Lakshya JEE 2026 Batch Mathematics Matrices Lecture 01 Study Notes

Lakshya JEE 2026 Batch: Mathematics - Matrices

Course Information

  • Subject: Mathematics

  • Topic: Matrices

  • Lecture: 01

  • Instructor: Ashish Agarwal Sir (IIT Kanpur)

  • Batch: Lakshya JEE 2026

Topics Covered in Lecture 01

  1. Introduction to Matrices

  2. Special types of Matrices

  3. Determinant of a Square Matrix

  4. Algebra of Matrices

Homework Discussion and TAH (Take-Away Homework) Solutions

TAH 02: Arithmetic Progression and Determinants
  • Question: If p,q,r,sp, q, r, s are in A.P. and f(x)=p+sin(x)amp;q+sin(x)amp;pr+sin(x)q+sin(x)amp;r+sin(x)amp;rs+sin(x)r+sin(x)amp;s+sin(x)amp;sq+sin(x)f(x) = \begin{vmatrix} p+\sin(x) & q+\sin(x) & p-r+\sin(x) \\ q+\sin(x) & r+\sin(x) & r-s+\sin(x) \\ r+\sin(x) & s+\sin(x) & s-q+\sin(x) \end{vmatrix} such that 02f(x)dx=4\int_0^2 f(x)\,dx = -4, find the common difference of the A.P.

  • Solution Strategy:

    • Let the common difference be dd.

    • Perform row transformations: R1R1R2R_1 \rightarrow R_1 - R_2 and R2R2R3R_2 \rightarrow R_2 - R_3.

    • Since p,q,r,sp, q, r, s are in A.P., then pq=dp-q = -d, qr=dq-r = -d, rs=dr-s = -d, etc.

    • The determinant value simplifies to f(x)=2d2f(x) = -2d^2.

    • Integrate: 022d2dx=2d2[x]02=4d2\int_0^2 -2d^2\,dx = -2d^2 [x]_0^2 = -4d^2.

    • Set equal to 4-4: 4d2=4d2=1d=±1-4d^2 = -4 \Rightarrow d^2 = 1 \Rightarrow d = \pm 1.

  • Options: A) -1, B) 1/2, C) 1, D) 2

  • Correct Answer: A and C (d=1d = 1 or d=1d = -1).

TAH 03: Function Differentiation
  • Question: Let F(x)=1amp;1+sin(x)amp;1+sin(x)+cos(x)2amp;3+2sin(x)amp;4+3sin(x)+2cos(x)3amp;6+3sin(x)amp;10+6sin(x)+3cos(x)F(x) = \begin{vmatrix} 1 & 1+\sin(x) & 1+\sin(x)+\cos(x) \\ 2 & 3+2\sin(x) & 4+3\sin(x)+2\cos(x) \\ 3 & 6+3\sin(x) & 10+6\sin(x)+3\cos(x) \end{vmatrix}. Find F(π2)F'(\frac{\pi}{2}).

  • Solution Strategy:

    • Perform row operations: R2R22R1R_2 \rightarrow R_2 - 2R_1 and R3R33R1R_3 \rightarrow R_3 - 3R_1.

    • The resulting determinant simplifies to the constant value F(x)=1F(x) = 1.

    • The derivative of a constant is zero: F(x)=0F'(x) = 0.

    • Thus, F(π2)=0F'(\frac{\pi}{2}) = 0.

  • Correct Answer: B (0).

TAH 04: IIT-JEE 1985 Combination Property
  • Question: Show that Δ=xCramp;xCr+1amp;xCr+2yCramp;yCr+1amp;yCr+2zCramp;zCr+1amp;zCr+2=xCramp;x+1Cr+1amp;x+2Cr+2yCramp;y+1Cr+1amp;y+2Cr+2zCramp;z+1Cr+1amp;z+2Cr+2\Delta = \begin{vmatrix} ^xC_r & ^xC_{r+1} & ^xC_{r+2} \\ ^yC_r & ^yC_{r+1} & ^yC_{r+2} \\ ^zC_r & ^zC_{r+1} & ^zC_{r+2} \end{vmatrix} = \begin{vmatrix} ^xC_r & ^{x+1}C_{r+1} & ^{x+2}C_{r+2} \\ ^yC_r & ^{y+1}C_{r+1} & ^{y+2}C_{r+2} \\ ^zC_r & ^{z+1}C_{r+1} & ^{z+2}C_{r+2} \end{vmatrix}.

  • Principle Used: Pascal's Identity: nCr+nCr+1=n+1Cr+1^nC_r + ^nC_{r+1} = ^{n+1}C_{r+1}.

