Integration Methods to Know for AP Calculus AB/BC (AP)

What You Need to Know

Integration on AP Calc AB/BC is mostly about recognizing which technique fits the integrand and executing cleanly. You’re expected to:

  • Find antiderivatives (indefinite integrals) and evaluate definite integrals.
  • Use the Fundamental Theorem of Calculus (FTC) to connect integrals and derivatives.
  • Choose among a small set of core integration methods:
    • Basic antiderivative rules (power/exponential/trig)
    • uu-substitution (reverse chain rule)
    • Integration by parts (BC emphasis; AB may appear conceptually)
    • Partial fractions (BC)
    • Trig identities / trig integrals (BC)
    • Improper integrals (BC)
    • Numerical integration: Trapezoidal Rule (AB/BC) and Simpson’s Rule (BC)

Core idea: Integration is pattern matching + algebra. If you can rewrite the integrand into a standard form, you’re 90% done.

Big exam reminder: Always check your limits of integration if you substitute, and always add +C+C for indefinite integrals.


Step-by-Step Breakdown

1) Basic Antiderivative Rules + FTC

Use when the integrand is already a standard derivative pattern.

  1. Rewrite the integrand (simplify, split sums).
  2. Apply known antiderivatives term-by-term.
  3. For definite integrals, evaluate with FTC:
    • If F(x)=f(x)F'(x)=f(x), then abf(x)dx=F(b)F(a)\int_a^b f(x)\,dx = F(b)-F(a).

Mini-example:

  • (3x24cosx)dx=x34sinx+C\int (3x^2 - 4\cos x)\,dx = x^3 - 4\sin x + C.
  • 0πsinxdx=[cosx]0π=(cosπ)(cos0)=2\int_0^{\pi} \sin x\,dx = [-\cos x]_0^{\pi} = (-\cos \pi)-(-\cos 0)=2.
2) uu-Substitution (Reverse Chain Rule)

Use when you see a composite function and (up to a constant) its derivative.

  1. Choose u=“inside”u = \text{“inside”}.
  2. Compute du=u(x)dxdu = u'(x)\,dx.
  3. Rewrite the integral entirely in uu and dudu.
  4. Integrate in uu.
  5. Convert back to xx (unless you changed definite bounds).
  6. For definite integrals: either convert bounds to uu-bounds _or_ switch back to xx before evaluating.

Mini-example:

  • 2x(x2+5)7dx\int 2x\,(x^2+5)^7\,dx
    • Let u=x2+5u=x^2+5, then du=2xdxdu=2x\,dx.
    • Integral becomes u7du=u88+C=(x2+5)88+C\int u^7\,du = \frac{u^8}{8}+C = \frac{(x^2+5)^8}{8}+C.

Decision point: If you can spot an “inside” function whose derivative is present (or can be created with a constant factor), use uu-sub.

3) Integration by Parts (IBP) (Mostly BC)

Use for products like xexx e^x, xsinxx\sin x, lnx\ln x, inverse trig, etc.

Key formula:

udv=uvvdu\int u\,dv = uv - \int v\,du

Steps:

  1. Choose uu (differentiate it) and dvdv (integrate it).
  2. Compute dudu and vv.
  3. Plug into udv=uvvdu\int u\,dv = uv - \int v\,du.
  4. Repeat if the remaining integral still needs IBP.

Mini-example:

  • xexdx\int x e^x\,dx
    • Choose u=xu=x, dv=exdxdv=e^x\,dx.
    • Then du=dxdu=dx, v=exv=e^x.
    • xexdx=xexexdx=xexex+C=ex(x1)+C\int x e^x\,dx = x e^x - \int e^x\,dx = x e^x - e^x + C = e^x(x-1)+C.

Decision point: If it’s a product and uu-sub doesn’t fit, think IBP.

4) Partial Fractions (BC)

Use for rational functions P(x)Q(x)\frac{P(x)}{Q(x)} where degP<degQ\deg P < \deg Q (after long division if needed).

  1. If degPdegQ\deg P \ge \deg Q: do polynomial long division first.
  2. Factor the denominator completely (over reals).
  3. Set up partial fraction form:
    • Distinct linear: Axa\frac{A}{x-a}
    • Repeated linear: Axa+B(xa)2+\frac{A}{x-a}+\frac{B}{(x-a)^2}+\cdots
    • Irreducible quadratic: Ax+Bx2+px+q\frac{Ax+B}{x^2+px+q}
  4. Solve for constants.
  5. Integrate term-by-term (often logs + arctan).

