FYS236 Electrodynamics Spring 2025 Lecture Notes Summary

Coulomb’s Law and Electric Field

  • Coulomb's Law: F=14πϵ0qQr2r^F = \frac{1}{4\pi\epsilon_0} \frac{qQ}{r^2} \hat{r}

  • Electric Field: E(r)=14πϵ<em>0</em>i=1nq<em>ir</em>i2r^iE(r) = \frac{1}{4\pi\epsilon<em>0} \sum</em>{i=1}^{n} \frac{q<em>i}{r</em>i^2} \hat{r}_i

  • Electric Field and Force: F=QEF = QE

  • Permittivity of free space: ϵ0=8.854×1012 F/m\epsilon_0 = 8.854 \times 10^{-12} \text{ F/m}

Continuous Charge Distributions

  • Electric field for continuous charge distributions:

    • Line charge: E(r)=14πϵ0λ(r)r2r^dlE(r) = \frac{1}{4\pi\epsilon_0} \int \frac{\lambda(r')}{r^2} \hat{r} dl'

    • Surface charge: E(r)=14πϵ0σ(r)r2r^daE(r) = \frac{1}{4\pi\epsilon_0} \int \frac{\sigma(r')}{r^2} \hat{r} da'

    • Volume charge: E(r)=14πϵ0ρ(r)r2r^dτE(r) = \frac{1}{4\pi\epsilon_0} \int \frac{\rho(r')}{r^2} \hat{r} d\tau'

Gauss’s Law

  • Integral Form: <em>SEda=Q</em>encϵ0\oint<em>S E \cdot da = \frac{Q</em>{enc}}{\epsilon_0}

  • Differential Form: E=ρϵ0\nabla \cdot E = \frac{\rho}{\epsilon_0}

  • Electric flux: Φ<em>E=</em>SEda\Phi<em>E = \int</em>S E \cdot da

Curl of E and Electric Potential V

  • Curl of E for a point charge: ×E=0\nabla \times E = 0

  • Electric Potential: V(r)=OrEdlV(r) = -\int_O^r E \cdot dl

  • Electric Field as Gradient of Potential: E=VE = -\nabla V

  • Potential Difference: V(b)V(a)=abEdlV(b) - V(a) = -\int_a^b E \cdot dl

Electric Potential, Boundary Conditions, Energy

  • Poisson's Equation: 2V=ρϵ0\nabla^2 V = -\frac{\rho}{\epsilon_0}

  • Laplace's Equation (in charge-free regions): 2V=0\nabla^2 V = 0

  • Boundary Condition (tangential): Eabove<em>=Ebelow</em>E^{\text{above}}<em>{\parallel} = E^{\text{below}}</em>{\parallel}

  • Boundary Condition (normal): Eabove<em>Ebelow</em>=σϵ0n^E^{\text{above}}<em>{\perp} - E^{\text{below}}</em>{\perp} = \frac{\sigma}{\epsilon_0} \hat{n}

  • Energy density in electrostatic fields: W=ϵ<em>02</em>all spaceE2dτW = \frac{\epsilon<em>0}{2} \int</em>{\text{all space}} E^2 d\tau

Conductors

  • Electrostatic properties:

    • E = 0 inside a conductor.

    • ρ = 0 inside a conductor.

    • Conductor is an equipotential body.

    • E is perpendicular to the surface.

  • Capacitance: C=QVC = \frac{Q}{V}

Dipoles, Polarization, Electric Fields in Matter

  • Dipole moment: p=qdp = qd

  • Potential of a dipole: V(r)=pr^4πϵ0r2V(r) = \frac{p \cdot \hat{r}}{4 \pi \epsilon_0 r^2}

  • The field of a polarized object:

    • Bound surface charge: σb=Pn^\sigma_b = P \cdot \hat{n}

    • Bound volume charge: ρb=P\rho_b = -\nabla \cdot P

  • Gauss’s law with dielectric: D=ρ<em>f\nabla \cdot D = \rho<em>f with D=ϵ</em>0E+PD = \epsilon</em>0 E + P

  • Linear dielectric materials: P=ϵ<em>0χ</em>eEP = \epsilon<em>0 \chi</em>e E and D=ϵED = \epsilon E

Magnetostatics

  • Lorentz law: F=q(E+v×B)F = q(E + v \times B)

Biot-Savart Law and Maxwell Equations

  • Biot-Savart Law: B(r)=μ<em>04πIdl×r^r2=μ</em>04πJ(r)×r^r2dτB(r) = \frac{\mu<em>0}{4 \pi} \int \frac{I dl' \times \hat{r}}{r^2} = \frac{\mu</em>0}{4 \pi} \int \frac{J(r') \times \hat{r}}{r^2} d\tau'

Ampere’s Law

  • Ampère’s Law (integral form): Bdl=μ<em>0I</em>enc\oint B \cdot dl = \mu<em>0 I</em>{enc}

  • Magnetic Vector Potential: B=×AB = \nabla \times A

  • Vector potential of a current loop: A(r)=μ04πm×r^r2A(r) = \frac{\mu_0}{4 \pi} \frac{m \times \hat{r}}{r^2}

Magnetic Fields in Matter

  • The auxiliary field H: H=1μ0BMH = \frac{1}{\mu_0} B - M

  • Magnetic susceptibility and permeability:

    • M=χmH\vec{M} = \chi_m \vec{H}

Electromotive Force

  • Ohm’s law: J=σEJ = \sigma E

  • Resistance: R=VIR = \frac{V}{I}

  • Electromotive force: E=fdlE = \oint f \cdot dl

  • Faraday's Law: E=dΦBdtE = - \frac{d \Phi_B}{dt}

Inductance, Displacement Current, Maxwell Equations

  • Inductance: L=ΦIL = \frac{\Phi}{I}
    Maxwell’s repair of Ampère’s Law:
    *Ampère-Maxwell equation:
    ×B=μ<em>0J+μ</em>0ϵ<em>0Et\nabla \times B = \mu<em>0 J + \mu</em>0 \epsilon<em>0 \frac{\partial E}{\partial t} *Displacement current: ϵ</em>0Et\epsilon</em>0 \frac{\partial E}{\partial t}