L’Hôpital’s Rule & Indeterminate Forms — Study Notes

Session logistics and course updates

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  • Scheduling: once the other section is added, sessions’ times will be finalized.
  • Homework schedule:
    • Homework 2 is due next week (homework indexed by week).
    • Homework 1 had no assignment; due Thursday before midnight on Gradescope.
    • Homework problems include ENV (engineering problems) to align MAP 2029 with engineering problems; PDF available on Brightspace → content → syllabus → download.
  • Quizzes: there will be a quiz every Thursday based on the homework and discussion.
  • Moving into a regular rhythm: weekly homework due Thursdays and quizzes on Thursdays.

Course content and current topic

  • We are continuing in Chapter 5, section 5.8a: L’Hôpital’s rule.
  • Focus: indeterminate forms zero over zero (0/0) and infinity over infinity (∞/∞).
  • Recap from calculus 1: certain forms like 0/0 can yield many possible limits unless you do more work; L’Hôpital’s rule helps determine the limit when applicable.
  • The rule is:
    • If

      rac{f(x)}{g(x)} o ext{ indeterminate form } 0/0 ext{ or } rac{ ext{∞}}{ ext{∞}}

      as x o a (where a may be finite or infinite),
      ext{and } f ext{ and } g ext{ are differentiable near } a,

      then

      rac{f(x)}{g(x)} o rac{f'(x)}{g'(x)}
      as x o a, provided the limit on the right exists.
  • Important nuance: this is not the quotient rule; it is a separate rule that asks you to differentiate the numerator and denominator and then evaluate the limit of the new quotient.
  • Notation: some people write L’Hôpital’s rule as L' (or L’Ho) to emphasize differentiating; the instructor emphasizes clearly indicating when L’Hôpital has been used.
  • Conditions to emphasize for exams/graded work: always identify the indeterminate form before applying L’Hôpital; and distinguish between numbers, +∞, -∞, and does-not-exist when reporting limits.

Indeterminate forms and their classifications

  • Primary indeterminate forms to use L’Hôpital for (the “green” forms):
    • 0/0
    • ∞/∞
  • Cautionary forms (the “orange” forms) where L’Hôpital can still be useful but require tricks or manipulation to convert to a quotient form that is 0/0 or ∞/∞:
    • ∞ · 0
    • 0 · ∞
    • ∞ − ∞
  • Exponential indeterminate forms handled with a logarithm trick:
    • 0^0
    • ∞^0
    • 1^∞
  • The three “flavors” of limits discussed: numbers, +∞, -∞, and does-not-exist. These distinctions matter for full credit on exams.
  • A practical reminder: you can apply L’Hôpital multiple times if each subsequent application remains valid (i.e., the form stays 0/0 or ∞/∞ after each differentiation). You may need to simplify algebraically between steps.

Tricks and techniques to apply L’Hôpital beyond the basic 0/0 and ∞/∞

  • If the limit is not initially in a 0/0 or ∞/∞ form, create one via algebraic manipulation:
    • Convert products to quotients (e.g., transform ∞ · 0 to a quotient by inverting a factor).
    • Use reciprocal forms to create a quotient (e.g., rewrite a product or reciprocal to form a ratio).
    • Use sublimits for complex expressions (see below).
  • Sublimits (for complex indeterminate forms like ∞ − ∞):
    • Identify a sublimit by factoring out the dominant term to isolate a part of the expression.
    • Evaluate the sublimit separately (often using L’Hôpital), then infer the behavior of the original limit from the sublimit.
    • Example logic: if you can write the limit as (something) / (something else) and you can show the sublimit of a portion tends to ∞, 0, or a finite value, you can deduce the overall limit after algebraic simplification.
  • When dealing with ∞ − ∞, a common approach is to factor out the dominant growth term and form a quotient that can be treated with L’Hôpital.
  • For products that resemble ∞ · 0, rewrite as a quotient (e.g., as (ln x) / (1/x) or x / (1/x)) to create a 0/0 or ∞/∞ form.
  • Pattern recognition for using log tricks with exponentials:
    • If you have an expression of the form f(x)^{g(x)} with f(x) → 1 and g(x) → ∞, take logarithms to bring the exponent down and study the limit of the logarithm.
    • Then exponentiate to recover the original limit.

Growth-rate intuition and its practical implications

  • Growth-rate hierarchy (useful for quick judgments about limits and time complexity):

    rac{

    }

    • ln x grows slower than any power of x
    • x grows faster than ln x:
      rac{

    }{x} o 0 ext{ as } x o \n

    • e^x dominates any polynomial in x: for any positive integer n,
      rac{x^n}{e^x} o 0 ext{ as } x o \n
    • Therefore e^x grows much faster than any polynomial; Ln x grows slower than x, and e^x grows fastest among these basic functions.
  • Practical takeaway for problem solving:

    • If you see a quotient with an exponential in the numerator or denominator, expect quick divergence to ∞ or 0 after a single L’Hôpital step.
    • For expressions like e^x/p(x), often you’ll get ∞ after differentiation because e^x is its own derivative.
    • When comparing growth rates, Ln x/x → 0, and e^x/x → ∞ as x → ∞.
  • Connection to broader concepts: recognizing growth rates helps anticipate when a limit will diverge or converge and informs algorithmic complexity considerations (e.g., exponential time vs polynomial time).

Worked examples (step-by-step, reflecting the transcript)

  • Example 1: lim_{x→∞}
    rac{x}{

    }
    (interpreted as x over ln x; the assistant uses the derivative of the numerator and denominator as: f'(x) = 1, g'(x) = 1/x)

    • Determine the form: as x → ∞, x → ∞ and ln x → ∞ → ∞/∞ (indeterminate).
    • Apply L’Hôpital’s rule:
      rac{d}{dx}[x] = 1,
      rac{d}{dx}[
      abla ext{ln} x] = rac{1}{x}
    • Then
      ext{limit} = \lim_{x o ty} rac{1}{1/x} =
      abla x o
      abla o ext{infinity}
    • Conclusion: the limit diverges to $+
      abla$ (i.e., $+
      abla$). In the notes, the instructor emphasizes reporting as infinity and noting the indeterminate form initially.
  • Example 2: lim_{x→∞}
    abla^x / x

    • Recognize the form: $
      abla/
      abla$ (∞/∞).
    • Apply L’Hôpital:
      rac{d}{dx}[
      abla^x] =
      abla^x,\