CIVL 2240: Introduction to Environmental Engineering - Water Pollution (Organic)
Types of Water Pollutants
- Water pollutants can be categorized in various ways:
- Pathogens
- Organic/Inorganic substances
- Nutrients
- Chemical pollutants
- Sediments
- Radio nuclides
- Emerging contaminants
Organic Water Pollution
- An organic molecule is defined as any compound containing carbon, with exceptions including:
- Carbon monoxide (CO)
- Carbon dioxide (CO2)
- Bicarbonate (HCO3−)
- Carbonate (CO32−)
Biodegradation of Organic Matter
- The process of biodegradation includes:
- Substrate (Feed)
- Nutrients (N, P, Fe, etc.)
- Oxygen (O2)
- Produces:
- New cells
- Carbon dioxide (CO2)
- Water (H2O)
- Reaction: Organic matter + O2 → CO2 + H2O + New Cells
Measuring Organic Matter
Biochemical Oxygen Demand (BOD):
Indicator for organic matter concentration.
Defined as the amount of oxygen utilized by microorganisms to oxidize organic matter.
Measured by incubating a contaminated sample with microorganisms for 5 days at 25°C, comparing initial and final dissolved oxygen.
Example:
Sample (1): 500 mg O2 drawn
Sample (2): 3000 mg O2 drawn
Chemical Oxygen Demand (COD)
- Chemical Oxygen Demand (COD):
- Measures total oxygen required to oxidize organic matter using strong oxidizing agents (e.g., potassium dichromate (K2Cr2O7), potassium permanganate (KMnO4)).
- Generally, COD values are higher than BOD values:
- Microorganisms may not oxidize all organic matter.
Calculating Oxygen Requirements for Oxidation
Four essential steps are:
- Write the chemical equation for the oxidation process.
- Balance the equation (moles for C, H, O).
- Convert moles to grams.
- Assess the mass of oxygen required per gram of organic matter.
General reaction:
[ \text{Organic matter} + O2 \rightarrow CO2 + H_2O ]Example Calculation (Glucose):
- Write balanced equation: [ C6H{12}O6 + ZO2 \rightarrow XCO2 + YH2O ]
- Balancing yields: [ C6H{12}O6 + 6O2 \rightarrow 6CO2 + 6H2O ]
- Analysis leads to:
- 1 mole of glucose requires 6 moles of oxygen.
- Grams calculation (1 mole of oxygen = 32 g):
- 6 x 32 g O2 = 192 g O2 for 180 g glucose ( \Rightarrow 1.07 \, \text{g O2/g glucose} )
Other Organic Compounds and Their COD Equivalents
Butyric Acid (C4H8O2):
- Balanced: [ C4H8O2 + 5O2 \rightarrow 4CO2 + 4H2O ]
- Calculated COD equivalent: [ 1.82 \, \text{g COD/g Butyric acid} ]
Glycine (C2H5O2N):
- Balanced: [ C2H5O2N + 1.5O2 \rightarrow 2CO2 + H2O + NH_3 ]
- Calculated COD equivalent: [ 0.64 \, \text{g COD/g Glycine} ]
Measurement of Biomass in Wastewater
Biomass Concentration Measurement Methods:
- Cell number (visual count under microscope).
- Cell mass metrics (Dry weight, Optical density/Turbidity using wavelengths of 600-700 nm).
Total Solids (TS):
- Composed of:
- Total Suspended Solids (TSS) + Total Dissolved Solids (TDS)
- Measurement temp range: 103-105 °C.
Total Suspended Solids (TSS)
- Types of Solids:
- Fixed Solids (FS) post-combustion at 500 °C (indicator of inorganic matter).
- Volatile Solids (VS) loss of mass post-combustion at 500 °C (indicator of organic matter).
COD Fractions
- Classifications based on Size:
- Particulate COD, Soluble COD, Colloidal COD, Semi-soluble COD.
- Generally, Total COD = Particulate COD + Soluble COD.
- COD can be used to estimate biomass through: [ pCOD = 1.42 \times VSS ]
Nutrients for Bacterial Growth
- Major components of bacterial cells include:
- Water ~75%, organic compounds 22.5%, inorganic components 2.5%.
- Nutritional elements needed are:
- Carbon, Hydrogen, Oxygen, Nitrogen, Phosphorus, and other trace elements (Sulfur, Potassium, etc.).
Theoretical Biomass Yield from Substrates
- Example for glucose:
- Biomass yield from glucose calculated as:
[ Biomass Yield = \frac{226}{540} = 0.42 \, g cell/g glucose ]
- Biomass yield from glucose calculated as:
References
- Essential readings:
- "Introduction to Environmental Engineering and Science" by Gilbert M. Masters and Wendell P. Ela (2008).
- "Introduction to Environmental Engineering" by Vesilind, Morgan, & Heine (2010).