Thermodynamics of Biological Systems

Thermodynamics and Metabolism

  • Thermodynamics is crucial in understanding metabolism because it deals with the relationships between heat, work, and energy.
  • It involves the transfer of energy between a system and its surroundings, or the conversion of energy from one form to another.
  • The laws of thermodynamics govern the behavior of all systems, including biological ones, helping to explain why certain reactions occur spontaneously while others do not.

Gibbs Free Energy (G)

  • The spontaneity of a reaction is determined by both enthalpy (H) and entropy (S).
  • Gibbs free energy (G) is expressed as: G=HTSG = H - TS

Internal Energy (E) and Enthalpy (H)

  • Internal energy (E) is the sum of all energies within a system, measured in Joules.
  • For closed systems, internal energy relates to the total energy of the molecules within the system.
  • Enthalpy (H) is defined as: H=E+PVH = E + PV where P is pressure and V is volume.
  • Change in enthalpy is given by: ΔH=ΔE+PΔV\Delta H = \Delta E + P\Delta V
  • In biochemical processes occurring in liquids, the change in volume (ΔV\Delta V) is often negligible, thus: ΔHΔE\Delta H \approx \Delta E

Enthalpy (H) and Bond Energies

  • Atoms in a bond are in a lower energy state compared to unbound atoms.
  • Energy is released when bonds form (heat).
  • Energy is required to break bonds.
  • Each molecule has characteristic bond energies. For example:
    • C-C bond: 347 kJ/mol347 \text{ kJ/mol}
    • C=C bond: 614 kJ/mol614 \text{ kJ/mol}

Enthalpy Change in Reactions

  • For reactions, the enthalpy change (ΔH\Delta H) relates to energy changes due to bond breaking and formation:
    ΔEΔH\Delta E \approx \Delta H
  • ΔE\Delta E is the energy used to break bonds plus the energy released when bonds form.
  • If energy used to break bonds > energy released when bonds form: ΔEΔH\Delta E \approx \Delta H is positive, indicating an endothermic reaction.
  • If energy used to break bonds < energy released when bonds form: ΔEΔH\Delta E \approx \Delta H is negative, indicating an exothermic reaction.

Second Law of Thermodynamics and Entropy (S)

  • Systems tend to move from ordered (low entropy) to disordered states (high entropy).
  • The entropy of the universe (system and surroundings) is unchanged in reversible processes and increases in irreversible processes.
  • ΔS<em>universe=ΔS</em>system+ΔSsurroundings0\Delta S<em>{\text{universe}} = \Delta S</em>{\text{system}} + \Delta S_{\text{surroundings}} \geq 0
  • Entropy (S) represents energy unavailable to do work and measures the disorder of a system.

Gibbs Free Energy (G) and Spontaneity

  • For any reaction at constant temperature (T) and pressure:
    ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S
  • Based on the second law of thermodynamics:
    • If ΔG\Delta G is negative, the reaction is spontaneous.
    • If ΔG\Delta G is positive, the reaction is non-spontaneous.

Standard State Reactions

  • A standard state is defined to compare thermodynamic parameters of different reactions.
  • For a reaction A+BC+DA + B \leftrightarrow C + D, the standard state is when the concentration of reactants and products are at 1M.
  • Thermodynamic parameters in the standard state are indicated by "\circ ", e.g., H,S,GH^\circ, S^\circ, G^\circ
  • The standard state for H+H^+ ions corresponds to pH ~ 0.
  • For biological systems, a modified standard state (designated by "\circ' ") is used at pH 7.

Spontaneous Reactions and Concentration

  • If ΔG\Delta G is negative, the reaction is spontaneous at a given temperature T.
  • If ΔG\Delta G is positive, the reaction is non-spontaneous at a given temperature T.
  • The influence of concentration on spontaneity is given by: ΔG=ΔG+RTln[C][D][A][B]\Delta G = \Delta G^\circ + RT \ln \frac{[C][D]}{[A][B]}
    • T = temperature in Kelvin (K)
    • R = gas constant (8.314 J/mol·K)

Calculating ΔG\Delta G

  • For the reaction [A][B]+[C][A] \leftrightarrow [B] + [C] with ΔG=0.0 kJ/mol\Delta G^\circ = 0.0 \text{ kJ/mol}
  • ΔG=ΔG+RTln[B][C][A]\Delta G = \Delta G^\circ + RT \ln \frac{[B][C]}{[A]}
  • Given conditions at 310K:
    • Condition 1: [A] = 1×1031 \times 10^{-3} M, [B] = 1×1061 \times 10^{-6} M, [C] = 1×1021 \times 10^{-2} M
    • Condition 2: [A] = 1×1061 \times 10^{-6} M, [B] = 1×1031 \times 10^{-3} M, [C] = 1×1021 \times 10^{-2} M

Spontaneity and ΔG\Delta G

  • If ΔG\Delta G is negative, the reaction is spontaneous at a given temperature T.
  • If ΔG\Delta G is positive, the reaction is non-spontaneous at a given temperature T.
  • For the reaction A+BC+DA + B \leftrightarrow C + D, the spontaneity depends on the concentrations: ΔG=ΔG+RTln[C][D][A][B]\Delta G = \Delta G^\circ + RT \ln \frac{[C][D]}{[A][B]}
    • T = temperature in Kelvin (K)
    • R = gas constant (8.314 J/mol·K)
  • ΔG\Delta G is negative when \Delta G^\circ + RT \ln \frac{[C][D]}{[A][B]} < 0
  • Since R and T are constant, RTln[C][D][A][B]RT \ln \frac{[C][D]}{[A][B]} depends on the concentration of reactants and products.

High Energy Compounds

  • These compounds have large negative free energies of hydrolysis.
  • Example: ATP hydrolysis: ATP+H<em>2OADP+P</em>iATP + H<em>2O \rightarrow ADP + P</em>i with \Delta G^\circ' = -30.5 \text{ kJ/mol}
  • These compounds are transient forms of stored energy, carrying energy from one reaction to another.
  • High energy does not equate to instability; the activation energy needed to break the O-P bond in ATP is between 200 - 400 kJ/mol.

ATP Hydrolysis

  • The hydrolysis of ATP involves a phosphoryl group transfer potential of approximately 30.5 kJ/mol-30.5 \text{ kJ/mol}.

Coupled Reactions

  • A coupled reaction involves the product of one reaction serving as the substrate for another, or sharing a common intermediate.
  • This allows reactions to proceed against their thermodynamic potential (i.e., in the direction of a positive ΔG\Delta G).
  • The energy released from a thermodynamically favorable reaction can drive a thermodynamically unfavorable reaction, as long as the overall ΔG\Delta G is negative.
  • Example:
    • Glucose+P<em>iGlucose 6-P+H</em>2OGlucose + P<em>i \rightarrow Glucose \text{ 6-P} + H</em>2O \Delta G^\circ' = 13.8 \text{ kJ/mol}
    • ATP+H<em>2OADP+P</em>iATP + H<em>2O \rightarrow ADP + P</em>i \Delta G^\circ' = -30.5 \text{ kJ/mol}
    • Coupled reaction: Glucose+ATPGlucose 6P+ADPGlucose + ATP \rightarrow Glucose \text{ 6P} + ADP \Delta G^\circ' = -16.7 \text{ kJ/mol}