Orienting Yourself: The Use of Coordinates

Historical Foundations of Coordinate Systems

  • Origins of Grid-Based Thinking: The concept of using grids to define physical locations has deep roots in Bhārat. The first systematic urban-scale application occurred thousands of years ago in the Sindhu-Sarasvatĩ Civilisation.

    • Urban Planning: City streets were constructed with precision in North–South and East–West directions, spaced uniformly at intervals of approximately 10m10\,m.

    • Practical Use: This served as a functional coordinate system; merchants located shops or warehouses by counting units of distance from the city centre.

  • Baudhāyana (c. 800 BCE): Utilized North–South and East–West lines for advanced geometric constructions. His work developed the Baudhāyana–Pythagoras Theorem, laying the groundwork for coordinate geometry.

  • Navigation and the Prime Meridian:

    • Ujjayinĩ: Described as early as the 4th century BCE in the early Siddhāntas as the central longitude meridian for world measurements.

    • Ptolemy (c. 150 BCE): Built on the work of Hipparchus to record latitudes and longitudes of thousands of locations, referring to Ujjayinĩ as ‘Ozine’.

  • Mathematical Evolution:

    • Āryabhaᙩa (c. 499 CE): Replaced Greek ‘chords’ with ‘sines’ (sin(x)\sin(x)), simplifying calculations for the coordinates of stars and cities. He mapped the sky using Celestial Coordinates measured from the ecliptic (the Sun's path).

    • Brahmagupta (c. 628 CE): Formalised zero (00) and negative numbers as algebraic entities. This made the modern four-quadrant Cartesian plane possible, as the origin is defined at zero and the negative axes represent values less than zero.

  • Global Transmission:

    • Brahmagupta’s work was translated into Arabic as the Sindhind.

    • The Ujjayinĩ meridian was adopted into Arabic geography as ‘Arin’, serving as the zero-longitude reference.

    • Al-Bĩrũnĩ (c. 1000 CE): Studied the Siddhāntas and used Indian trigonometry to calculate Asian city coordinates. He perfected the ‘astrolabe’ for nautical navigation.

    • –mar Khayyām (c. 1100 CE): An expert in the Indian decimal system, he was the first to solve algebraic problems by interpreting them as geometry in a coordinate plane.

  • European Formalisation:

    • Fermat (1636 CE) and Ren Descartes (1637 CE): Descartes formalised the definition that any point in a two-dimensional (2-D) plane can be represented by two numbers indicating distances from two perpendicular axes. This bridged algebra and geometry.

Conceptual Application: Reiaan’s Room

  • Scenario: Reiaan, a student who is unable to see, moves to a new city. His sister Shalini, who has completed Grade 9, uses coordinate geometry to help him navigate their new home.

  • The Tactical Grid: Shalini creates a physical map of the room's floor using a rectangular grid.

    • Materials: Pins to mark key points and thick wool/thread to connect points representing the corners of objects.

    • Scale: Shalini used a scale of 1cm:1foot1\,cm : 1\,foot.

  • Limitations: Because the map is a 2-D floor plan, vertical elements (like the height of windows or the height of a table) cannot be represented.

The 2-D Cartesian Coordinate System Components

  • Definition: A coordinate system is a structured framework (like grid lines) that uses numbers to describe exact physical locations.

  • The Axes:

    • x-axis: The horizontal line of the system.

    • y-axis: The vertical line of the system.

    • Coordinate Axes: The collective name for both the x-axis and y-axis.

  • The Origin (O): The point where the x-axis and y-axis intersect. Its coordinates are always (0,0)(0, 0).

  • Coordinates of a Point: Represented as (x,y)(x, y).

    • x-coordinate: The perpendicular distance of a point from the y-axis, measured along the x-axis.

    • y-coordinate: The perpendicular distance of a point from the x-axis, measured along the y-axis.

  • Standard Notation: While points can be written as P=(x,y)P = (x, y), it is common practice to drop the equals sign and write it as P(x,y)P(x, y).

  • Positional Rules:

    • Right of Origin: Positive x.

    • Left of Origin: Negative x (x < 0).

    • Upward from Origin: Positive y.

    • Downward from Origin: Negative y (y < 0).

  • Points on Axes:

    • A point on the x-axis has coordinates of the form (x,0)(x, 0).

    • A point on the y-axis has coordinates of the form (0,y)(0, y).

The Cartesian Plane and Quadrants

  • The Cartesian Plane: Also known as the coordinate plane or the xy-plane.

  • Quadrants: The axes divide the plane into four distinct parts, numbered I through IV:

    • Quadrant I: Both x and y are positive (+,++, +).

    • Quadrant II: Negative x, positive y (,+-, +).

    • Quadrant III: Both x and y are negative (,-, -).

    • Quadrant IV: Positive x, negative y (+,+, -).

  • Identity Property: If xyx \neq y, then (x,y)(y,x)(x, y) \neq (y, x). The points (x,y)(x, y) and (y,x)(y, x) only coincide if and only if x=yx = y.

Distance Between Points in a 2-D Plane

  • Parallel to Axes:

    • The distance between two points (x1,y)(x_1, y) and (x2,y)(x_2, y) on a line parallel to the x-axis is x2x1|x_2 - x_1|.

