Solving Modulus Equations: Theoretical Definition and Step-by-Step Solutions

Definition and Fundamental Principles of Modulus Equations

  • The absolute value or modulus definition is divided into two distinct domain conditions:

    • Case 1: When xx is greater than or equal to zero (x≥0x \ge 0).
    • Case 2: When xx is less than zero (x<0x < 0).
  • Solving a modulus equation requires analyzing the problem from two separate mathematical angles to yield two distinct solutions.

  • Principles for Case 1 (x≥0x \ge 0):

    • The expression is written without the modulus sign.
    • No terms or signs within or outside the modulus are altered except for the removal of the modulus sign itself.
    • For the equation ∣3x∣=18|3x| = 18, dropping the modulus sign yields:     3x=183x = 18
  • Principles for Case 2 (x<0x < 0):

    • The term 3x3x is retained as it is written, while the opposite side of the equation is multiplied by −1-1.
    • Multiplying the right-hand side constant 1818 by −1-1 gives −18-18.
    • This produces the second algebraic equation:     3x=−183x = -18

Step-by-Step Solution of the Modulus Equation

  • Solving the First Linear Equation (x≥0x \ge 0):

    • Equation:     3x=183x = 18
    • Divide both sides of the equation by 33 to isolate xx:     x=183x = \frac{18}{3}
    • Simplify the quotient:     x=6x = 6
  • Solving the Second Linear Equation (x<0x < 0):

    • Equation:     3x=−183x = -18
    • Divide both sides of the equation by 33 to isolate xx:     x=−183x = \frac{-18}{3}
    • Simplify the quotient:     x=−6x = -6
  • Final Result:

    • The two solutions derived for xx in the equation ∣3x∣=18|3x| = 18 are x=6x = 6 and x=−6x = -6

Questions and Discussion

  • Initial Explanation Clarification:

    • Question / Feedback: A participant expressed confusion during the initial explanation, stating, "Yes, sir. No, sir. You can start over. Start over."
    • Request for Review: A request was made to repeat the material from the beginning: "We can go back a little bit. Didn't catch, like, half of it. Let's go again."
    • Re-explanation: The formal definition of the modulus sign was repeated, clearly stating the two domain cases (x<0x < 0 and x≥0x \ge 0) and highlighting that for x≥0x \ge 0, nothing changes in 3x=183x = 18 except removing the modulus sign.
  • Intermediate Comprehension Check:

    • Question / Check: After demonstrating how to multiply the right side of the equation by −1-1 for the x<0x < 0 case to get 3x=−183x = -18, understanding was confirmed.
    • Response: "Okay? Yes, sir. I got it now. I got I got got somewhere?"
  • Final Solution and Writing Directive:

    • Question / Check: After completing both calculations to obtain x=6x = 6 and x=−6x = -6, the final inquiry was made: "Make any sense to you?"
    • Response: "Yes, sir."
    • Final Instructions: "Alright. Clear to everybody? Could you please write it down for me, please?"