Geometry Honors Study Guide: Transformations, Congruence, and Triangle Proofs

Fundamental Definitions and Concepts of Geometric Transformations

  • Transformation: The change in position, size, or shape of a geometric figure.
  • Pre-Image: The original figure before a transformation is applied.
  • Image: The new figure resulting from a transformation.
  • Mapping: A transformation maps the pre-image to the image.
  • Notation:
    • Arrow notation (→\rightarrow) is used to describe a transformation (e.g., △ABC→△A′B′C′\triangle ABC \rightarrow \triangle A'B'C').
    • Primes (′') are used to label the image figure (e.g., A′A' is the image of AA).
  • Three Basic Rigid Transformations:
    • Reflection (or Flip): A transformation across a line, called the line of reflection. Each point on the pre-image and its corresponding image point are the exact same distance from the line of reflection.
    • Rotation (or Turn): A transformation about a point PP, called the center of rotation. Each point on the pre-image and its corresponding image point are the exact same distance from the center of rotation PP.
    • Translation (or Slide/Shift): A transformation in which all the points of a figure move the exact same distance in the exact same direction.
  • Application to Sample Figures: Transformations can be performed on target figures or letters such as EE, KK, or PP.

Transformation Coordinate Rules and Examples

  • Identifying and Describing Transformations:
    • Example 1A: Rotation of 90∘90^\circ counterclockwise.
    • Example 1B: Reflection over the xx-axis.
    • Example 1C: Translation right 22 units, down 33 units.
  • Applying Coordinate Rules (MM):
    • Rule A: M:(x,y)→(x−4,y+1)M: (x, y) \rightarrow (x - 4, y + 1)
    • Description: Translation left 44 units, up 11 unit.
    • Vertices Application: Pre-image polygon with vertices P(1,3)P(1, 3), Q(1,1)Q(1, 1), and R(4,1)R(4, 1) maps to image vertices P′(−3,4)P'(-3, 4), Q′(−3,2)Q'(-3, 2), and R′(0,2)R'(0, 2).
    • Rule B: M:(x,y)→(x,−y)M: (x, y) \rightarrow (x, -y)
    • Description: Reflection over the xx-axis.
    • Vertices Application: Pre-image polygon with vertices A(1,2)A(1, 2), B(4,2)B(4, 2), and C(3,1)C(3, 1) maps to image vertices A′(1,−2)A'(1, -2), B′(4,−2)B'(4, -2), and C′(3,−1)C'(3, -1).
    • Rule C: M:(x,y)→(y,x)M: (x, y) \rightarrow (y, x)
    • Description: Rotation 90∘90^\circ clockwise about the origin.
    • Vertices Application: Pre-image polygon with vertices R(−3,0)R(-3, 0), E(−3,3)E(-3, 3), C(−1,3)C(-1, 3), and T(−1,0)T(-1, 0) maps to image vertices R′(0,3)R'(0, 3), E′(3,3)E'(3, 3), C′(3,1)C'(3, 1), and T′(0,1)T'(0, 1).
  • Board Practice Transformations:
    • 1. Translation right 66 units, down 22 units.
    • 2. Reflection over the yy-axis.
    • 3. Rotation 90∘90^\circ clockwise.
    • 4. Rotation 180∘180^\circ clockwise or counterclockwise about the origin.
    • 5. Reflection.
    • 6. Reflection over the yy-axis applied to coordinates B(−5,−1)B(-5, -1), A(−0.6,−2)A(-0.6, -2), and C(3,−4)C(3, -4) resulting in B′(5,−1)B'(5, -1), A′(0.6,−2)A'(0.6, -2), and C′(−3,−4)C'(-3, -4).

Congruence and Rigid Motion Transformations

  • Connection Between Transformations and Congruence: Reflections, rotations, and translations result in an image that is congruent to the pre-image.
  • Definition of Congruent Figures: Figures are congruent when all pairs of corresponding sides and all pairs of corresponding angles are congruent.
  • Listing Corresponding Congruent Parts:
    • Given Statement: △DOG≅△CAT\triangle DOG \cong \triangle CAT
    • Corresponding Angles:
    • ∠D≅∠C\angle D \cong \angle C
    • ∠O≅∠A\angle O \cong \angle A
    • ∠G≅∠T\angle G \cong \angle T
    • Corresponding Sides:
    • DO≅CADO \cong CA
    • OG≅ATOG \cong AT
    • DG≅CTDG \cong CT

