Lesson 7.3/4 - Limiting and Excess Reactants
Limiting & Excess Reactants
Introduction to Limiting Reactant
In real life, chemical reactions rarely have reactants in stoichiometric amounts.
Example: BBQ reaction: C<em>3H</em>8(g)+5O<em>2(g)→3CO</em>2(g)+4H2O(g)
Question: What happens when you run out of propane?
Limiting Reagent (LR)
Excess Reagent (ER)
The reactant present in more than the required amount for a complete reaction to occur.
This reactant remains after the reaction is over.
The excess reactant cannot be used in stoichiometry problems.
Examples of Limiting and Excess Reactants
2 car bodies, 7 tires
No gasoline in your vehicle but oxygen is still present for combustion
4 hamburger patties, 2 hamburger buns
6 crackers, 28 chocolate squares, 2 marshmallows to make Perfect S’mores (2 Graham Crackers, 4 Chocolate Squares, 1 Marshmallow)
Answers to Examples
The limiting and excess reactants in the previous scenarios:
Limiting: car bodies, Excess: tires
Limiting: gasoline, Excess: oxygen
Limiting: hamburger buns, Excess: hamburger patties
Limiting: marshmallows, Excess: crackers and chocolate squares
Complete & Incomplete Combustion
Figure 1: When you light a Bunsen burner, you start with an orange flame then adjust the air intake to get a hot, blue flame. This demonstrates the effect of changing the reactant ratio on the reaction.
Identifying Limiting and Excess Reactants in a Chemical Reaction
Consider the reaction: 2H<em>2(g)+O</em>2(g)→2H2O(g)
Figure 4: The synthesis of water from its elements. The limiting reagent, oxygen, is completely used up in the reaction. Some hydrogen, the excess reagent, remains after the reaction is complete.
Significance of Limiting Reactant
The reactant that runs out first (the limiting reactant) dictates how much product will be produced.
Example: C<em>3H</em>8(g)+5O<em>2(g)→3CO</em>2(g)+4H2O(g)
We need 1 mol of C<em>3H</em>8 for every 5 mol of O2.
If we only had 4 mol of O<em>2, then O</em>2isthelimitingreactant</p></li></ul></li></ul><h4id="69748be4−82d7−4d22−8ccc−4b2feade60fb"data−toc−id="69748be4−82d7−4d22−8ccc−4b2feade60fb"collapsed="false"seolevelmigrated="true">SampleProblem1</h4><ul><li><p>Apieceofmagnesiummetalreactswithhydrochloricacidandcompletelydisappears:<br>Mg(s) + 2 HCl(aq) \rightarrow H2(g) + MgCl2(aq)
a) Identify the limiting reactant.
b) Identify the excess reactant.
c) What mass of hydrogen gas will be produced from the reaction of 25.0 g of magnesium? (2.08 g)
7.4 - Calculations Involving Limiting Reagents
To determine which reactant is the limiting reagent:
Find the moles of each reactant
Divide each by their coefficient from the balanced equation
The lower of the two is the limiting reagent, the other is in excess
Sample Problem 1 - Problems Involving Amounts
Determine the amount of titanium metal produced when 2.8 mol of titanium (IV) chloride reacts with 5.4 mol of magnesium.
Step 1 - Write a balanced equation listing given value(s) and required value(s)
Step 2 - To determine the limiting reagent, first use the amount of one reactant to find the stoichiometric amount of the other
Step 3 - Use the amount of limiting reagent to find the amount of required substance
Sample Problem 2 & 3
Chloroform, CHCl_3,reactswithchlorinetoformcarbontetrachlorideandhydrogenchloride.Inanexperiment25gofchloroformand25gofchlorineweremixed.<br>a)Whichisthelimitingreactant?<br>b)Whatisthemaximumyieldofcarbontetrachloride?<br>c)Determinethemassofexcessremaining.</p></li></ul><h4id="138955b8−d8b0−41e9−9ded−10faa0e2ad9a"data−toc−id="138955b8−d8b0−41e9−9ded−10faa0e2ad9a"collapsed="false"seolevelmigrated="true">SampleProblem4</h4><ul><li><p>6.73gofmagnesiumreactswith8.15gofoxygeninacombustionreaction.<br>a)Determinethelimitingreagent.<br>b)Calculatethemaximummassoftheproductformed.<br>c)Calculatetheamountofexcessreagentremaining.</p></li></ul><h4id="a3dcc3f5−8c06−475a−abc3−24c5e1922c4d"data−toc−id="a3dcc3f5−8c06−475a−abc3−24c5e1922c4d"collapsed="false"seolevelmigrated="true">SampleProblem5−AmountsInvolvedintheSynthesisofWater</h4><ul><li><p>2 H2(g) + O2(g) \rightarrow 2 H2O(g) with 8.15 g of oxygen in a combustion reaction.
2Mg(s)+O2(g)→2MgO(s)
a) Determine the limiting reagent.
b) Calculate the maximum mass of the product formed.
c) Calculate the amount of excess reagent remaining.