  • Proof Steps:

    • Use column operations to transform entries. Adding column 1 to column 2 gives nCr+nCr+1=n+1Cr+1^nC_r + ^nC_{r+1} = ^{n+1}C_{r+1}.

    • Subsequent addition of modified columns results in the shown matrix form.

Introduction to Matrices

Definition
  • A matrix is an arrangement of elements (numbers, symbols, or functions) in the form of rows and columns.

  • Row: Horizontal alignment of elements.

  • Column: Vertical alignment of elements.

  • Mathematical Application: Matrices are primarily concerned with numbers as elements.

Difference Between Matrix and Determinant
  1. Nature: A matrix is an arrangement/structure; a determinant is a numerical value associated with a square matrix.

  2. Value: A matrix has no value; a determinant has a specific numerical value.

  3. Rows/Columns: In a matrix, the number of rows may or may not be equal to the number of columns. In a determinant, the number of rows must equal the number of columns.

Representation and Order
  • Notation: Matrices are represented using square brackets [][ \dots ] or parentheses ()( \dots ). Some older notations used double bars || \dots ||, but this is now obsolete.

  • Order: If a matrix A has mm rows and nn columns, its order is written as m×nm \times n (read as "m by n").

  • Number of Elements: The total number of elements in a matrix of order m×nm \times n is mnmn.

  • Abbreviated Form: A=[aij]m×nA = [a_{ij}]_{m \times n}, where aija_{ij} represents the element in the ii-th row and jj-th column (1im1 \le i \le m and 1jn1 \le j \le n).

  • Real Matrix: If all elements of a matrix are real numbers, it is called a real matrix.

Constructing Matrices: Examples
  • Example 1: Construct a 3×23 \times 2 matrix where aij=i2j2a_{ij} = \frac{|i - 2j|}{2}.

    • a11=1/2,a12=3/2a_{11} = 1/2, a_{12} = 3/2

    • a21=0,a22=1a_{21} = 0, a_{22} = 1

    • a31=1/2,a32=1/2a_{31} = 1/2, a_{32} = 1/2

    • Matrix A=(1/2amp;3/20amp;11/2amp;1/2)A = \begin{pmatrix} 1/2 & 3/2 \\ 0 & 1 \\ 1/2 & 1/2 \end{pmatrix}.

  • Example 2: Find all possible orders for a matrix with 24 elements.

    • Factors of 24: 1×24,24×1,2×12,12×2,3×8,8×3,4×6,6×41 \times 24, 24 \times 1, 2 \times 12, 12 \times 2, 3 \times 8, 8 \times 3, 4 \times 6, 6 \times 4. (8 possible matrices).

Special Types of Matrices

Basic Types
  • Row Matrix: A matrix having only one row. Order is 1×n1 \times n. Also called a Row Vector.

  • Column Matrix: A matrix having only one column. Order is m×1m \times 1. Also called a Column Vector.

  • Zero or Null Matrix: An m×nm \times n matrix where all entries are zero. Denoted by Om×nO_{m \times n}.

  • Horizontal Matrix: A matrix where the number of columns is greater than the number of rows (n > m).

  • Vertical Matrix: A matrix where the number of rows is greater than the number of columns (m > n).

Square Matrix and Related Sub-types
  • Square Matrix: A matrix where the number of rows equals the number of columns (m=nm = n).

    • Diagonal Elements: Entries aija_{ij} where i=ji = j (e.g., a11,a22,a33a_{11}, a_{22}, a_{33}).

    • Conjugate Elements: Entries aija_{ij} and ajia_{ji} for iji \ne j.

    • Total Diagonal Entries: nn for a matrix of order nn.

    • Elements above Diagonal: Entries where i < j.

    • Elements below Diagonal: Entries where i > j.

  • Triangular Matrix:

    • Upper Triangular Matrix (UTM): A square matrix where all entries below the main diagonal are zero (aij=0a_{ij} = 0 for all i > j).

    • Lower Triangular Matrix (LTM): A square matrix where all entries above the main diagonal are zero (aij=0a_{ij} = 0 for all i < j).

  • Diagonal Matrix: A square matrix where all non-diagonal elements are zero (aij=0a_{ij} = 0 for iji \ne j). Abbreviated as diag(d1,d2,,dn)diag(d_1, d_2, \dots, d_n).

  • Scalar Matrix: A diagonal matrix where all diagonal entries are equal (d1=d2==ad_1 = d_2 = \dots = a).

  • Identity or Unit Matrix (II): A scalar matrix where all diagonal entries are equal to 1. Denoted as InI_n.

