Unit Overview: Thermochemistry focuses on the energy changes during chemical reactions and includes understanding limiting reactants and thermochemical equations.
Learning Objectives
By the end of this section, you should be able to:
Calculate the limiting reactant using thermochemical equations.
Key Concepts
Limiting Reactant:
Definition: The limiting reactant is the reactant that is completely consumed first in a chemical reaction, thereby determining the amount of product formed.
Importance: Identifying the limiting reactant is crucial in stoichiometry as it will dictate how much of the product can be formed based on the reactants available.
Thermochemical Equations:
These are balanced chemical equations that include the enthalpy change (energy) associated with the reaction. For instance, a thermochemical equation reflects how much energy is absorbed or released when the reactants are converted to products.
Examples
Example 1: Hydrosulfuric Acid and Oxygen Gas Reaction
Reaction:
2 H₂S + 3 O₂ → 2 SO₂ + 2 H₂O + 175 kJ
Given Data:
14.3 moles of H₂S
17.1 moles of O₂
Energy Calculations:
Calculate energy for H₂S:
14.3 mol H₂S × (175 kJ / 2 mol H₂S) = 1250 kJ
Calculate energy for O₂:
17.1 mol O₂ × (175 kJ / 3 mol O₂) = 1000 kJ
Conclusion: Since O₂ limits the reaction, it is the limiting reactant.
Example 2: Tin and Nitrogen Reaction
Reaction:
Sn + N₂ → Sn₃N₄ + 632 kJ
Given Data:
13.11 g of Sn
2.715 g of N₂
Molar Masses:
Molar mass of Sn = 118.71 g/mol
Molar mass of N₂ = 28.02 g/mol
Energy Calculations:
Convert grams to moles:
Sn: 13.11 g Sn × (1 mol Sn / 118.71 g Sn)
N₂: 2.715 g N₂ × (1 mol N₂ / 28.02 g N₂)
Calculate energy produced:
Based on stoichiometric ratios:
For Sn: (1 mol Sn produces 632 kJ)
For N₂: (3 mol Sn produces 632 kJ)
Conclusion: Determine which reactant is limiting by calculating amount of energy produced based on the moles of each reactant.
Worksheets
Questions?
Begin Worksheet #4 after this session to practice identifying limiting reactants and using thermochemical equations in calculations.