Mini-example:

  • 1x21dx=1(x1)(x+1)dx\int \frac{1}{x^2-1}\,dx = \int \frac{1}{(x-1)(x+1)}\,dx
    • 1(x1)(x+1)=Ax1+Bx+1\frac{1}{(x-1)(x+1)}=\frac{A}{x-1}+\frac{B}{x+1}
    • Solve: A=12,  B=12A=\frac{1}{2},\;B=-\frac{1}{2}
    • Integral: 12lnx112lnx+1+C=12lnx1x+1+C\frac{1}{2}\ln|x-1| - \frac{1}{2}\ln|x+1| + C = \frac{1}{2}\ln\left|\frac{x-1}{x+1}\right| + C
5) Trig Integrals / Trig Identity Rewrites (BC)

Use when powers of sinx\sin x and cosx\cos x appear.

  1. If one power is odd: save one factor, convert the rest using sin2x=1cos2x\sin^2 x = 1-\cos^2 x or cos2x=1sin2x\cos^2 x = 1-\sin^2 x, then uu-sub.
  2. If both are even: use half-angle identities:
    • sin2x=1cos(2x)2\sin^2 x = \frac{1-\cos(2x)}{2}
    • cos2x=1+cos(2x)2\cos^2 x = \frac{1+\cos(2x)}{2}

Mini-example (odd power):

  • sin3xcosxdx\int \sin^3 x\cos x\,dx
    • Rewrite sin3x=sin2xsinx=(1cos2x)sinx\sin^3 x = \sin^2 x\sin x=(1-\cos^2 x)\sin x
    • Let u=cosxu=\cos x, du=sinxdxdu=-\sin x\,dx
    • Integral becomes (1u2)du=(uu33)+C=cosx+cos3x3+C-\int (1-u^2)\,du = -\left(u-\frac{u^3}{3}\right)+C = -\cos x + \frac{\cos^3 x}{3}+C
6) Improper Integrals (BC)

Use when bounds are infinite or the integrand blows up.

  1. Replace the problematic bound or point with a variable.
  2. Evaluate as a limit.
  3. If the limit is finite: converges. If infinite/DNE: diverges.

Forms:

  • Infinite interval: af(x)dx=limbabf(x)dx\int_a^{\infty} f(x)\,dx = \lim_{b\to\infty}\int_a^b f(x)\,dx
  • Vertical asymptote at aa: abf(x)dx=limta+tbf(x)dx\int_a^b f(x)\,dx = \lim_{t\to a^+}\int_t^b f(x)\,dx (or split if asymptote is inside).

Mini-example:

  • 11x2dx=limb[1x]1b=limb(1b+1)=1\int_1^{\infty} \frac{1}{x^2}\,dx = \lim_{b\to\infty}\left[-\frac{1}{x}\right]_1^b = \lim_{b\to\infty}\left(-\frac{1}{b}+1\right)=1 (convergent)
7) Numerical Integration (Trapezoidal + Simpson)

Use when you have a table of values or no elementary antiderivative.

Trapezoidal Rule (AB/BC):

  1. Compute Δx=ban\Delta x = \frac{b-a}{n}.
  2. Apply:

Tn=Δx2[f(x0)+2f(x1)++2f(xn1)+f(xn)]T_n = \frac{\Delta x}{2}\left[f(x_0)+2f(x_1)+\cdots+2f(x_{n-1})+f(x_n)\right]

Simpson’s Rule (BC): requires even nn.

  1. Compute Δx=ban\Delta x = \frac{b-a}{n}.
  2. Apply:

Sn=Δx3[f(x0)+4f(x1)+2f(x2)+4f(x3)++2f(xn2)+4f(xn1)+f(xn)]S_n = \frac{\Delta x}{3}\left[f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+\cdots+2f(x_{n-2})+4f(x_{n-1})+f(x_n)\right]

Decision point: Simpson’s is usually more accurate (for smooth functions), but you must have even nn.


