Functions and Graphs

Objectives and Textbook Overview

  • Reference Text: Introductory Mathematical Analysis for Business, Economics, and the Life and Social Sciences (Thirteenth Edition) by Haeussler, Paul, and Wood.

  • Chapter Subject: Functions and Graphs.

  • Chapter Objectives:

    • To understand what functions and domains are.

    • To introduce different types of functions.

    • To become familiar with the shapes of the graphs of six basic functions.

Fundamentals of Functions, Domain, and Range

  • Definition of a Function: A function assigns each input number to exactly one output number.

  • Definition of Domain: The set of all input numbers to which the function applies is called the domain of the function.

  • Definition of Range: The set of all output numbers produced by evaluating the function across its domain is called the range.

Methods for Finding the Domain of Algebraic Functions

  • General Rule for Finding Domain:

    • To find the domain of a function, first identify the excluded values (values for which the expression is undefined, such as division by zero).

    • The domain is the set of real numbers R\mathbb{R} from which all excluded values are removed.

  • Example 1: Domain and Evaluation of a Polynomial Function

    • Given function:     g(x)=3x2−x+5g(x) = 3x^2 - x + 5

    • Finding Domain: Any real number can be used for xx, so the domain of gg is all real numbers:     D(g)=(−∞,+∞)D(g) = (-\infty, +\infty)

    • Evaluation Exercises:

    • Find g(z)g(z)       g(z)=3z2−z+5g(z) = 3z^2 - z + 5

    • Find g(r2)g(r^2)       g(r2)=3(r2)2−r2+5g(r^2) = 3(r^2)^2 - r^2 + 5       g(r2)=3r4−r2+5g(r^2) = 3r^4 - r^2 + 5

    • Find g(x+h)g(x + h)       g(x+h)=3(x+h)2−(x+h)+5g(x + h) = 3(x + h)^2 - (x + h) + 5       g(x+h)=3(x2+2xh+h2)−x−h+5g(x + h) = 3(x^2 + 2xh + h^2) - x - h + 5       g(x+h)=3x2+6xh+3h2−x−h+5g(x + h) = 3x^2 + 6xh + 3h^2 - x - h + 5

  • Example 2: Domain of a Rational Function

    • Given function:     f(x)=2x3x−4f(x) = \frac{2x}{3x - 4}

    • Finding Excluded Values: Set the denominator equal to zero:     3x−4=03x - 4 = 0     3x=43x = 4     x=43x = \frac{4}{3}

    • Domain Solution:     D(f)=R∖{43}=(−∞,43)∪(43,+∞)D(f) = \mathbb{R} \setminus \left\{\frac{4}{3}\right\} = \left(-\infty, \frac{4}{3}\right) \cup \left(\frac{4}{3}, +\infty\right)

Determining Domain and Range from Graphs

  • Procedure for Graphical Identification:

    • To find the domain of a function from its graph, look for all inputs on the xx-axis that correspond to points on the graph.

    • To find the range of a function from its graph, look for all outputs on the yy-axis that correspond to points on the graph.

  • Example 1: Continuous Curve with Closed Endpoints   !Graph of y = f(x) showing domain [-2, 1] and range [0, 3]

    • Graph features: Starts at solid endpoint (−2,0)(-2, 0), curves up through (0,2)(0, 2), and ends at solid endpoint (1,3)(1, 3).

    • Domain:     {x∣−2≤x≤1}\{x \mid -2 \le x \le 1\}     [−2,1][-2, 1]

    • Range:     {y∣0≤y≤3}\{y \mid 0 \le y \le 3\}     [0,3][0, 3]

  • Example 2: Line Segment with Open and Closed Endpoints   ![Graph of y = f(x) showing domain (-2, 1] and range -1, 2)

    • Graph features: Open endpoint at (−2,2)(-2, 2), passing through (0,0)(0, 0), ending at solid endpoint (1,−1)(1, -1).

    • Domain:     {x∣−2<x≤1}\{x \mid -2 < x \le 1\}     (−2,1](-2, 1]

    • Range:     {y∣−1≤y<2}\{y \mid -1 \le y < 2\}     [−1,2)[-1, 2)

Special Types of Functions

  • Constant Function:

    • Definition: A function of the form h(x)=ch(x) = c, where cc is a constant real number, is a constant function.

    • Domain: The domain of hh is all real numbers (−∞,+∞)(-\infty, +\infty).

    • Example: Let h(x)=2h(x) = 2     h(10)=2h(10) = 2     h(−387)=2h(-387) = 2     h(x+3)=2h(x + 3) = 2

  • Rational Functions:

    • Definition: A function f(x)f(x) is a rational function if both the numerator and denominator are polynomial functions.

    • Rational Example A:     f(x)=x2−6xx+5f(x) = \frac{x^2 - 6x}{x + 5}     This is rational because both x2−6xx^2 - 6x and x+5x + 5 are polynomials.

    • Rational Example B:     g(x)=2x+3g(x) = 2x + 3     This is rational because it can be written as a fraction over 11:     2x+3=2x+312x + 3 = \frac{2x + 3}{1}

  • Absolute-Value Function:

    • Definition: The absolute-value function f(x)=∣x∣f(x) = |x| is defined piece-wise as:     ∣x∣={xif x≥0−xif x<0|x| = \begin{cases} x & \text{if } x \ge 0 \\ -x & \text{if } x < 0 \end{cases}

Inverse Functions

  • Definition of Inverse Functions:

    • Let ff and gg be two functions such that:     f(g(x))=xfor every x in the domain of gf(g(x)) = x \quad \text{for every } x \text{ in the domain of } g     g(f(x))=xfor every x in the domain of fg(f(x)) = x \quad \text{for every } x \text{ in the domain of } f

    • The function gg is the inverse of the function ff and is denoted by f−1f^{-1} (read "ff-inverse").