Statistical Properties of Matrices of Order nn
  • Minimum number of zeroes in a Triangular Matrix: n2n2\frac{n^2 - n}{2}.

  • Minimum number of cyphers (zeroes) in a Diagonal/Scalar/Unit Matrix: n2nn^2 - n.

  • Maximum number of zeroes in a Triangular Matrix: n2+n22\frac{n^2 + n - 2}{2}.

Numerical Problem: Distinct Entries
  • Question: AA is a square matrix of order nn. Let ll be the maximum number of distinct entries if AA is triangular, mm be the max distinct entries if AA is diagonal, and pp be minimum zeroes if AA is triangular. If l+5=p+2ml + 5 = p + 2m, find nn.

  • Formulas:

    • l=n(n+1)2+1l = \frac{n(n+1)}{2} + 1 (Diagonal entries + one set of zeros + above/below entries).

    • m=n+1m = n + 1 (Diagonal entries + zero).

    • p=n(n1)2p = \frac{n(n-1)}{2}.

  • Calculation: Substituting into l+5=p+2ml + 5 = p + 2m reveals n=3n = 3.

Determinant of a Square Matrix

  • If AA is a square matrix, its determinant is denoted by A|A| or det(A)\det(A).

  • Singular Matrix: A square matrix AA such that A=0|A| = 0.

  • Non-Singular Matrix: A square matrix AA such that A0|A| \ne 0.

  • Important Note: A null matrix always has a determinant of 0, but a matrix with a determinant of 0 is not necessarily a null matrix.

Advanced Determinant Questions
  • Singular Matrix Condition: If A=(2kamp;k1amp;3k)A = \begin{pmatrix} 2-k &amp; -k \\ -1 &amp; 3-k \end{pmatrix} is singular, find 5kk25k - k^2.

    • A=(2k)(3k)(1)(k)=065k+k2k=0k26k+6=0|A| = (2-k)(3-k) - (-1)(-k) = 0 \Rightarrow 6 - 5k + k^2 - k = 0 \Rightarrow k^2 - 6k + 6 = 0.

    • From k26k+6=0k^2 - 6k + 6 = 0, we find k25k=k6k^2 - 5k = k - 6. Calculation leads to specific result (Ans: 4).

  • Summation of Determinants (WB JEE 2023): If Mr=(ramp;r1r1amp;r)M_r = \begin{pmatrix} r &amp; r-1 \\ r-1 &amp; r \end{pmatrix}, find r=12008det(Mr)\sum_{r=1}^{2008} \det(M_r).

    • det(Mr)=r2(r1)2=r2(r22r+1)=2r1\det(M_r) = r^2 - (r-1)^2 = r^2 - (r^2 - 2r + 1) = 2r - 1.

    • r=12008(2r1)=2(2008×20092)2008=20082\sum_{r=1}^{2008} (2r-1) = 2(\frac{2008 \times 2009}{2}) - 2008 = 2008^2.

Algebra of Matrices

Equality of Matrices

Two matrices AA and BB are equal if and only if:

  1. They have the same order (O(A)=O(B)O(A) = O(B)).

  2. Every corresponding element is identical (aij=bija_{ij} = b_{ij} for all i,ji, j).

Addition and Subtraction
  • Defined only for matrices of the same order.

  • Addition: A+B=[aij+bij]A + B = [a_{ij} + b_{ij}].

  • Subtraction: AB=[aijbij]A - B = [a_{ij} - b_{ij}].

  • Properties:

    1. Commutative: A+B=B+AA + B = B + A.

    2. Associative: A+(B+C)=(A+B)+CA + (B + C) = (A + B) + C.

    3. Additive Inverse: The additive inverse of AA is A=[aij]-A = [-a_{ij}].

Questions & Discussion

Question Answered by Sakil (West Bengal)
  • Context: Solution to the TAH 01 determinant problem involving a2+b2+c2=1a^2+b^2+c^2 = 1.

  • Result: Showed that the determinant simplifies to cos2(θ)\cos^2(\theta).

Question Answered by Dhairya Goel (Faridabad)
  • Context: Solution for the AP determinant (TAH 02) and the differentiation problem (TAH 03).

  • Process: Demonstrated row/column reduction steps and the application of f(x)dx\int f(x)\,dx.

Question Answered by Ajay (Giridih, Jharkhand)
  • Context: Verification of the combinations identity proof (TAH 04) using column operations.

Question Answered by Yash Singh (Jharkhand)
  • Context: Provided calculation details for the row reduction and integration of the AP problem.