1sinx=cscx\frac{1}{\sin{x}} = \csc{x}sinx1=cscx, which also implies 1cscx=sinx\frac{1}{\csc{x}} = \sin{x}cscx1=sinx
cscx=1sinx\csc{x} = \frac{1}{\sin{x}}cscx=sinx1
sinx=1cscx\sin{x} = \frac{1}{\csc{x}}sinx=cscx1
secx=1cosx\sec{x} = \frac{1}{\cos{x}}secx=cosx1
cosx=1secx\cos{x} = \frac{1}{\sec{x}}cosx=secx1
cotx=1tanx\cot{x} = \frac{1}{\tan{x}}cotx=tanx1
tanx=1cotx\tan{x} = \frac{1}{\cot{x}}tanx=cotx1
tanx=sinxcosx\tan{x} = \frac{\sin{x}}{\cos{x}}tanx=cosxsinx
cotx=cosxsinx\cot{x} = \frac{\cos{x}}{\sin{x}}cotx=sinxcosx
sin2θ+cos2θ=1\sin^2{\theta} + \cos^2{\theta} = 1sin2θ+cos2θ=1
1+tan2θ=sec2θ1 + \tan^2{\theta} = \sec^2{\theta}1+tan2θ=sec2θ
1+cot2θ=csc2θ1 + \cot^2{\theta} = \csc^2{\theta}1+cot2θ=csc2θ
1−cos2x=sin2x1 - \cos^2{x} = \sin^2{x}1−cos2x=sin2x
1+tan2x=sec2x1 + \tan^2{x} = \sec^2{x}1+tan2x=sec2x
1cos2x=sec2x\frac{1}{\cos^2{x}} = \sec^2{x}cos2x1=sec2x
cosxsinx=cotx\frac{\cos{x}}{\sin{x}} = \cot{x}sinxcosx=cotx
1sinx=cscx\frac{1}{\sin{x}} = \csc{x}sinx1=cscx
1cos2x=sec2x\frac{1}{\cos^2 x} = \sec^2 xcos2x1=sec2x