ELECTRICITY

CHARGING BY FRICTION (FULL EXPLANATION + DIAGRAMS)

What it is

When two materials rub, electrons move from one to the other.

How to know who loses/gains?

Use the Triboelectric Series (given on test).

  • Higher on list → loses electrons → becomes positive

  • Lower on list → gains electrons → becomes negative

🔵 DIAGRAM: Charging by Friction

(Neutral objects → rubbed → one becomes +, one becomes –)

Before rubbing

Both objects neutral:

Code

Object A:  +  -  +  -  +  -
Object B:  +  -  +  -  +  -

During rubbing

Electrons move from the material HIGHER on the series → LOWER on the series.

Example: Glass (higher) rubbed with plastic wrap (lower)

Code

Glass:      +  -  +  -  +  -   → loses electrons
Plastic:    +  -  +  -  +  -   → gains electrons

After rubbing

Code

Glass:      +  +  +  +  +      (POSITIVE)
Plastic:    -  -  -  -  -      (NEGATIVE)

CHARGING BY CONTACT?

🧠 WHY does this happen?

Because electrons move, and they always move in the direction that makes things more balanced.

  • Negative object = has extra electrons

  • Positive object = has too few electrons

  • Neutral object = equal electrons & protons

When they touch, electrons move to fix the imbalance.

TWO CASES

We do BOTH with diagrams.

🔵 CASE 1 — NEGATIVE OBJECT TOUCHES NEUTRAL

(Electrons move into the neutral object)

Before contact

Code

NEGATIVE OBJECT:   - - - - - + + +
NEUTRAL OBJECT:    + - + - + -

During contact

Electrons flow from negative → neutral.

Code

NEGATIVE OBJECT:   - - - - + + + +
NEUTRAL OBJECT:    - - - - + - + -

After contact

Code

NEGATIVE OBJECT:   still negative
NEUTRAL OBJECT:    becomes negative

Neutral becomes negative
Electrons moved INTO it

🔴 CASE 2 — POSITIVE OBJECT TOUCHES NEUTRAL

(Electrons move out of the neutral object)

Before contact

Code

POSITIVE OBJECT:   + + + + - - -
NEUTRAL OBJECT:    + - + - + -

During contact

Electrons flow from neutral → positive.

Code

POSITIVE OBJECT:   + + + - - - - -
NEUTRAL OBJECT:    + + + - + -

After contact

Code

POSITIVE OBJECT:   still positive
NEUTRAL OBJECT:    becomes positive

Neutral becomes positive
Electrons moved OUT of it

SUPER SIMPLE SUMMARY

  • Touch with negative → electrons go into neutral → neutral becomes negative

  • Touch with positive → electrons go out of neutral → neutral becomes positive

CHARGING BY INDUCTION

🧠 WHAT IS INDUCTION? (Proper explanation)

From your notes:

“Induction is the movement/rearrangement of electrons within a substance caused by a nearby charged object, without direct contact.”

Meaning:

The charged object NEVER touches

Electrons inside the neutral object shift positions

The object stays overall neutral

The charge is temporary (only exists while the charged object is near)

This is the KEY difference from contact.

WHY DOES INDUCTION HAPPEN?

Because electrons move away from negative
and move toward positive.

Electrons are like scared little boiis:

  • They run away from negative charges

  • They run toward positive charges

So when a charged object comes close, electrons inside the neutral object rearrange.

🔵 CASE 1 — NEGATIVE OBJECT NEAR A NEUTRAL OBJECT

(Electrons get pushed away)

Before

Neutral object = electrons evenly spread.

During induction

Negative rod repels electrons → they move to the far side.

Result

  • Near side becomes positive

  • Far side becomes negative

  • Object is STILL neutral overall

  • Charge disappears when rod is removed

🔴 CASE 2 — POSITIVE OBJECT NEAR A NEUTRAL OBJECT

(Electrons get pulled toward the rod)

Before

Neutral object = electrons evenly spread.

During induction

Positive rod attracts electrons → they move to the near side.

Result

  • Near side becomes negative

  • Far side becomes positive

  • Object is STILL neutral overall

  • Charge disappears when rod is removed

1. PITH‑BALL ELECTROSCOPE

A tiny ball made of pith (light, non‑conductive material) hanging from a thread.

HOW IT WORKS

The pith ball is neutral at the start.

A) Charged object brought NEAR (induction)

  • Electrons inside the pith ball shift

  • The pith ball becomes temporarily polarized

  • It gets attracted to the charged object

B) Charged object TOUCHES the pith ball (contact)

  • Electrons transfer

  • The pith ball becomes charged

  • Now it can repel from the same charge

EXAMPLE: Negative balloon near pith ball

  • Balloon repels electrons inside the pith ball

  • Near side becomes positive

  • Pith ball is attracted

EXAMPLE: Negative balloon touches pith ball

  • Electrons move into pith ball

  • Pith ball becomes negative

  • Now it repels from the balloon

2. METAL‑LEAF ELECTROSCOPE

This one is more sensitive and shows charge using two thin metal leaves.

HOW IT WORKS

Inside the electroscope:

  • A metal knob

  • A metal rod

  • Two thin metal leaves

All connected → electrons can move freely.

WHAT HAPPENS WHEN A CHARGED OBJECT COMES NEAR?

A) Induction (NO touching)

  • Electrons shift inside the electroscope

  • Leaves get the same charge

  • Leaves repel and spread apart

B) Contact (TOUCHING)

  • Electrons transfer

  • Electroscope becomes charged

  • Leaves stay apart even after the rod is removed

🧠 KEY IDEA

Leaves spread apart = electroscope is charged.
Leaves collapse = electroscope is neutral.

PART 1 — CIRCUITS (SERIES + PARALLEL)

🔵 SERIES CIRCUIT

Only ONE path for electrons.

Rules

  • Current is the SAME everywhere
    IT = I1 = I2 = I3

  • Voltage SPLITS
    VT = V1 + V2 + V3

  • Resistance ADDS
    RT = R1 + R2 + R3

  • If one bulb breaks → ALL go out

🔴 PARALLEL CIRCUIT

Electrons have multiple paths.

Rules

  • Voltage is the SAME on each branch
    VT = V1 = V2 = V3

  • Current SPLITS
    IT = I1 + I2 + I3

  • Resistance DECREASES
    1/RT = 1/R1 + 1/R2 + 1/R3

  • If one bulb breaks → others stay on

PART 2 — OHM’S LAW (V = IR)

Using GRASP properly

Formula

  • V = I × R

  • I = V ÷ R

  • R = V ÷ I

Example 1 — Find Voltage (V)

A current of 4 A flows through a 40 Ω resistor.

G: I = 4 A, R = 40 Ω

R: V

A: V = IR

S: V = 4 × 40 = 160 V

P: The voltage is 160 V.

Example 2 — Find Resistance (R)

V = 240 V, I = 20 A

G: V = 240 V, I = 20 A

R: R

A: R = V ÷ I

S: 240 ÷ 20 = 12 Ω

P: The resistance is 12 Ω.

Example 3 — Find Current (I)

V = 30 V, R = 15 Ω

G: V = 30 V, R = 15 Ω

R: I

A: I = V ÷ R

S: 30 ÷ 15 = 2 A

P: The current is 2 A.

Current (I)

SUPER SUMMARY TABLE

Feature

Series

Parallel

Paths

1

Many

Current

Same

Splits

Voltage

Splits

Same

Resistance

Adds

Decreases

If one bulb breaks

All off

Others stay on