\sqrt{2}}{2}
  • sin(30°) = \frac{1}{2}
  • Therefore:
    sin(75°) = \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} = \frac{\sqrt{6} + \sqrt{2}}{4}

Sine of a Difference Identity

  • The identity for the sine of a difference is:
    sin(a - b) = sin(a)cos(b) - cos(a)sin(b)

Example: Sine of 15 Degrees

  • Let's calculate sin(15°), where 15° = 45° - 30°
  • sin(15°) = sin(45°)cos(30°) - cos(45°)sin(30°) = \frac{\sqrt{6} - \sqrt{2}}{4}

Cosine of a Sum and Difference Identities

  • Cosine of a sum:
    cos(a + b) = cos(a)cos(b) - sin(a)sin(b)
  • Cosine of a difference:
    cos(a - b) = cos(a)cos(b) + sin(a)sin(b)

Example: Cosine of 15 Degrees

  • Using the cosine difference identity to find cos(15°), where 15° = 45° - 30°
  • cos(15°) = cos(45°)cos(30°) + sin(45°)sin(30°) = \frac{\sqrt{6} + \sqrt{2}}{4}

Observation: cos(15°) and sin(75°) are Equal

  • The result for cos(15°) is the same as sin(75°).
  • Explanation: On the unit circle, 15° and 75° are mirror images about the line y = x, so their x and y coordinates (cosine and sine values) are switched.

Tangent of a Sum and Difference Identities

  • Tangent of a sum:
    tan(a + b) = \frac{tan(a) + tan(b)}{1 - tan(a)tan(b)}
  • Tangent of a difference:
    tan(a - b) = \frac{tan(a) - tan(b)}{1 + tan(a)tan(b)}

Example: Tangent of \frac{7π}{12}

  • Let's find tan(\frac{7π}{12}), where \frac{7π}{12} = \frac{π}{4} + \frac{π}{3}
  • tan(\frac{7π}{12}) = \frac{tan(\frac{π}{4}) + tan(\frac{π}{3})}{1 - tan(\frac{π}{4})tan(\frac{π}{3})}

Calculations and Result

  • tan(\frac{π}{4}) = 1
  • tan(\frac{π}{3}) = \sqrt{3}
  • Therefore:
    tan(\frac{7π}{12}) = \frac{1 + \sqrt{3}}{1 - \sqrt{3}}

Conclusion

  • Using sum and difference identities, sine, cosine and tangent can be calculated for a multitude of angles based on memorized angles on the unit circle.
  • These identities work in both degrees and radians.