Mole Calculations Study Notes

Mole Calculations #2

Problem 1: Volume of Helium Gas

  • Question: What volume, in liters (at STP), would be occupied by 4.81 x 10²¹ atoms of helium gas?
  • Relevant Concepts:
    • STP (Standard Temperature and Pressure):
    • Defined as 0°C (273.15 K) and 1 atm pressure.
    • At STP, 1 mole of any gas occupies a volume of 22.4 liters.
  • Calculation Steps:
    • Find moles from atoms:
    • Use the Avogadro's number: $N_A = 6.022 imes 10^{23}$ atoms/mole.
    • Moles of He = ( ext{Moles} = rac{4.81 imes 10^{21} ext{ atoms}}{6.022 imes 10^{23} ext{ atoms/mole}} )
    • Calculate volume:
    • Use the volume occupied by 1 mole at STP:
    • Volume = moles x 22.4 L/mole.

Problem 2: Mass of Oxygen Gas

  • Question: What is the mass, in grams, of 34.99 liters of oxygen gas (O2), at STP?
  • Relevant Concepts:
    • Moles of oxygen gas: Use the volume at STP (22.4 L/mole) to find moles.
  • Calculation Steps:
    • Find moles from liters:
    • Moles of O2 = ( ext{Moles} = rac{34.99 ext{ L}}{22.4 ext{ L/mole}} )
    • Determine mass from moles:
    • Molar mass of O2 = 32 g/mole (since O has an atomic mass of 16 g, O2 = 2 × 16 g).
    • Mass = moles x molar mass.

Problem 3: Moles of Aluminum Sulfate

  • Question: How many moles are equal to 393.6 grams of aluminum sulfate?
  • Relevant Concepts:
    • Molar Mass Calculation:
    • Formula of aluminum sulfate: Al2(SO4)3.
    • Molar mass = 2(27) + 3(32) + 12(16) = 342 g/mole.
  • Calculation Steps:
    • Find moles from grams:
    • Moles = ( ext{Moles} = rac{393.6 ext{ g}}{342 ext{ g/mole}} )

Problem 4: Atoms of Chlorine Gas

  • Question: How many atoms are equal to 0.056 liters of chlorine (Cl2) gas, at STP?
  • Relevant Concepts:
    • Moles of Cl2 from liters:
    • Calculation Steps:
    • Moles of Cl2 = ( ext{Moles} = rac{0.056 ext{ L}}{22.4 ext{ L/mole}} )
    • Atoms = moles x Avogadro's number: ( ext{Atoms} = ext{Moles} imes 6.022 imes 10^{23} ext{ atoms/mole} ).

Problem 5: Volume of Carbon Monoxide Gas

  • Question: What volume, in liters (at STP), would be occupied by 0.78 moles of carbon monoxide gas?
  • Relevant Concepts:
    • Volume Calculation at STP:
  • Calculation Steps:
    • Volume = moles x 22.4 L/mole = ( 0.78 ext{ moles} imes 22.4 ext{ L/mole} ).