Physical Science Final Review: Kinetic and Potential Energy Calculations

Fundamental Principles and Equations of Energy

To perform the following calculations accurately, two primary forms of mechanical energy are considered: Kinetic Energy (KEKE) and Gravitational Potential Energy (PEPE). Kinetic energy is associated with an object's motion, while potential energy is associated with an object's position or height relative to a reference point.

  • Kinetic Energy Formula: The energy of motion is calculated using the following equation:     KE=12mv2KE = \frac{1}{2}mv^{2}     Where:

    • KEKE is Kinetic Energy measured in Joules (JJ).

    • mm is the mass of the object measured in kilograms (kgkg).

    • vv is the velocity or speed of the object measured in meters per second (m/sm/s).

  • Potential Energy Formula: The energy of position is calculated using the following equation:     PE=mghPE = mgh     Where:

    • PEPE is Potential Energy measured in Joules (JJ).

    • mm is the mass of the object measured in kilograms (kgkg).

    • gg is the acceleration due to gravity, which is a constant approximately equal to 9.8m/s29.8\,m/s^{2}.

    • hh is the height of the object above the reference surface measured in meters (mm).

Problem-Solving Analysis

1. Kinetic Energy of a Motorcycle
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 900kg900\,kg

    • Velocity (vv) = 25m/s25\,m/s

    • Unknown: Kinetic Energy (KEKE)

  • Step 2: Formula Selection

    • KE=12mv2KE = \frac{1}{2}mv^{2}

  • Step 3: Substitution

    • KE=12×900kg×(25m/s)2KE = \frac{1}{2} \times 900\,kg \times (25\,m/s)^{2}

  • Step 4: Calculation

    • KE=450kg×625m2/s2KE = 450\,kg \times 625\,m^{2}/s^{2}

  • Step 5: Final Result

    • KE=281,250JKE = 281,250\,J

2. Mass of a Hanging Sign
  • Step 1: Identify Given Information and Unknowns

    • Potential Energy (PEPE) = 735J735\,J

    • Height (hh) = 5m5\,m

    • Gravity (gg) = 9.8m/s29.8\,m/s^{2}

    • Unknown: Mass (mm)

  • Step 2: Formula Selection

    • m=PEghm = \frac{PE}{gh}

  • Step 3: Substitution

    • m=735J(9.8m/s2)(5m)m = \frac{735\,J}{(9.8\,m/s^{2})(5\,m)}

  • Step 4: Calculation

    • m=735J49m2/s2m = \frac{735\,J}{49\,m^{2}/s^{2}}

  • Step 5: Final Result

    • m=15kgm = 15\,kg

3. Kinetic Energy of a Skateboarder
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 65kg65\,kg

    • Velocity (vv) = 8m/s8\,m/s

    • Unknown: Kinetic Energy (KEKE)

  • Step 2: Formula Selection

    • KE=12mv2KE = \frac{1}{2}mv^{2}

  • Step 3: Substitution

    • KE=12×65kg×(8m/s)2KE = \frac{1}{2} \times 65\,kg \times (8\,m/s)^{2}

  • Step 4: Calculation

    • KE=32.5kg×64m2/s2KE = 32.5\,kg \times 64\,m^{2}/s^{2}

  • Step 5: Final Result

    • KE=2,080JKE = 2,080\,J

4. Potential Energy of a Backpack
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 12kg12\,kg

    • Height (hh) = 2.5m2.5\,m

    • Gravity (gg) = 9.8m/s29.8\,m/s^{2}

    • Unknown: Potential Energy (PEPE)

  • Step 2: Formula Selection

    • PE=mghPE = mgh

  • Step 3: Substitution

    • PE=12kg×9.8m/s2×2.5mPE = 12\,kg \times 9.8\,m/s^{2} \times 2.5\,m

  • Step 4: Calculation

    • PE=117.6N×2.5mPE = 117.6\,N \times 2.5\,m

  • Step 5: Final Result

    • PE=294JPE = 294\,J

5. Mass of a Diver
  • Step 1: Identify Given Information and Unknowns

    • Height (hh) = 10m10\,m

    • Potential Energy (PEPE) = 5,880J5,880\,J

    • Gravity (gg) = 9.8m/s29.8\,m/s^{2}

    • Unknown: Mass (mm)