Key Formulas, Rules & Facts

Must-know antiderivatives (AB/BC)
Integrand f(x)f(x)Antiderivative f(x)dx\int f(x)\,dxNotes
xnx^nxn+1n+1+C\frac{x^{n+1}}{n+1}+Cn1n\neq -1
1x\frac{1}{x}lnx+C\ln|x|+Cabsolute value matters
exe^xex+Ce^x+Cself-derivative
axa^xaxlna+C\frac{a^x}{\ln a}+Ca>0,  a1a>0,\;a\neq 1
sinx\sin xcosx+C-\cos x+C
cosx\cos xsinx+C\sin x+C
sec2x\sec^2 xtanx+C\tan x+C
csc2x\csc^2 xcotx+C-\cot x+C
secxtanx\sec x\tan xsecx+C\sec x+C
cscxcotx\csc x\cot xcscx+C-\csc x+C
11+x2\frac{1}{1+x^2}arctanx+C\arctan x + C
11x2\frac{1}{\sqrt{1-x^2}}arcsinx+C\arcsin x + Cdomain matters
Fundamental Theorem of Calculus (FTC)
StatementUseNotes
If F(x)=f(x)F'(x)=f(x) then abf(x)dx=F(b)F(a)\int_a^b f(x)\,dx = F(b)-F(a)Evaluate definite integralscompute antiderivative then plug bounds
ddx(axf(t)dt)=f(x)\frac{d}{dx}\left(\int_a^x f(t)\,dt\right)=f(x)Differentiate an accumulation functionrequires continuity (AP typically assumes)
ddx(ag(x)f(t)dt)=f(g(x))g(x)\frac{d}{dx}\left(\int_a^{g(x)} f(t)\,dt\right)=f(g(x))\,g'(x)Chain rule + FTCvery common FRQ pattern
Quick “which method?” table
Pattern you seeMethodFast hint
f(g(x))g(x)f(g(x))g'(x)uu-subinside + derivative present
product like xexx e^x, xsinxx\sin x, lnx\ln xIBPpick uu to simplify when differentiated
rational function P(x)Q(x)\frac{P(x)}{Q(x)}long division then partial fractionsfactor Q(x)Q(x)
sinmxcosnx\sin^m x\cos^n xtrig rewriteodd/even strategy
infinity bound or vertical asymptoteimproper integralconvert to limit
table of values / messy integraltrapezoid / SimpsonSimpson needs even subintervals
Trig identities you actually use for integrals
  • sin2x+cos2x=1\sin^2 x + \cos^2 x = 1
  • 1+tan2x=sec2x1+\tan^2 x = \sec^2 x
  • sin2x=1cos(2x)2\sin^2 x = \frac{1-\cos(2x)}{2}
  • cos2x=1+cos(2x)2\cos^2 x = \frac{1+\cos(2x)}{2}

Examples & Applications

Example 1: Definite integral with uu-sub (change bounds)

Evaluate 012xx2+1dx\int_0^1 2x\sqrt{x^2+1}\,dx.

  • Let u=x2+1u=x^2+1, so du=2xdxdu=2x\,dx.
  • Change bounds: when x=0x=0, u=1u=1; when x=1x=1, u=2u=2.
  • Integral becomes 12u1/2du=[23u3/2]12=23(23/21)\int_1^2 u^{1/2}\,du = \left[\frac{2}{3}u^{3/2}\right]_1^2 = \frac{2}{3}\left(2^{3/2}-1\right).

Exam angle: This tests whether you remember to adjust bounds (or correctly switch back).

Example 2: IBP classic

Evaluate lnxdx\int \ln x\,dx.

  • Use IBP with u=lnxu=\ln x and dv=dxdv=dx.
  • Then du=1xdxdu=\frac{1}{x}dx, v=xv=x.
  • lnxdx=xlnxx1xdx=xlnx1dx=xlnxx+C\int \ln x\,dx = x\ln x - \int x\cdot \frac{1}{x}\,dx = x\ln x - \int 1\,dx = x\ln x - x + C.

Exam angle: A “no obvious antiderivative” problem that becomes easy with IBP.

Example 3: Partial fractions with logs

Evaluate 3x+5x2+2x3dx\int \frac{3x+5}{x^2+2x-3}\,dx.

  • Factor denominator: x2+2x3=(x+3)(x1)x^2+2x-3=(x+3)(x-1).
  • Set: 3x+5(x+3)(x1)=Ax+3+Bx1\frac{3x+5}{(x+3)(x-1)}=\frac{A}{x+3}+\frac{B}{x-1}.
  • Solve: 3x+5=A(x1)+B(x+3)=(A+B)x+(A+3B)3x+5=A(x-1)+B(x+3)=(A+B)x+(-A+3B).
    • System: A+B=3A+B=3 and A+3B=5-A+3B=5 gives B=2B=2, A=1A=1.
  • Integrate: (1x+3+2x1)dx=lnx+3+2lnx1+C\int \left(\frac{1}{x+3}+\frac{2}{x-1}\right)dx = \ln|x+3|+2\ln|x-1|+C.

Exam angle: Factoring + algebra accuracy.