Geometric Postulates, Properties, and Proof Rules

  • Reflexive Property Postulate: Any segment or angle is congruent to itself.
    • Examples: KT≅KTKT \cong KT, ∠Q≅∠Q\angle Q \cong \angle Q, RC≅RCRC \cong RC, MT≅MTMT \cong MT
  • Specific Triangle Congruence & Property Examples:
    • △ERC≅△TCR\triangle ERC \cong \triangle TCR because RC≅RCRC \cong RC by the Reflexive Property.
    • Given EE is the midpoint of TPTP, △SPE≅△RTE\triangle SPE \cong \triangle RTE.
    • △BOW≅△YTI\triangle BOW \cong \triangle YTI where ∠1≅∠2\angle 1 \cong \angle 2 because vertical angles are congruent.
  • Shortcuts and Direct Reasoning Rules in Proofs:
    • Straight Angles: Diagrams do not require assuming straight angles; direct statements can be made such as "straight angles are congruent" or "If the sum of 22 angles is a straight angle, then they are supplementary."
    • Complementary Angles:
    • Angles complementary to the same angle are congruent.
    • Angles complementary to congruent angles are congruent.
    • Supplementary Angles:
    • Angles supplementary to the same angle are congruent.
    • Angles supplementary to congruent angles are congruent.
    • Perpendicular Lines and Right Angles:
    • Perpendicular segments form right angles.
    • All right angles are congruent.
    • All straight angles are congruent.
    • Midpoints and Bisectors:
    • A midpoint divides a segment into 22 congruent segments.
    • A segment bisector divides a segment into 22 congruent segments.
    • Angle Bisectors and Trisection:
    • An angle bisector divides an angle into 22 congruent angles.
    • An angle trisector divides an angle into 33 congruent angles.
    • Segment Trisection:
    • A segment trisector divides a segment into 33 congruent segments.
  • Triangle Correspondence Notation: Line up corresponding vertices when writing triangle congruence statements (e.g., △HMT≅△AMT\triangle HMT \cong \triangle AMT).

Triangle Congruence Shortcuts

  • Proving Triangles Congruent: It is not necessary to show that all three pairs of sides and all three pairs of angles are congruent to prove two triangles are congruent. Four valid shortcuts exist:
    • SSSSSS (Side-Side-Side): The three sides of one triangle must be congruent to the three sides of the other triangle.
    • SASSAS (Side-Angle-Side): Two sides and the included angle of one triangle must be congruent to two sides and the included angle of the other triangle.
    • ASAASA (Angle-Side-Angle): Two angles and the included side of one triangle must be congruent to two angles and the included side of the other triangle.
    • AASAAS (Angle-Angle-Side): Two angles and the nonincluded side of one triangle must be congruent to two angles and the nonincluded side of the other triangle.
  • Invalid Methods:
    • AAAAAA (Angle-Angle-Angle) cannot be used in proofs.
    • SSASSA (Side-Side-Angle) cannot be used in proofs.

Step-by-Step Formal Geometric Proofs

  • Proof 1:

    • Given: IDID bisects ∠WIL\angle WIL, ID⊥WLID \perp WL
    • Prove: △WID≅△LID\triangle WID \cong \triangle LID
    • Proof Steps:
    1. IDID bisects ∠WIL\angle WIL, ID⊥WLID \perp WL | Given
    2. ∠WID≅∠LID\angle WID \cong \angle LID | Bisector divides an angle into 22 congruent angles
    3. ∠WDI\angle WDI and ∠LDI\angle LDI are right angles | Perpendicular segments form right angles
    4. ∠WDI≅∠LDI\angle WDI \cong \angle LDI | Right angles are congruent
    5. ID≅IDID \cong ID | Reflexive Property
    6. △WID≅△LID\triangle WID \cong \triangle LID | ASAASA
  • Proof 2:

    • Given: AD=AEAD = AE, AF=AGAF = AG, CD=BECD = BE, FGFG bisects ABAB and ACAC
    • Prove: △ACE≅△ABD\triangle ACE \cong \triangle ABD
    • Proof Steps:
    1. AD=AEAD = AE, AF=AGAF = AG, CD=BECD = BE, FGFG bisects ABAB and ACAC | Given
    2. CE=DBCE = DB | Addition
    3. AC=ABAC = AB | Addition / Multiplication
    4. △ACE≅△ABD\triangle ACE \cong \triangle ABD | SSSSSS
  • Proof 3:

    • Given: GM=OHGM = OH, ∠G\angle G is complementary to ∠HEM\angle HEM, ∠O\angle O is complementary to ∠HEM\angle HEM, EG=EOEG = EO
    • Prove: △EGH≅△EOM\triangle EGH \cong \triangle EOM
    • Proof Steps:
    1. GM=OHGM = OH, ∠G\angle G comp. to ∠HEM\angle HEM, ∠O\angle O comp. to ∠HEM\angle HEM, EG=EOEG = EO | Given
    2. ∠G≅∠O\angle G \cong \angle O | Angles complementary to the same angle are congruent
    3. GH=OMGH = OM | Subtraction
    4. △EGH≅△EOM\triangle EGH \cong \triangle EOM | SASSAS
  • Proof 4:

    • Given: BB is the midpoint of AEAE, AEAE bisects CDCD
    • Prove: △ACB≅△EDB\triangle ACB \cong \triangle EDB
    • Proof Steps:
    1. BB is the midpoint of AEAE, AEAE bisects CDCD | Given
    2. AB≅BEAB \cong BE | Midpoint divides a segment into 22 congruent segments
    3. CB≅BDCB \cong BD | Bisector divides a segment into 22 congruent segments
    4. ∠CBA≅∠EBD\angle CBA \cong \angle EBD | Vertical angles are congruent
    5. △ACB≅△EDB\triangle ACB \cong \triangle EDB | SASSAS