Sum and Difference Identities in Trigonometry
The Number One Mistake in Trigonometry
- The common mistake is assuming that the sine of a sum of angles is equal to the sum of their sines.
sin(a + b) ≠ sin(a) + sin(b) - This incorrect assumption would simplify trigonometry, but it's not valid.
Illustration with Sine of 75 Degrees
- To demonstrate the mistake, let's calculate sin(75°).
- 75 degrees can be expressed as 45° + 30°.
- If the initial assumption were correct:
sin(75°) = sin(45°) + sin(30°)
Calculations Using Special Angles
- sin(45°) = sin(\frac{π}{4}) = \frac{\sqrt{2}}{2}
- sin(30°) = sin(\frac{π}{6}) = \frac{1}{2}
- Adding these:
\frac{\sqrt{2}}{2} + \frac{1}{2} = \frac{\sqrt{2} + 1}{2} - Approximation:
\frac{1.4 + 1}{2} ≈ 1.2 - This would imply that sin(75°) = 1.2.
The Contradiction
- The sine of any angle cannot be greater than 1 because on the unit circle, the y-coordinate of any point is always less than or equal to 1.
- Therefore, the initial assumption sin(a + b) = sin(a) + sin(b) is incorrect.
- The correct identity for the sine of a sum is:
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
- Using the correct formula to find sin(75°)
sin(75°) = sin(45°)cos(30°) + cos(45°)sin(30°)
Calculations with the Sine of a Sum Identity
- sin(45°) = \frac{\sqrt{2}}{2}
- cos(30°) = \frac{\sqrt{3}}{2}
- cos(45°) = \frac{\sqrt{2}}{2}
- sin(30°) = \frac{1}{2}
- Therefore:
sin(75°) = \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} = \frac{\sqrt{6} + \sqrt{2}}{4}
Sine of a Difference Identity
- The identity for the sine of a difference is:
sin(a - b) = sin(a)cos(b) - cos(a)sin(b)
Example: Sine of 15 Degrees
- Let's calculate sin(15°), where 15° = 45° - 30°
- sin(15°) = sin(45°)cos(30°) - cos(45°)sin(30°) = \frac{\sqrt{6} - \sqrt{2}}{4}
Cosine of a Sum and Difference Identities
- Cosine of a sum:
cos(a + b) = cos(a)cos(b) - sin(a)sin(b) - Cosine of a difference:
cos(a - b) = cos(a)cos(b) + sin(a)sin(b)
Example: Cosine of 15 Degrees
- Using the cosine difference identity to find cos(15°), where 15° = 45° - 30°
- cos(15°) = cos(45°)cos(30°) + sin(45°)sin(30°) = \frac{\sqrt{6} + \sqrt{2}}{4}
Observation: cos(15°) and sin(75°) are Equal
- The result for cos(15°) is the same as sin(75°).
- Explanation: On the unit circle, 15° and 75° are mirror images about the line y = x, so their x and y coordinates (cosine and sine values) are switched.
Tangent of a Sum and Difference Identities
- Tangent of a sum:
tan(a + b) = \frac{tan(a) + tan(b)}{1 - tan(a)tan(b)} - Tangent of a difference:
tan(a - b) = \frac{tan(a) - tan(b)}{1 + tan(a)tan(b)}
Example: Tangent of \frac{7π}{12}
- Let's find tan(\frac{7π}{12}), where \frac{7π}{12} = \frac{π}{4} + \frac{π}{3}
- tan(\frac{7π}{12}) = \frac{tan(\frac{π}{4}) + tan(\frac{π}{3})}{1 - tan(\frac{π}{4})tan(\frac{π}{3})}
Calculations and Result
- tan(\frac{π}{4}) = 1
- tan(\frac{π}{3}) = \sqrt{3}
- Therefore:
tan(\frac{7π}{12}) = \frac{1 + \sqrt{3}}{1 - \sqrt{3}}
Conclusion
- Using sum and difference identities, sine, cosine and tangent can be calculated for a multitude of angles based on memorized angles on the unit circle.
- These identities work in both degrees and radians.