    • Identity equations:     f(f−1(x))=xf(f^{-1}(x)) = x     f−1(f(x))=xf^{-1}(f(x)) = x

    • Domain-Range Relationship: The domain of ff is equal to the range of f−1f^{-1}, and the range of ff is equal to the domain of f−1f^{-1}.

  • Example: Verifying Inverse Functions

    • Show that ff and gg are inverse functions:     f(x)=4x−7f(x) = 4x - 7     g(x)=x+74g(x) = \frac{x + 7}{4}

    • Evaluation of f(g(x))f(g(x)):     f(g(x))=f(x+74)f(g(x)) = f\left(\frac{x + 7}{4}\right)     f(g(x))=4(x+74)−7f(g(x)) = 4\left(\frac{x + 7}{4}\right) - 7     f(g(x))=x+7−7f(g(x)) = x + 7 - 7     f(g(x))=xf(g(x)) = x

    • Evaluation of g(f(x))g(f(x)):     g(f(x))=g(4x−7)g(f(x)) = g(4x - 7)     g(f(x))=(4x−7)+74g(f(x)) = \frac{(4x - 7) + 7}{4}     g(f(x))=4x4g(f(x)) = \frac{4x}{4}     g(f(x))=xg(f(x)) = x

    • Conclusion: Since f(g(x))=g(f(x))=xf(g(x)) = g(f(x)) = x, ff and gg are inverse functions.

Graphs and Intercepts in Rectangular Coordinates

  • Rectangular Coordinate System: Provides a geometric framework to graph equations in two variables.

  • Definition and Rules of Intercepts:

    • To find xx-intercepts, look for points where the graph crosses or intersects the xx-axis (set y=0y = 0).

    • To find yy-intercepts, look for points where the graph crosses or intersects the yy-axis (set x=0x = 0).

    • Intercept limit: A function can have more than one xx-intercept, but at most one yy-intercept.

  • Example 1: Quadratic Function Intercepts

    Graph of y = x^2 + 2x - 3 showing two x-intercepts and one y-intercept
    • Equation: y=x2+2x−3y = x^2 + 2x - 3

    • xx-intercepts: Points where curve crosses xx-axis.

    • yy-intercept: Point where curve crosses yy-axis.

  • Example 2: Reading Intercepts from Graph

    • For graph of f(x)f(x), the xx-intercepts are (−3,0)(-3, 0), (−1,0)(-1, 0), and (2,0)(2, 0).

    • The yy-intercept is (0,−6)(0, -6).

  • Example 3: Intercepts and Graph of a Linear Function

    Graph and table of values for y = 2x + 3
    • Given equation: y=2x+3y = 2x + 3

    • Finding xx-intercept (set y=0y = 0):     0=2x+30 = 2x + 3     2x=−32x = -3     x=−32x = -\frac{3}{2}     x-intercept: (−32,0)x\text{-intercept: } \left(-\frac{3}{2}, 0\right)

    • Finding yy-intercept (set x=0x = 0):     y=2(0)+3y = 2(0) + 3     y=3y = 3     y-intercept: (0,3)y\text{-intercept: } (0, 3)

    • Table of Values for y=2x+3y = 2x + 3:

    • x=0  ⟹  y=3x = 0 \implies y = 3

    • x=−32  ⟹  y=0x = -\frac{3}{2} \implies y = 0

    • x=12  ⟹  y=4x = \frac{1}{2} \implies y = 4

    • x=−12  ⟹  y=2x = -\frac{1}{2} \implies y = 2

    • x=1  ⟹  y=5x = 1 \implies y = 5

    • x=−1  ⟹  y=1x = -1 \implies y = 1

    • x=2  ⟹  y=7x = 2 \implies y = 7

    • x=−2  ⟹  y=−1x = -2 \implies y = -1

  • Example 4: Vertical Line Graph

    Graph and table of values for vertical line x = 3
    • Equation: x=3x = 3

    • xx-intercept: (3,0)(3, 0)

    • yy-intercept: There is no yy-intercept because xx cannot be 00

    • Table of Values:

    • (3,0)(3, 0)

    • (3,3)(3, 3)

    • (3,−2)(3, -2)

Algebraic and Graphical Symmetry: Even and Odd Functions

  • Algebraic Definitions:

    • Even Function: Function ff is even if f(−x)=f(x)f(-x) = f(x) for all xx in the domain of ff.

    • Odd Function: Function ff is odd if f(−x)=−f(x)f(-x) = -f(x) for all xx in the domain of ff.

  • Example: Determining Even/Odd Symmetry

    • Given function: h(x)=x5+1h(x) = x^5 + 1

    • Testing Evenness:     h(−x)=(−x)5+1h(-x) = (-x)^5 + 1     h(−x)=−x5+1h(-x) = -x^5 + 1     Since h(−x)≠h(x)h(-x) \neq h(x), the function is not even.

    • Testing Oddness:     −h(x)=−(x5+1)-h(x) = -(x^5 + 1)     −h(x)=−x5−1-h(x) = -x^5 - 1     Since h(−x)≠−h(x)h(-x) \neq -h(x), the function is not odd.

    • Conclusion: The function h(x)=x5+1h(x) = x^5 + 1 is neither even nor odd.

  • Graphical Symmetry Principles:

    • The graph of an even function (f(−x)=f(x)f(-x) = f(x)) is symmetric with respect to the yy-axis.

    • The graph of an odd function (f(−x)=−f(x)f(-x) = -f(x)) is symmetric with respect to the origin.