Example 4: Simpson’s Rule from a table (BC)

Approximate 04f(x)dx\int_0^4 f(x)\,dx using Simpson’s Rule with n=4n=4 and values f(0)=1f(0)=1, f(1)=3f(1)=3, f(2)=2f(2)=2, f(3)=5f(3)=5, f(4)=4f(4)=4.

  • Δx=404=1\Delta x = \frac{4-0}{4}=1.
  • S4=13[f(0)+4f(1)+2f(2)+4f(3)+f(4)]S_4=\frac{1}{3}\left[f(0)+4f(1)+2f(2)+4f(3)+f(4)\right]
  • S4=13[1+4(3)+2(2)+4(5)+4]=13(1+12+4+20+4)=413S_4=\frac{1}{3}\left[1+4(3)+2(2)+4(5)+4\right]=\frac{1}{3}(1+12+4+20+4)=\frac{41}{3}.

Exam angle: Coefficient pattern 1,4,2,4,,2,4,11,4,2,4,\dots,2,4,1 and even nn.


Common Mistakes & Traps

  1. Forgetting +C+C (indefinite integrals)

    • Wrong: treating an antiderivative as a single function.
    • Fix: if there’s no bounds, add +C+C automatically.
  2. Bad uu choice or not converting everything to uu

    • Wrong: after substituting, leaving stray xx terms.
    • Fix: solve for xx in terms of uu if needed, or choose a cleaner uu.
  3. Not changing bounds (or double-changing) in definite uu-sub

    • Wrong: switching to uu but still plugging in x=a,bx=a,b.
    • Fix: choose ONE approach:
      • Convert bounds to uu and stay in uu, or
      • switch back to xx before evaluating.
  4. Sign errors with trig derivatives/antiderivatives

    • Common slips: sinxdx\int \sin x\,dx and csc2xdx\int \csc^2 x\,dx.
    • Fix: memorize the “negative” ones: sinxdx=cosx+C\int \sin x\,dx=-\cos x + C and csc2xdx=cotx+C\int \csc^2 x\,dx=-\cot x + C.
  5. IBP setup mistakes (mixing up uu and dvdv or missing parentheses)

    • Wrong: using udv=uv+vdu\int u\,dv = uv + \int v\,du (sign wrong) or dropping a factor.
    • Fix: write the formula every time: udv=uvvdu\int u\,dv = uv - \int v\,du.
  6. Partial fractions before long division

    • Wrong: trying PF when degPdegQ\deg P \ge \deg Q.
    • Fix: divide first, then decompose the proper fraction.
  7. Dropping absolute values in log answers

    • Wrong: 1x2dx=ln(x2)+C\int \frac{1}{x-2}\,dx = \ln(x-2)+C.
    • Fix: always write lnx2+C\ln|x-2|+C.
  8. Improper integrals: evaluating like normal definite integrals

    • Wrong: plugging in the “bad” endpoint directly.
    • Fix: replace with a limit and check convergence.

Memory Aids & Quick Tricks

Trick / mnemonicWhat it helps you rememberWhen to use it
Reverse chain ruleuu-sub is “undoing” chain ruleComposite functions with an “inside”
LIATE (or ILATE)Picking uu for IBP: Log, Inverse trig, Algebraic, Trig, ExponentialIBP choice for products
“Odd saves one”For sinmxcosnx\sin^m x\cos^n x: if one exponent is odd, save one factor and convert the restTrig power integrals
Simpson pattern: 1,4,2,4,,2,4,11,4,2,4,\dots,2,4,1Coefficients for Simpson’s RuleSimpson’s Rule computations
Logs need bars1xdx=lnx+C\int \frac{1}{x}\,dx = \ln|x|+CAny log-type antiderivative
Improper = limitIf something is infinite/undefined at an endpoint, you must use a limitImproper integrals

Quick Review Checklist

  • You can instantly recognize when to use basic rules vs uu-sub vs IBP vs partial fractions.
  • You know the must-have antiderivatives (power/log/exp/trig/inverse trig) and the signs.
  • For uu-sub, you rewrite **everything** in uu (and handle bounds correctly).
  • For IBP, you use udv=uvvdu\int u\,dv = uv - \int v\,du and choose uu using LIATE.
  • For rational functions, you long divide first if needed, then partial fractions.
  • For trig powers, you use odd/even strategies and half-angle when both even.
  • For improper integrals, you convert to a limit and decide converge/diverge.
  • For numerical methods, you can compute TnT_n and SnS_n and remember Simpson needs **even** nn.

You’ve got the tools—now it’s just recognition + clean algebra.