  • Step 2: Formula Selection

    • m=PEghm = \frac{PE}{gh}

  • Step 3: Substitution

    • m=5,880J(9.8m/s2)(10m)m = \frac{5,880\,J}{(9.8\,m/s^{2})(10\,m)}

  • Step 4: Calculation

    • m=5,880J98m2/s2m = \frac{5,880\,J}{98\,m^{2}/s^{2}}

  • Step 5: Final Result

    • m=60kgm = 60\,kg

6. Kinetic Energy of a Car
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 1,500kg1,500\,kg

    • Velocity (vv) = 20m/s20\,m/s

    • Unknown: Kinetic Energy (KEKE)

  • Step 2: Formula Selection

    • KE=12mv2KE = \frac{1}{2}mv^{2}

  • Step 3: Substitution

    • KE=12×1,500kg×(20m/s)2KE = \frac{1}{2} \times 1,500\,kg \times (20\,m/s)^{2}

  • Step 4: Calculation

    • KE=750kg×400m2/s2KE = 750\,kg \times 400\,m^{2}/s^{2}

  • Step 5: Final Result

    • KE=300,000JKE = 300,000\,J

7. Height of a Box
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 40kg40\,kg

    • Potential Energy (PEPE) = 1,960J1,960\,J

    • Gravity (gg) = 9.8m/s29.8\,m/s^{2}

    • Unknown: Height (hh)

  • Step 2: Formula Selection

    • h=PEmgh = \frac{PE}{mg}

  • Step 3: Substitution

    • h=1,960J(40kg)(9.8m/s2)h = \frac{1,960\,J}{(40\,kg)(9.8\,m/s^{2})}

  • Step 4: Calculation

    • h=1,960J392kgm/s2h = \frac{1,960\,J}{392\,kg\cdot m/s^{2}}

  • Step 5: Final Result

    • h=5mh = 5\,m

8. Kinetic Energy of a Baseball
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 0.15kg0.15\,kg

    • Velocity (vv) = 30m/s30\,m/s

    • Unknown: Kinetic Energy (KEKE)

  • Step 2: Formula Selection

    • KE=12mv2KE = \frac{1}{2}mv^{2}

  • Step 3: Substitution

    • KE=12×0.15kg×(30m/s)2KE = \frac{1}{2} \times 0.15\,kg \times (30\,m/s)^{2}

  • Step 4: Calculation

    • KE=0.075kg×900m2/s2KE = 0.075\,kg \times 900\,m^{2}/s^{2}

  • Step 5: Final Result

    • KE=67.5JKE = 67.5\,J

9. Potential Energy of a Rock
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 75kg75\,kg

    • Height (hh) = 18m18\,m

    • Gravity (gg) = 9.8m/s29.8\,m/s^{2}

    • Unknown: Potential Energy (PEPE)

  • Step 2: Formula Selection

    • PE=mghPE = mgh

  • Step 3: Substitution

    • PE=75kg×9.8m/s2×18mPE = 75\,kg \times 9.8\,m/s^{2} \times 18\,m

  • Step 4: Calculation

    • PE=735N×18mPE = 735\,N \times 18\,m

  • Step 5: Final Result

    • PE=13,230JPE = 13,230\,J

10. Kinetic Energy of a Soccer Ball
  • Step 1: Identify Given Information and Unknowns

    • Mass (mm) = 2kg2\,kg

    • Velocity (vv) = 12m/s12\,m/s

    • Unknown: Kinetic Energy (KEKE)

  • Step 2: Formula Selection

    • KE=12mv2KE = \frac{1}{2}mv^{2}

  • Step 3: Substitution

    • KE=12×2kg×(12m/s)2KE = \frac{1}{2} \times 2\,kg \times (12\,m/s)^{2}

  • Step 4: Calculation

    • KE=1kg×144m2/s2KE = 1\,kg \times 144\,m^{2}/s^{2}

  • Step 5: Final Result

    • KE=144JKE = 144\,J