    • The distance between two points (x,y1)(x, y_1) and (x,y2)(x, y_2) on a line parallel to the y-axis is y2y1|y_2 - y_1|.

  • General Distance Formula: For any two points A(x1,y1)A(x_1, y_1) and B(x2,y2)B(x_2, y_2), the distance is calculated using the Baudhāyana–Pythagoras Theorem:

    • Step 1: Find the horizontal shift x2x1|x_2 - x_1|.

    • Step 2: Find the vertical shift y2y1|y_2 - y_1|.

    • Step 3: Apply the theorem: Distance=(x2x1)2+(y2y1)2Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

  • Case Study: Triangle ADM:

    • Points: A(3,4)A(3, 4), D(7,1)D(7, 1), and M(9,6)M(9, 6).

    • Calculation for ADAD:

    • Distance along x-axis: 73=47 - 3 = 4.

    • Distance along y-axis: 41=34 - 1 = 3.

    • AD=42+32=16+9=25=5unitsAD = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5\,units.

    • Calculation for DMDM:

    • DM=(97)2+(61)2=22+52=29unitsDM = \sqrt{(9-7)^2 + (6-1)^2} = \sqrt{2^2 + 5^2} = \sqrt{29}\,units.

    • Calculation for MAMA:

    • MA=(93)2+(64)2=62+22=40unitsMA = \sqrt{(9-3)^2 + (6-4)^2} = \sqrt{6^2 + 2^2} = \sqrt{40}\,units.

Geometric Transformations and Reflections

  • Reflection in the y-axis: When a shape (like triangle ADMADM) is reflected across the y-axis, the x-coordinates change sign while the y-coordinates remain the same.

    • Image of A(3,4)A(3,4)A(3, 4) \rightarrow A'(-3, 4).

    • Image of D(7,1)D(7,1)D(7, 1) \rightarrow D'(-7, 1).

    • Image of M(9,6)M(9,6)M(9, 6) \rightarrow M'(-9, 6).

  • Invariance: Reflection preserves the lengths of the sides of the triangle. For example, distance ADA'D' remains 5units5\,units, just like ADAD.

    • AC=41=3A'C' = 4 - 1 = 3.

    • CD=3(7)=4C'D' = -3 - (-7) = 4.

    • AD=32+42=5unitsA'D' = \sqrt{3^2 + 4^2} = 5\,units.

Practical Scenarios and Accessibility

  • Door Width and Accessibility: In the exercise involving Reiaan’s room, the door D1R1D_1R_1 is discussed.

    • If D1D_1 is at x=10.5x = 10.5 and R1R_1 is at (11.5,0)(11.5, 0), the door width is 1.0unit1.0\,unit (which is 1foot1\,foot in Shalini's scale).

    • Accessibility Question: A width of 1foot1\,foot (12inches12\,inches) is not a comfortable width for a room door and would not allow a person in a wheelchair to enter easily.

  • Computer Graphics Application:

    • A screen is defined as a grid of pixels (e.g., 800pixels800\,pixels width ×\times 600pixels600\,pixels height).

    • The origin (0,0)(0, 0) is at the bottom-left corner.

    • Objects like icons are placed using coordinate centers and radii.

    • To check if icons intersect, the distance between their center points A(x1,y1)A(x_1, y_1) and B(x2,y2)B(x_2, y_2) must be compared to the sum of their radii (r1+r2r_1 + r_2).

Questions & Discussion

  • Questions from Exercise 1.1:

    • Q: How far is the door D1R1D_1R_1 from the left wall (y-axis)?

    • A: The distance is represented by the x-coordinate of the door's start point.

    • Q: Is the bathroom door narrower or wider than the room door if bathroom endpoints are B1(0,1.5)B_1(0, 1.5) and B2(0,4)B_2(0, 4)?

    • A: The width is 41.5=2.5feet|4 - 1.5| = 2.5\,feet. Compared to the room door (assuming 11.510.5=1foot11.5 - 10.5 = 1\,foot), the bathroom door is wider.

  • Think and Reflect:

    • Q: What is the x-coordinate of a point on the y-axis?

    • A: The x-coordinate is always 00.

    • Q: If xyx \neq y, then (x,y)(y,x)(x, y) \neq (y, x). Is this claim true?

    • A: Yes. The order of coordinates matters in a 2-D plane.

    • Q: Are doors in schools suitable for wheelchairs?

    • A: This requires students to observe standard widths, which usually need to be at least 3236inches32–36\,inches for accessibility, whereas the example door was only 1foot1\,foot.

  • Advanced Coordinate Challenges:

    • Collinearity: To check if points M(3,4)M(-3, -4), A(0,0)A(0, 0), and G(6,8)G(6, 8) lie on the same straight line, one can compare the ratios of distance shifts or use the distance formula to see if MA+AG=MGMA + AG = MG.

    • Midpoint Identification: M is the midpoint of ST if its coordinates are the averages of the coordinates of S and T: M(xS+xT2,yS+yT2)M\left(\frac{x_S+x_T}{2}, \frac{y_S+y_T}{2}\right).